0:00:00.417,0:00:01.589 - [Voiceover] Let's now do a proof 0:00:01.589,0:00:04.248 of the polynomial remainder theorem. 0:00:04.248,0:00:06.257 Just to make the proof[br]a little bit tangible, 0:00:06.257,0:00:07.731 I'm going to start with the example 0:00:07.731,0:00:09.948 that we saw in the video that introduced 0:00:09.948,0:00:11.516 the polynomial remainder theorem. 0:00:11.516,0:00:13.129 We saw that if you took three x squared 0:00:13.129,0:00:15.068 minus four x plus seven and you divided 0:00:15.068,0:00:18.307 by x minus one, you got three x minus one 0:00:18.307,0:00:20.153 with the remainder of six. 0:00:20.153,0:00:21.732 When we do polynomial long division, 0:00:21.732,0:00:23.530 how do we know when we've[br]got to our remainder? 0:00:23.530,0:00:25.183 Well when we get to an expression that has 0:00:25.183,0:00:28.689 a lower degree than the[br]thing that is the divisor, 0:00:28.689,0:00:32.322 the thing that we're dividing[br]into the other thing. 0:00:32.322,0:00:34.862 So in this example we[br]could have re-written 0:00:34.862,0:00:39.302 what we just did right[br]over here as our f of x. 0:00:39.302,0:00:40.719 Let me just write it right over here. 0:00:40.719,0:00:44.498 So we could have said three x squared 0:00:44.498,0:00:48.480 minus four x plus seven is equal to 0:00:48.480,0:00:51.359 x minus one times the[br]quotient right over here, 0:00:51.359,0:00:53.797 or I could say the[br]quotient times x minus one. 0:00:53.797,0:00:57.384 So it's going to be[br]equal to this business. 0:00:57.384,0:01:01.877 It's going to be equal[br]to three x minus one 0:01:01.877,0:01:06.138 times the divisor, times x minus one. 0:01:10.497,0:01:11.566 When you multiply these two things, 0:01:11.566,0:01:12.611 you're not going to get exactly this. 0:01:12.611,0:01:14.665 You still have to add the remainder. 0:01:14.933,0:01:18.391 So plus the remainder. 0:01:18.694,0:01:20.535 Actually, let me write[br]the actual remainder down. 0:01:20.535,0:01:22.309 So plus six. 0:01:22.346,0:01:24.587 The analogy here is exactly the analogy 0:01:24.587,0:01:26.444 to when you did traditional division. 0:01:26.444,0:01:29.370 If I were to say, actually, let me just 0:01:29.370,0:01:30.924 show you the analogy. 0:01:31.088,0:01:36.088 If I were to say 25 divided by four, 0:01:38.529,0:01:42.627 you would say, okay,[br]well four goes into 25 0:01:42.627,0:01:46.121 six times, six times four is 24. 0:01:46.284,0:01:48.397 You would subtract, and then you would get 0:01:48.397,0:01:51.065 a remainder, one. 0:01:51.299,0:01:53.505 Or another way of saying[br]this is you could say 0:01:53.505,0:01:58.505 that 25 is equal to six[br]times four plus one. 0:02:12.161,0:02:13.948 So we just did the exact same thing here, 0:02:13.948,0:02:16.338 but we just did it with expressions. 0:02:16.664,0:02:18.801 So once again, I haven't[br]started the proof yet, 0:02:18.801,0:02:20.125 I just wanted to make you feel comfortable 0:02:20.125,0:02:22.168 with what I just wrote right over here. 0:02:22.168,0:02:26.242 If I divided this expression[br]into this polynomial, 0:02:26.242,0:02:27.705 and I were to get this quotient, 0:02:27.705,0:02:29.564 that's the same thing as[br]saying this polynomial 0:02:29.564,0:02:32.186 could be equal to three x minus one 0:02:32.186,0:02:35.156 times x minus one plus six. 0:02:35.599,0:02:37.201 Now this is true in general. 0:02:37.201,0:02:38.442 Let's abstract a little bit. 0:02:38.618,0:02:41.077 This is our f of x. 0:02:41.276,0:02:43.120 So that is f of x. 0:02:45.235,0:02:47.104 So f of x is going to be equal to 0:02:47.104,0:02:48.578 whatever the quotient is. 0:02:48.578,0:02:50.360 Let me call that q of x. 0:02:51.030,0:02:52.922 So do this in a different color. 0:02:53.722,0:02:58.333 So I'm going to call that q of x. 0:02:59.855,0:03:02.021 This right over here is q of x. 0:03:02.220,0:03:04.437 So f of x is going to be[br]equal to the quotient, 0:03:04.437,0:03:08.036 q of x, times, this is our x minus a, 0:03:08.036,0:03:09.499 in this case a is one, but I'm just trying 0:03:09.499,0:03:11.601 to generalize it a little bit. 0:03:11.601,0:03:16.098 So x minus a, and then plus the remainder. 0:03:18.252,0:03:19.532 We know that the remainder is going 0:03:19.532,0:03:21.746 to be a constant because the remainder 0:03:21.746,0:03:26.024 is going to have a lower[br]degree then x minus a. 0:03:26.024,0:03:28.288 X minus a is a first degree. 0:03:28.288,0:03:30.006 So in order to have a lower degree, 0:03:30.006,0:03:31.307 this has to be zeroth degree. 0:03:31.307,0:03:33.280 This has to be a constant. 0:03:33.280,0:03:35.160 So this is true in general. 0:03:35.160,0:03:37.145 This is true for any polynomial 0:03:37.145,0:03:42.145 f of x divided by any x minus a. 0:03:42.486,0:03:43.992 So this is just true. 0:03:44.586,0:03:49.586 So this is true for any[br]f of x and x minus a. 0:03:55.070,0:04:00.070 Now what is going to happen[br]if we evaluate f of a? 0:04:04.032,0:04:07.805 Well if f of x can be written like this, 0:04:07.805,0:04:10.347 well we could write f of, 0:04:10.347,0:04:14.027 let me do a in a new[br]color so it sticks out. 0:04:14.027,0:04:19.027 We could write f of a would be equal to 0:04:22.444,0:04:27.444 q of a times, I think you might see 0:04:31.660,0:04:36.660 where this is going,[br]times a minus a plus r. 0:04:43.217,0:04:45.110 Well what's that going to be equal to? 0:04:45.110,0:04:47.071 What's all this business[br]going to be equal to? 0:04:47.071,0:04:51.019 Well a minus a is zero, and q of a, 0:04:51.019,0:04:52.296 I don't care what q of a is, 0:04:52.296,0:04:53.829 if you're going to multiply it by zero 0:04:53.829,0:04:56.233 all of this is going to be zero. 0:04:56.233,0:05:01.233 So f of a is going to be equal to r. 0:05:06.634,0:05:07.829 And so you're done. 0:05:07.829,0:05:09.339 This is the proof of the 0:05:09.339,0:05:11.196 polynomial remainder theorem. 0:05:11.196,0:05:15.515 Any function, if when you[br]divide it by x minus a 0:05:15.515,0:05:18.580 you get the quotient q[br]of x and the remainder r, 0:05:18.580,0:05:20.390 it can then be written in this way. 0:05:20.390,0:05:22.701 If it's written in this[br]way and you evaluated 0:05:22.701,0:05:25.405 at f of a and you put the a over here, 0:05:25.405,0:05:26.926 you're going to see that[br]f of a is going to be 0:05:26.926,0:05:29.862 whatever that remainder was. 0:05:29.862,0:05:33.625 That is the polynomial remainder theorem. 0:05:33.625,0:05:34.646 And we're done. 0:05:34.646,0:05:36.998 One of the simpler proofs that exists 0:05:36.998,0:05:40.735 for something that at first[br]seems somewhat magical.