Example 5: Using the quadratic formula | Quadratic equations | Algebra I | Khan Academy
-
0:01 - 0:03We're asked to solve
the quadratic equation, -
0:03 - 0:08negative 3x squared plus
10x minus 3 is equal to 0. -
0:08 - 0:10And it's already written
in standard form. -
0:10 - 0:11And there's many
ways to solve this. -
0:11 - 0:14But in particular, all solve
it using the quadratic formula. -
0:14 - 0:15So let me just rewrite it.
-
0:15 - 0:19We have negative 3x squared
plus 10x minus 3 is equal to 0. -
0:19 - 0:21And actually, I'll
solve it twice -
0:21 - 0:23using the quadratic
formula to show you -
0:23 - 0:25that as long as we manipulated
this in the valid way, -
0:25 - 0:27the quadratic
formula will give us -
0:27 - 0:30the exact same roots or
the exact same solutions -
0:30 - 0:31to this equation.
-
0:31 - 0:34So in this form right over
here, what are our ABCs? -
0:34 - 0:37Let's just remind ourselves
what the quadratic formula even -
0:37 - 0:37is actually.
-
0:37 - 0:39That's a good place to start.
-
0:39 - 0:41The quadratic formula
tells us that if we -
0:41 - 0:43have a quadratic
equation in the form ax -
0:43 - 0:48squared plus bx plus c is equal
to 0, so in standard form, -
0:48 - 0:52then the roots of this are
x are equal to negative b -
0:52 - 0:56plus or minus the
square root of b -
0:56 - 1:02squared minus 4ac,
all of that over 2a. -
1:02 - 1:05And this is derived from
completing the square -
1:05 - 1:06in a general way.
-
1:06 - 1:10So it's no magic here, and I've
derived it in other videos. -
1:10 - 1:11But this is the
quadratic formula. -
1:11 - 1:13This is actually giving
you two solutions, -
1:13 - 1:15because you have the
positive square root here -
1:15 - 1:17and the negative square root.
-
1:17 - 1:20So let's apply it here in the
case where-- in this case, -
1:20 - 1:27a is equal to negative
3, b is equal to 10, -
1:27 - 1:31and c is equal to negative 3.
-
1:31 - 1:33So applying the quadratic
formula right here, -
1:33 - 1:37we get our solutions to be
x is equal to negative b. -
1:37 - 1:38b is 10.
-
1:38 - 1:43So negative b is negative 10
plus or minus the square root -
1:43 - 1:45of b squared.
-
1:45 - 1:45b is 10.
-
1:45 - 1:51So b squared is 100
minus 4 times a times c. -
1:51 - 1:54So minus 4 times negative
3 times negative 3. -
1:54 - 1:55Let me just write it down.
-
1:55 - 1:59Minus 4 times negative
3 times negative 3. -
1:59 - 2:01All of that's under
the radical sign. -
2:01 - 2:03And then all of that is over 2a.
-
2:03 - 2:06So 2 times a is negative 6.
-
2:06 - 2:08So this is going to be
equal to negative 10 -
2:08 - 2:15plus or minus the square root
of 100 minus-- negative 3 times -
2:15 - 2:16negative 3 is positive 9.
-
2:16 - 2:18Positive 9 times
4 is positive 36. -
2:18 - 2:20We have a minus sign out here.
-
2:20 - 2:22So minus 36.
-
2:22 - 2:24All of that over negative 6.
-
2:24 - 2:27This is equal to
100 minus 36 is 64. -
2:27 - 2:32So negative 10 plus or
minus the square root of 64. -
2:32 - 2:34All of that over negative 6.
-
2:34 - 2:36The principal square
root of 64 is 8. -
2:36 - 2:38But we're taking the positive
and negative square root. -
2:38 - 2:44So this is negative 10 plus
or minus 8 over negative 6. -
2:44 - 2:46So if we take the
positive version, -
2:46 - 2:48we say x could be
equal to-- negative 10 -
2:48 - 2:53plus 8 is negative
2 over negative 6. -
2:53 - 2:55So that was taking
the plus version. -
2:55 - 2:56That's this right over here.
-
2:56 - 2:59And negative 2 over
negative 6 is equal to 1/3. -
2:59 - 3:01If we take the
negative square root, -
3:01 - 3:05negative 10 minus 8-- So let's
take negative 10 minus 8. -
3:05 - 3:08That would be x is equal
to-- negative 10 minus 8 -
3:08 - 3:10is negative 18.
-
3:10 - 3:13And that's going to
be over negative 6. -
3:13 - 3:17Negative 18 divided by
negative 6 is positive 3. -
3:17 - 3:19So the two roots for
this quadratic equation -
3:19 - 3:22are positive 1/3 and positive 3.
-
3:22 - 3:25And I want to show you the
we'll get the same answer, -
3:25 - 3:26even if we manipulate this.
-
3:26 - 3:27Some people might
not like the fact -
3:27 - 3:30that our first coefficient
here is a negative 3. -
3:30 - 3:32Maybe they want a positive 3.
-
3:32 - 3:33So to get rid of
that negative 3, -
3:33 - 3:37they can multiply both sides of
this equation times negative 1. -
3:37 - 3:39And then if you did
that, you would get 3x -
3:39 - 3:45squared minus 10x plus 3 is
equal to 0 times negative 1, -
3:45 - 3:47which is still equal to 0.
-
3:47 - 3:52So in this case, a is equal to
3, b is equal to negative 10, -
3:52 - 3:54and c is equal to 3 again.
-
3:54 - 3:56And we could apply
the quadratic formula. -
3:56 - 4:01We get x is equal to
negative b. b is negative 10. -
4:01 - 4:02So negative negative
10 is positive -
4:02 - 4:0510, plus or minus
the square root -
4:05 - 4:08of b squared, which is
negative 10 squared, -
4:08 - 4:12which is 100, minus
4 times a times c. -
4:12 - 4:16a times c is 9 times 4 is 36.
-
4:16 - 4:18So minus 36.
-
4:18 - 4:20All of that over 2 times a.
-
4:20 - 4:22All of that over 6.
-
4:22 - 4:28So this is equal to 10 plus or
minus the square root of 64, -
4:28 - 4:31or really that's
just going to be 8. -
4:31 - 4:32All of that over 6.
-
4:32 - 4:36If we add 8 here, we get
10 plus 8 is 18 over 6. -
4:36 - 4:38We get x could be equal to 3.
-
4:38 - 4:41Or if we take the negative
square root or the negative 8 -
4:41 - 4:43here, 10 minus 8 is 2.
-
4:43 - 4:462 over 6 is 1/3.
-
4:46 - 4:50So once again, you get
the exact same solutions.
- Title:
- Example 5: Using the quadratic formula | Quadratic equations | Algebra I | Khan Academy
- Description:
-
Applying the Quadratic Formula
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Fran Ontanaya edited English subtitles for Example 5: Using the quadratic formula | Quadratic equations | Algebra I | Khan Academy | |
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Fran Ontanaya edited English subtitles for Example 5: Using the quadratic formula | Quadratic equations | Algebra I | Khan Academy |