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Example 5: Using the quadratic formula | Quadratic equations | Algebra I | Khan Academy

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    We're asked to solve
    the quadratic equation,
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    negative 3x squared plus
    10x minus 3 is equal to 0.
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    And it's already written
    in standard form.
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    And there's many
    ways to solve this.
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    But in particular, all solve
    it using the quadratic formula.
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    So let me just rewrite it.
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    We have negative 3x squared
    plus 10x minus 3 is equal to 0.
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    And actually, I'll
    solve it twice
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    using the quadratic
    formula to show you
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    that as long as we manipulated
    this in the valid way,
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    the quadratic
    formula will give us
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    the exact same roots or
    the exact same solutions
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    to this equation.
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    So in this form right over
    here, what are our ABCs?
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    Let's just remind ourselves
    what the quadratic formula even
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    is actually.
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    That's a good place to start.
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    The quadratic formula
    tells us that if we
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    have a quadratic
    equation in the form ax
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    squared plus bx plus c is equal
    to 0, so in standard form,
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    then the roots of this are
    x are equal to negative b
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    plus or minus the
    square root of b
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    squared minus 4ac,
    all of that over 2a.
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    And this is derived from
    completing the square
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    in a general way.
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    So it's no magic here, and I've
    derived it in other videos.
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    But this is the
    quadratic formula.
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    This is actually giving
    you two solutions,
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    because you have the
    positive square root here
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    and the negative square root.
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    So let's apply it here in the
    case where-- in this case,
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    a is equal to negative
    3, b is equal to 10,
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    and c is equal to negative 3.
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    So applying the quadratic
    formula right here,
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    we get our solutions to be
    x is equal to negative b.
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    b is 10.
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    So negative b is negative 10
    plus or minus the square root
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    of b squared.
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    b is 10.
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    So b squared is 100
    minus 4 times a times c.
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    So minus 4 times negative
    3 times negative 3.
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    Let me just write it down.
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    Minus 4 times negative
    3 times negative 3.
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    All of that's under
    the radical sign.
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    And then all of that is over 2a.
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    So 2 times a is negative 6.
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    So this is going to be
    equal to negative 10
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    plus or minus the square root
    of 100 minus-- negative 3 times
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    negative 3 is positive 9.
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    Positive 9 times
    4 is positive 36.
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    We have a minus sign out here.
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    So minus 36.
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    All of that over negative 6.
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    This is equal to
    100 minus 36 is 64.
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    So negative 10 plus or
    minus the square root of 64.
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    All of that over negative 6.
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    The principal square
    root of 64 is 8.
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    But we're taking the positive
    and negative square root.
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    So this is negative 10 plus
    or minus 8 over negative 6.
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    So if we take the
    positive version,
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    we say x could be
    equal to-- negative 10
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    plus 8 is negative
    2 over negative 6.
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    So that was taking
    the plus version.
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    That's this right over here.
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    And negative 2 over
    negative 6 is equal to 1/3.
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    If we take the
    negative square root,
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    negative 10 minus 8-- So let's
    take negative 10 minus 8.
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    That would be x is equal
    to-- negative 10 minus 8
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    is negative 18.
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    And that's going to
    be over negative 6.
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    Negative 18 divided by
    negative 6 is positive 3.
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    So the two roots for
    this quadratic equation
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    are positive 1/3 and positive 3.
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    And I want to show you the
    we'll get the same answer,
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    even if we manipulate this.
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    Some people might
    not like the fact
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    that our first coefficient
    here is a negative 3.
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    Maybe they want a positive 3.
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    So to get rid of
    that negative 3,
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    they can multiply both sides of
    this equation times negative 1.
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    And then if you did
    that, you would get 3x
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    squared minus 10x plus 3 is
    equal to 0 times negative 1,
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    which is still equal to 0.
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    So in this case, a is equal to
    3, b is equal to negative 10,
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    and c is equal to 3 again.
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    And we could apply
    the quadratic formula.
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    We get x is equal to
    negative b. b is negative 10.
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    So negative negative
    10 is positive
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    10, plus or minus
    the square root
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    of b squared, which is
    negative 10 squared,
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    which is 100, minus
    4 times a times c.
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    a times c is 9 times 4 is 36.
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    So minus 36.
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    All of that over 2 times a.
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    All of that over 6.
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    So this is equal to 10 plus or
    minus the square root of 64,
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    or really that's
    just going to be 8.
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    All of that over 6.
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    If we add 8 here, we get
    10 plus 8 is 18 over 6.
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    We get x could be equal to 3.
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    Or if we take the negative
    square root or the negative 8
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    here, 10 minus 8 is 2.
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    2 over 6 is 1/3.
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    So once again, you get
    the exact same solutions.
Title:
Example 5: Using the quadratic formula | Quadratic equations | Algebra I | Khan Academy
Description:

Applying the Quadratic Formula

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Video Language:
English
Team:
Khan Academy
Duration:
04:51

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