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Molarity Practice Problems

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    Calculate the molarity of a solution
    prepared by dissolving 9.8 moles of solid
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    NaOH, that's sodium hydroxide, in enough
    water to make 3.62 liters of solution.
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    To find molarity,
    you take moles of solute and
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    divide it by liters of solution.
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    So to set our equation up here,
    we have Molarity = moles of solute,
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    sodium hydroxide is the solute here
    cuz it's getting dissolved in water.
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    And we have 9.8 moles of that,
    divided by liters
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    of solution,
    which is 3.62 liters right here.
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    So find molarity, 9.8 divided by 3.62,
    round the answer to
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    two significant figures cuz I
    have 9.8 up here, and I get 2.7.
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    What should the units be for this?
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    When you find molarity the final answer
    is in units of molar, capital M.
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    So this is 2.7 molar.
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    But what 2.7 molar really means is that
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    there are 2.7 moles of NaOH,
    of the solute,
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    for every one liter of the solution.
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    So 2.7 M, but
    don't forget that that means 2.7 moles for
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    each 1 liter of this solution up here.
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    You dissolve 152.5 g of CuCl2,
    that's copper chloride,
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    in water to make a solution with
    a final volume of 2.25 liters.
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    What is it's molarity?
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    So, for molarity as you know,
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    we wanna take moles of solute
    divided by the liters of solution.
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    CuCl2, copper chloride is also a solute in
    this case cuz it's getting dissolved in
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    the water.
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    But the problem doesn't tell us how
    many moles of copper chloride we have.
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    It tells us how many grams
    of copper chloride we have.
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    So 152.5, we can't use that number,
    instead we have to convert
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    this to moles and then we can plug
    it into the molarity equation.
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    So to convert this amount
    in grams into moles,
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    the first thing that we've got to start
    with is the molar mass of copper chloride.
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    And so to find the molar mass of copper
    chloride, we got to find copper and
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    chlorine on the periodic table and
    take a look at their atomic masses.
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    So copper, there is one copper
    atom in copper chloride.
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    So I'll take the molar mass of copper,
    63.55, and then there
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    are two of these chlorines
    in copper chloride.
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    So I wanna take 2 times the molar
    mass of chlorine which is 35.44.
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    When I add these together,
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    I get 134.45 grams
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    per 1 mole, okay.
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    That's like the molar mass of it.
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    Now we're gonna have to use
    this as a conversion factor,
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    to go between grams and moles.
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    So remember that when we have
    conversion factors like this,
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    we can always write them in two ways.
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    We can write it like this,
    or we can flip it.
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    And so we can say 1 mole,
    for every 134.45 grams.
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    Both of these are ways to express
    the relationship between grams and
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    moles for copper chloride.
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    Now that I know how to go between grams
    and moles, because of conversion factor,
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    I can take 152.5 grams and I can multiply
    it by one of these two conversion factors.
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    I wanna use the one,
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    that gets rid of grams from
    the top of the equation up here.
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    Since grams is on the top,
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    I'm gonna choose this conversion
    factor with grams down here.
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    So now grams cancels out,
    grams cancels out, I'm left with moles.
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    And I'm gonna do 152.5
    times 1 divided by 134.45.
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    And that is gonna give me 1.134 moles.
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    I'm rounding to four significant figures
    here because I have one, two, three,
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    four significant figures and I don't worry
    about the 1 cuz it's part of a definition.
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    So now I know that I have
    1.134 moles of CuCl2.
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    Now I can go ahead and
    calculate the molarity.
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    So molarity is going
    to be moles of solute,
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    1.134 moles divided by liters
    of solution equals 2.25 liters.
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    And I wanna crank through that,
    rounding it to three significant figures,
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    cuz I have three sig figs there,
    it's gonna be 0.504 M.
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    And as I said before,
    don't forget that what that
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    means is that there
    are 0.504 moles of CuCl2 for
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    every 1 liter of this solution
    that we're making here.
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    A solution has a volume
    of 375 milliliters and
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    contains 42.5 grams of NaCl,
    sodium chloride.
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    What is its molarity?
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    This is kind of a challenging question,
    because there are two things we need to
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    calculate molarity, moles of solute and
    liters of solution.
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    We aren't given either of these
    two things in the problem.
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    Okay, instead of moles of solute,
    we're given grams of solute,
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    sodium chloride is the solute.
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    So we can't use that right away,
    we'll have to convert grams to moles.
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    And then instead of getting liters of
    solution, we get milliliters of solution.
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    So before we can run this equation,
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    we're gonna have to convert milliliters
    of solution into liters of solution.
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    So let's go step by step to show
    how do we do these conversions and
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    then how we can do
    the molarity at the end.
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    The first thing I'm gonna do is I'm gonna
    take this 42.5 g of sodium chloride and
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    turn it into moles of sodium chloride.
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    So I'm gonna need to start with
    a molar mass of sodium chloride.
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    We'll look at sodium and chlorine on
    the periodic table to get their masses.
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    And I'm gonna do 22.99 for sodium.
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    I only have one sodium, and
    I only have one chlorine here.
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    So I'm just going to do 35.44 here.
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    Add those together and
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    I'll get the molar mass which I'm
    gonnabe using as a convergent factor.
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    Okay, so I'm going to write
    this as 58.44 g over 1 mol.
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    That's one way to write it, or
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    I can flip the conversion factor and
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    I can write 1 mol divided by 58.44 g.
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    Now I have the two conversion
    factors that I'll use for
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    taking 42.5 grams of sodium chloride,
    multiplying it by one of these,
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    it's gonna be this one cuz I have
    grams up here grams down there.
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    So these cancel out.
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    42.5 divided by 58.44.
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    And that is going,
    I'll put the answer down here, and
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    that is going to give me 0.727
    moles of sodium chloride.
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    Now I know how many moles of sodium
    chloride I have, so I'm halfway there.
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    The next thing I have
    to do is I have to take
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    the volume which is 375 milliliters and
    multiply that by a conversion factor so
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    I can change it from
    milliliters into liters.
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    So there are 1,000
    milliliters in one liter,
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    which means that we can write
    these two conversion factors.
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    I want to use a conversion factor that's
    going to turn milliliters into liters.
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    So since it's on the top here, I will
    use a version of this conversion factor
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    that puts milliliters on the bottom here.
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    So, I'll cancel this out, cancel this out,
    I'll be left with liters.
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    And when I do that, 375 divided by 1,000.
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    I'm left with 0.375 liters.
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    Now I know my liters.
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    So now my moles of sodium chloride and
    my liters of solution.
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    And I can finish this by
    saying molarity equals
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    0.727 moles divided by 0.375 liters.
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    And I'm going to get 1.94,
    that's rounded to one,
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    two, three significant figures.
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    For my molarity, 1.94 are the units.
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    And as before,
    don't forget what this really means.
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    It means that for every liter of
    this solution, there are 1.94 moles.
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    1.94 moles per 1 liter of solution.
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    So sometimes you won't always be given
    moles, you won't always be given liters.
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    You'll probably have to convert from grams
    to moles or from milliliters into liters.
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    So just make sure you've got your
    conversion factors set up straight.
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    Now, in the next video instead of having
    moles and liters and calculating molarity,
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    you'll be given molarity and then you'll
    have to use that as a conversion factor
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    to move between moles in a solution and
    liters of a solution.
Title:
Molarity Practice Problems
Description:

To see all my Chemistry videos, check out http://vespr.org/chemistry

Confused about molarity? Don't be! Here, we'll do practice problems with molarity, calculating the moles and liters to find the molar concentration. We'll also have to use conversion factors to convert between grams and moles, and between milliliters and liters.

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Video Language:
English
Duration:
09:43

English subtitles

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