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Midpoint and distance on complex plane

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    Voiceover:So we have two
    complex numbers here.
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    The complex number z is
    equal to two plus three i
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    and the complex number w is
    equal to negative five minus i.
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    What I want to do in
    this video is to first
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    plot these two complex
    numbers on the complex plane
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    and then think about what
    the distance is between
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    these two numbers on the
    plane and what complex
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    number is exactly halfway
    between these two numbers
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    or another way of thinking
    about it, what complex
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    number is the midpoint
    between these two numbers.
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    So I encourage you to
    pause this video and think
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    about it on your own
    before I work through it.
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    So let's first try to plot
    these on the complex planes.
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    So let me draw, so right over here,
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    let me draw our imaginary axis.
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    So our imaginary axis, and over
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    here let me draw our real axis.
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    Real axis right over
    there, and let's first,
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    let's see, we're gonna
    have it go as high as
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    positive two in the real axis
    and as low as negative five
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    along the real axis so let's
    go one, two, three, four, five.
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    One, two, three, four, five.
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    Along the imaginary axis
    we go as high as positive
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    three and as low as negative one.
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    So we could do one, two,
    three and we could do
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    one, two, three and of
    course I could keep going
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    up here just to have nice
    markers there although we
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    won't use that part of the plane.
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    Now let's plot these two points.
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    So the real part of z
    is two and then we have
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    three times i so the
    imaginary part is three.
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    So we would go right over here.
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    So this is two and this
    is three right over here.
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    Two plus three i, so that
    right over there is z.
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    Now let's plot w, w is negative five.
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    One, two, three, four, five, negative five
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    minus i, so this is negative
    one right over here.
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    So minus i, that is w.
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    So first we can think about
    the distance between these two
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    complex numbers; the distance
    on the complex plane.
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    So one way of thinking
    about it, that's really
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    just the distance of this
    line right over here.
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    And to figure that out
    we can really just think
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    about the Pythagorean theorem.
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    If you hear about the Distance
    Formula in two dimensions,
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    well that's really just
    an application of the
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    Pythagorean theorem, so let's
    think about that a little bit.
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    So we can think about
    how much have we changed
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    along the real axis which is
    this distance right over here.
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    This is how much we've
    changed along the real axis.
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    And if we're going from
    w to z, we're going from
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    negative 5 along the real axis to two.
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    What is two minus negative 5?
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    Well it's seven, if we
    go five to get to zero
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    along the real axis and then
    we go two more to get to two,
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    so the length of this
    right over here is seven.
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    And what is the length of
    this side right over here?
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    Well along the imaginary
    axis we're going from
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    negative one to three so
    the distance there is four.
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    So now we can apply the
    Pythagorean theorem.
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    This is a right triangle, so the distance
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    is going to be equal to the distance.
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    Let's just say that this
    is x right over here.
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    x squared is going to be
    equal to seven squared,
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    this is just the Pythagorean
    theorem, plus four squared.
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    Plus four squared or we
    can say that x is equal
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    to the square root of 49 plus 16.
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    I'll just write it out so
    I don't skip any steps.
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    49 plus 16, now what is
    that going to be equal to?
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    That is 65 so x, that's right,
    59 plus another 6 is 65.
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    x is equal to the square root of 65.
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    Now let's see, 65 you can't factor this.
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    There's no factors that
    are perfect squares here,
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    this is just 13 times five so
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    we can just leave it like that.
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    x is equal to the square
    root of 65 so the distance
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    in the complex plane between
    these two complex numbers,
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    square root of 65 which is I
    guess a little bit over eight.
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    Now what about the complex number that is
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    exactly halfway between these two?
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    Well to figure that out, we just have to
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    figure out what number
    has a real part that
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    is halfway between these two real parts
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    and what number has an imaginary part
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    that's halfway between
    these two imaginary parts.
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    So if we had some, let's say
    that some complex number,
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    let's just call it a, is
    the midpoint, it's real part
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    is going to be the mean
    of these two numbers.
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    So it's going to be
    two plus negative five.
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    Two plus negative five over two, over two,
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    and it's imaginary part
    is going to be the mean
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    of these two numbers so
    plus, plus three minus one.
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    Three minus one, minus
    one, over two times i
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    and this is equal to, let's
    see, two plus negative five
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    is negative three so
    this is negative 3/2 plus
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    this is three minus 1 is
    negative, is negative two
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    over two is let's see three,
    make sure I'm doing this right.
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    Three, something in the
    mean, three minus one is two
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    divided by two is one,
    so three plus three.
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    Negative 3/2 plus i is the
    midpoint between those two
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    and if we plot it we can verify
    that actually makes sense.
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    So real part negative 3/2,
    so that's negative one,
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    negative one and a half so
    it'll be right over there
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    and then plus i so it's
    going to be right over there.
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    And I'll just have to
    draw it perfectly to scale
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    but this makes sense, that this right
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    over here would be the midpoint.
Title:
Midpoint and distance on complex plane
Description:

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Video Language:
English
Team:
Khan Academy
Duration:
06:10

English subtitles

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