Molarity Practice Problems
-
0:00 - 0:06Calculate the molarity of a solution
prepared by dissolving 9.8 moles of solid -
0:06 - 0:15NaOH, that's sodium hydroxide, in enough
water to make 3.62 liters of solution. -
0:15 - 0:18To find molarity,
you take moles of solute and -
0:18 - 0:22divide it by liters of solution.
-
0:22 - 0:27So to set our equation up here,
we have Molarity = moles of solute, -
0:27 - 0:31sodium hydroxide is the solute here
cuz it's getting dissolved in water. -
0:31 - 0:36And we have 9.8 moles of that,
divided by liters -
0:36 - 0:42of solution,
which is 3.62 liters right here. -
0:42 - 0:49So find molarity, 9.8 divided by 3.62,
round the answer to -
0:49 - 0:55two significant figures cuz I
have 9.8 up here, and I get 2.7. -
0:55 - 0:57What should the units be for this?
-
0:57 - 1:04When you find molarity the final answer
is in units of molar, capital M. -
1:04 - 1:07So this is 2.7 molar.
-
1:07 - 1:11But what 2.7 molar really means is that
-
1:11 - 1:17there are 2.7 moles of NaOH,
of the solute, -
1:17 - 1:22for every one liter of the solution.
-
1:22 - 1:28So 2.7 M, but
don't forget that that means 2.7 moles for -
1:28 - 1:33each 1 liter of this solution up here.
-
1:33 - 1:39You dissolve 152.5 g of CuCl2,
that's copper chloride, -
1:39 - 1:45in water to make a solution with
a final volume of 2.25 liters. -
1:45 - 1:48What is it's molarity?
-
1:48 - 1:50So, for molarity as you know,
-
1:50 - 1:53we wanna take moles of solute
divided by the liters of solution. -
1:53 - 1:57CuCl2, copper chloride is also a solute in
this case cuz it's getting dissolved in -
1:57 - 1:59the water.
-
1:59 - 2:03But the problem doesn't tell us how
many moles of copper chloride we have. -
2:03 - 2:07It tells us how many grams
of copper chloride we have. -
2:07 - 2:13So 152.5, we can't use that number,
instead we have to convert -
2:13 - 2:17this to moles and then we can plug
it into the molarity equation. -
2:17 - 2:21So to convert this amount
in grams into moles, -
2:21 - 2:26the first thing that we've got to start
with is the molar mass of copper chloride. -
2:26 - 2:30And so to find the molar mass of copper
chloride, we got to find copper and -
2:30 - 2:36chlorine on the periodic table and
take a look at their atomic masses. -
2:36 - 2:41So copper, there is one copper
atom in copper chloride. -
2:41 - 2:48So I'll take the molar mass of copper,
63.55, and then there -
2:48 - 2:52are two of these chlorines
in copper chloride. -
2:52 - 3:01So I wanna take 2 times the molar
mass of chlorine which is 35.44. -
3:01 - 3:04When I add these together,
-
3:04 - 3:12I get 134.45 grams
-
3:12 - 3:15per 1 mole, okay.
-
3:15 - 3:17That's like the molar mass of it.
-
3:17 - 3:20Now we're gonna have to use
this as a conversion factor, -
3:20 - 3:23to go between grams and moles.
-
3:23 - 3:25So remember that when we have
conversion factors like this, -
3:25 - 3:27we can always write them in two ways.
-
3:27 - 3:29We can write it like this,
or we can flip it. -
3:29 - 3:37And so we can say 1 mole,
for every 134.45 grams. -
3:37 - 3:42Both of these are ways to express
the relationship between grams and -
3:42 - 3:45moles for copper chloride.
-
3:45 - 3:49Now that I know how to go between grams
and moles, because of conversion factor, -
3:49 - 3:58I can take 152.5 grams and I can multiply
it by one of these two conversion factors. -
3:58 - 4:00I wanna use the one,
-
4:00 - 4:04that gets rid of grams from
the top of the equation up here. -
4:04 - 4:05Since grams is on the top,
-
4:05 - 4:09I'm gonna choose this conversion
factor with grams down here. -
4:09 - 4:14So now grams cancels out,
grams cancels out, I'm left with moles. -
4:14 - 4:20And I'm gonna do 152.5
times 1 divided by 134.45. -
4:20 - 4:28And that is gonna give me 1.134 moles.
-
4:28 - 4:32I'm rounding to four significant figures
here because I have one, two, three, -
4:32 - 4:36four significant figures and I don't worry
about the 1 cuz it's part of a definition. -
4:36 - 4:41So now I know that I have
1.134 moles of CuCl2. -
4:41 - 4:44Now I can go ahead and
calculate the molarity. -
4:44 - 4:47So molarity is going
to be moles of solute, -
4:47 - 4:561.134 moles divided by liters
of solution equals 2.25 liters. -
4:56 - 5:00And I wanna crank through that,
rounding it to three significant figures, -
5:00 - 5:07cuz I have three sig figs there,
it's gonna be 0.504 M. -
5:07 - 5:10And as I said before,
don't forget that what that -
5:10 - 5:18means is that there
are 0.504 moles of CuCl2 for -
5:18 - 5:23every 1 liter of this solution
that we're making here. -
5:23 - 5:27A solution has a volume
of 375 milliliters and -
5:27 - 5:33contains 42.5 grams of NaCl,
sodium chloride. -
5:33 - 5:35What is its molarity?
-
5:35 - 5:38This is kind of a challenging question,
because there are two things we need to -
5:38 - 5:43calculate molarity, moles of solute and
liters of solution. -
5:43 - 5:46We aren't given either of these
two things in the problem. -
5:46 - 5:50Okay, instead of moles of solute,
we're given grams of solute, -
5:50 - 5:51sodium chloride is the solute.
-
5:51 - 5:55So we can't use that right away,
we'll have to convert grams to moles. -
5:55 - 5:59And then instead of getting liters of
solution, we get milliliters of solution. -
5:59 - 6:01So before we can run this equation,
-
6:01 - 6:06we're gonna have to convert milliliters
of solution into liters of solution. -
6:06 - 6:09So let's go step by step to show
how do we do these conversions and -
6:09 - 6:11then how we can do
the molarity at the end. -
6:11 - 6:16The first thing I'm gonna do is I'm gonna
take this 42.5 g of sodium chloride and -
6:16 - 6:18turn it into moles of sodium chloride.
-
6:18 - 6:23So I'm gonna need to start with
a molar mass of sodium chloride. -
6:23 - 6:27We'll look at sodium and chlorine on
the periodic table to get their masses. -
6:27 - 6:31And I'm gonna do 22.99 for sodium.
-
6:31 - 6:34I only have one sodium, and
I only have one chlorine here. -
6:34 - 6:38So I'm just going to do 35.44 here.
-
6:38 - 6:41Add those together and
-
6:41 - 6:45I'll get the molar mass which I'm
gonnabe using as a convergent factor. -
6:45 - 6:51Okay, so I'm going to write
this as 58.44 g over 1 mol. -
6:51 - 6:53That's one way to write it, or
-
6:53 - 6:59I can flip the conversion factor and
-
6:59 - 7:04I can write 1 mol divided by 58.44 g.
-
7:04 - 7:08Now I have the two conversion
factors that I'll use for -
7:08 - 7:14taking 42.5 grams of sodium chloride,
multiplying it by one of these, -
7:14 - 7:20it's gonna be this one cuz I have
grams up here grams down there. -
7:20 - 7:22So these cancel out.
-
7:22 - 7:2842.5 divided by 58.44.
-
7:28 - 7:31And that is going,
I'll put the answer down here, and -
7:31 - 7:39that is going to give me 0.727
moles of sodium chloride. -
7:39 - 7:44Now I know how many moles of sodium
chloride I have, so I'm halfway there. -
7:44 - 7:46The next thing I have
to do is I have to take -
7:46 - 7:52the volume which is 375 milliliters and
multiply that by a conversion factor so -
7:52 - 7:56I can change it from
milliliters into liters. -
7:56 - 8:00So there are 1,000
milliliters in one liter, -
8:00 - 8:04which means that we can write
these two conversion factors. -
8:04 - 8:08I want to use a conversion factor that's
going to turn milliliters into liters. -
8:08 - 8:12So since it's on the top here, I will
use a version of this conversion factor -
8:12 - 8:15that puts milliliters on the bottom here.
-
8:15 - 8:21So, I'll cancel this out, cancel this out,
I'll be left with liters. -
8:21 - 8:25And when I do that, 375 divided by 1,000.
-
8:25 - 8:31I'm left with 0.375 liters.
-
8:31 - 8:32Now I know my liters.
-
8:32 - 8:37So now my moles of sodium chloride and
my liters of solution. -
8:37 - 8:40And I can finish this by
saying molarity equals -
8:40 - 8:490.727 moles divided by 0.375 liters.
-
8:49 - 8:54And I'm going to get 1.94,
that's rounded to one, -
8:54 - 8:57two, three significant figures.
-
8:57 - 9:02For my molarity, 1.94 are the units.
-
9:02 - 9:04And as before,
don't forget what this really means. -
9:04 - 9:09It means that for every liter of
this solution, there are 1.94 moles. -
9:09 - 9:151.94 moles per 1 liter of solution.
-
9:15 - 9:21So sometimes you won't always be given
moles, you won't always be given liters. -
9:21 - 9:26You'll probably have to convert from grams
to moles or from milliliters into liters. -
9:26 - 9:29So just make sure you've got your
conversion factors set up straight. -
9:29 - 9:34Now, in the next video instead of having
moles and liters and calculating molarity, -
9:34 - 9:39you'll be given molarity and then you'll
have to use that as a conversion factor -
9:39 - 9:43to move between moles in a solution and
liters of a solution.
- Title:
- Molarity Practice Problems
- Description:
-
To see all my Chemistry videos, check out http://vespr.org/chemistry
Confused about molarity? Don't be! Here, we'll do practice problems with molarity, calculating the moles and liters to find the molar concentration. We'll also have to use conversion factors to convert between grams and moles, and between milliliters and liters.
- Video Language:
- English
- Duration:
- 09:43
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