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www.mathcentre.ac.uk/.../8.2%20Differentiating%20sinx,%20cosx.mp4

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    The graph of Cynex looks like
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    this. And we can see the
    gradient of the tangents at
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    certain points of the graph.
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    For instance, when X equals
    π by two, the gradient of
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    the tangent is 0.
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    And it's also 0 - Π Pi 2, and at
    three π by 2.
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    At other points, the symmetry of
    the sine curve can help.
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    So the gradient of the tangent
    at X equals 0 is positive.
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    And it must be equal to
    the gradient of the
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    tangent at X equals 2π.
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    Also, the gradient of the
    tangent at X equals minus. Pi
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    must be equal to the gradient of
    the tangent at X equals π.
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    They must also both have the
    same magnitude as the gradient
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    at X equals 0.
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    But be negative.
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    Let's now plot the gradients
    of these tangents on a graph
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    directly underneath the sine
    graph.
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    Now assume we can join up the
    points with a smooth curve.
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    Once we don't know the values
    of the peaks and the troughs,
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    what we've drawn looks
    remarkably like the graph of
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    a cosine function.
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    So now we've got an idea of what
    we're looking for. Let's
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    differentiate cynex from first
    principles. Now there's three
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    things that we need to know.
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    The first is our definition of a
    derivative Cy by DX equals the
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    limit as Delta X approaches zero
    of F of X Plus Delta X
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    minus F of X.
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    Or divided by its Delta X?
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    The second is one of our
    trigonometric identity's and
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    that sign C minus sign D.
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    Equals twice the cause of C
    plus 3. / 2 multiplied by
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    the sign of C minus D
    divided by two.
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    And the third is the limit.
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    As theater approaches zero, that
    sign Theta divided by theater
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    equals 1. Now we can see
    this from a table of values.
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    So if we have a look at theater.
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    When it's in radians.
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    And then calculate.
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    Sign theater And then
    sign theater divided by theater.
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    We can have a look and see
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    what's happening. So our theater
    in radians. Let's look at one
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    first of all.
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    The sign of
    one is 0.84147.
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    So if we calculate sine
    Theta divided by Sita, we
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    just get the same 0.84147.
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    Now let's make theater smaller.
    Let's go to 0.1.
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    The sign of 0.1
    is 0.0998 three and
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    so on.
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    Just it continued
    on there, sorry.
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    OK, if we do sign
    theater divided by Theta then
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    we get 0.99833 and again.
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    Continues on.
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    Let's make seat even
    smaller now at 0.01.
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    The sign of Theta
    is going to be
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    0.00999, and so on.
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    So sine Theta divided
    by Sita equals 0.9998
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    three and so on.
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    And you can see that as Theta is
    getting smaller and smaller and
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    tending to 0.
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    Then sign Theta divided by
    theater is tending to one.
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    OK, let's carry on with
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    the calculation. So we have
    our Y equals sign
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    X. And let's start by just
    looking at the top part of our
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    formula. Our function of X Plus
    Delta X minus a function of X.
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    Sign X is our function of X, so
    our function of X Plus Delta X
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    is the sign of X Plus Delta X.
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    Minus R function of X, so minus
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    sign X. And this is where we
    have our sign. See take away as
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    signed D. So we can rewrite
    this as twice the cause.
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    Of C Plus D divided by
    two. So it's X Plus Delta
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    X Plus X divided by two.
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    Multiplied by the sign of C
    minus D divided by two.
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    So it's X Plus Delta X.
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    Minus X divided by two.
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    So this equals twice the cause.
    X Plus X is 2X Plus Delta
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    X or divided by 2 multiplied by
    the sign of X minus X is
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    0. So we just have Delta X
    divided by two.
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    I'm just going to tidy this up a
    little bit further, so we've got
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    two times the cause.
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    2 / 2 gives us just RX plus
    Delta X over 2 multiplied by the
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    sign of Delta X over 2.
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    So now if we go back to
    divide by DX.
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    Equals the limit as Delta
    X approaches 0.
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    Of F of X Plus Delta X
    minus F of X.
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    Which is this? So it's two calls
    X plus Delta X over 2 multiplied
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    by the sign of Delta X over 2.
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    All divided by Delta X.
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    Now multiplying the numerator,
    the top part of the fraction by
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    two is exactly the same as
    dividing the denominator. The
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    bottom part by two.
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    So I'm going to rewrite this.
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    Limit of Delta X tends to 0.
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    Taking this too from here.
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    And.
    Putting it as a division
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    in the denominator.
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    And I've done that so that you
    can see here. We've got the sign
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    of Delta X over 2.
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    Divided by Delta X over 2
    and that was where I third
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    fact came in that when we
    had signed theater divided
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    by Sita when we took the
    limit of Delta extending to
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    0, this will tend to one.
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    So let's actually take the
    limit. Now is Delta X approaches
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    0 sign Delta X over 2 divided by
    Delta X over 2?
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    Is one and Delta Rex over 2. As
    Delta X approaches, zero will be
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    0. So we're just left
    with our derivative of
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    sine X thing Cos X.
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    Let's have a look at the
    derivative now from first
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    principles of Cos X.
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    The graph of Cos X looks
    like this.
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    Again, we can draw the tangents
    at certain points.
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    And we can plot their values on
    a graph directly underneath the
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    cosine graph. This time if we
    join the points with a smooth
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    curve, we get a graph that looks
    like minus sign X.
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    Now before we
    differentiate cause X
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    from first principles,
    let's just have a look at
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    the graph of the sign of
    X plus Π by 2.
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    The graph of sign of X plus Π by
    2 looks like this.
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    It's just the graph of cynex
    with everything happening
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    pie by two earlier.
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    It's as though we've shifted the
    sign curve back along the X axis
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    by Π by 2.
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    And that just gives us Cossacks.
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    The two functions are the same.
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    Now shifting the sign curve back
    along the Axis doesn't affect
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    the shape of the curve, so it
    doesn't affect the shape of its
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    gradient function. Only the
    position of the gradient
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    function on the X axis.
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    So the derivative of sign of X
    plus Π by two is the cause of X
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    plus Π by 2.
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    But the graph of cause of X plus
    Π by two is identical to the
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    graph of minus sign X.
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    So the derivative of Cos X.
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    Is minus sign X?
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    Let's have a look at the
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    calculation now. Y equals Cos
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    X. And we need to know three
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    things again. To help us do the
    calculation, the first is our
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    definition of our derivative DY
    by DX equals the limit as Delta
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    X approaches 0.
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    About function of X Plus
    Delta X minus a function
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    of X divided by Delta X.
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    The second thing we need to know
    is one of the trigonometric
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    identity's. And that cause see
    minus calls D equals minus two
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    times the sign of C Plus D
    divided by 2 multiplied by the
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    sign of C minus D divided by
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    two. And the third thing
    is the limit. As theater
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    approaches 0. Sign Theta divided
    by feature is equal to 1.
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    So let's have a look.
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    Add putting our function into
    this top part against RF of X
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    Plus Delta X minus a function of
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    X. Is equal to.
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    I cause of X Plus
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    Delta X. Minus a function of
    X which is called sex.
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    So here we have our cause of C
    minus icons of D.
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    So let's do this
    substitution now.
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    So it's minus twice the sign of
    C Plus D over 2, so that's X
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    Plus Delta X.
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    Plus, X all divided by two.
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    Multiplied by the sign of C
    minus T over 2. So that's X
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    Plus Delta X.
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    Minus X divided by two.
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    Which equals minus two times
    the sign of X plus
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    X is 2X plus Delta
    X divided by two.
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    Multiplied by the sign of X
    minus X is 0, so we're just left
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    with Delta X divided by two.
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    And again, as we did before.
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    We write this is minus 2 sign 2X
    divided by two leaves us with X
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    Plus our Delta X over 2
    multiplied by our sign of Delta
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    X over 2.
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    Now we can turn the page and put
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    this into our.
    Formula.
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    So that we have the why
    by DX equals the limit a
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    Delta X approaches zero of minus
    2 signs of X Plus Delta
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    X over 2.
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    Multiplied by sign Delta X over
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    2. All divided by Delta
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    X. I'm not equals, and again
    we're going to do this change
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    where instead of multiplying the
    numerator by two, I'm going to
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    divide the denominator by two.
    So we have the limit as Delta X
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    approaches 0. Of minus
    the sign of X Plus Delta
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    X divided by 2 multiplied
    by the sign of Delta X
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    divided by two all
    divided by Delta X
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    divided by two.
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    Now as we take the limit as
    Delta X approaches 0. Again,
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    here we've got the sign of Delta
    X over 2 divided by Delta X over
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    2, and we know that as Delta X
    approaches zero, then this tends
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    to one. And then as Delta X
    divided by two, here tends to 0.
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    Then our derivative will be
    minus the sign of X.
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    So our derivative of Cos X is
    minus sign X.
Title:
www.mathcentre.ac.uk/.../8.2%20Differentiating%20sinx,%20cosx.mp4
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