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- [Voiceover] Let's now do a proof
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of the polynomial remainder theorem.
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Just to make the proof
a little bit tangible,
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I'm going to start with the example
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that we saw in the video that introduced
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the polynomial remainder theorem.
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We saw that if you took three x squared
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minus four x plus seven and you divided
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by x minus one, you got three x minus one
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with the remainder of six.
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When we do polynomial long division,
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how do we know when we've
got to our remainder?
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Well when we get to an expression that has
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a lower degree than the
thing that is the divisor,
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the thing that we're dividing
into the other thing.
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So in this example we
could have re-written
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what we just did right
over here as our f of x.
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Let me just write it right over here.
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So we could have said three x squared
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minus four x plus seven is equal to
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x minus one times the
quotient right over here,
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or I could say the
quotient times x minus one.
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So it's going to be
equal to this business.
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It's going to be equal
to three x minus one
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times the divisor, times x minus one.
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When you multiply these two things,
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you're not going to get exactly this.
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You still have to add the remainder.
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So plus the remainder.
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Actually, let me write
the actual remainder down.
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So plus six.
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The analogy here is exactly the analogy
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to when you did traditional division.
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If I were to say, actually, let me just
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show you the analogy.
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If I were to say 25 divided by four,
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you would say, okay,
well four goes into 25
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six times, six times four is 24.
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You would subtract, and then you would get
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a remainder, one.
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Or another way of saying
this is you could say
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that 25 is equal to six
times four plus one.
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So we just did the exact same thing here,
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but we just did it with expressions.
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So once again, I haven't
started the proof yet,
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I just wanted to make you feel comfortable
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with what I just wrote right over here.
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If I divided this expression
into this polynomial,
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and I were to get this quotient,
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that's the same thing as
saying this polynomial
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could be equal to three x minus one
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times x minus one plus six.
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Now this is true in general.
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Let's abstract a little bit.
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This is our f of x.
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So that is f of x.
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So f of x is going to be equal to
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whatever the quotient is.
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Let me call that q of x.
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So do this in a different color.
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So I'm going to call that q of x.
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This right over here is q of x.
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So f of x is going to be
equal to the quotient,
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q of x, times, this is our x minus a,
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in this case a is one, but I'm just trying
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to generalize it a little bit.
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So x minus a, and then plus the remainder.
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We know that the remainder is going
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to be a constant because the remainder
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is going to have a lower
degree then x minus a.
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X minus a is a first degree.
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So in order to have a lower degree,
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this has to be zeroth degree.
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This has to be a constant.
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So this is true in general.
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This is true for any polynomial
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f of x divided by any x minus a.
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So this is just true.
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So this is true for any
f of x and x minus a.
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Now what is going to happen
if we evaluate f of a?
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Well if f of x can be written like this,
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well we could write f of,
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let me do a in a new
color so it sticks out.
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We could write f of a would be equal to
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q of a times, I think you might see
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where this is going,
times a minus a plus r.
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Well what's that going to be equal to?
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What's all this business
going to be equal to?
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Well a minus a is zero, and q of a,
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I don't care what q of a is,
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if you're going to multiply it by zero
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all of this is going to be zero.
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So f of a is going to be equal to r.
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And so you're done.
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This is the proof of the
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polynomial remainder theorem.
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Any function, if when you
divide it by x minus a
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you get the quotient q
of x and the remainder r,
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it can then be written in this way.
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If it's written in this
way and you evaluated
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at f of a and you put the a over here,
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you're going to see that
f of a is going to be
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whatever that remainder was.
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That is the polynomial remainder theorem.
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And we're done.
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One of the simpler proofs that exists
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for something that at first
seems somewhat magical.