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Calculate the sum of all
positive divisors of 27,000.
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The easiest thing that
I can think of doing
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is first take the prime
factorization of 27,000,
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and then that will help us
kind of structure our thought
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of what all of the
different divisors of 27,000
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would have to look like.
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So 27,000 is the same thing
as 27 times 1,000, which
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is the same thing as 3 to the
third times 10 to the third,
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and 10 is, of course, the
same thing as 2 times 5.
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So this is the same thing
as 2 times 5 to the third,
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or it's the same thing as 2 to
the third times 5 to the third.
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So 27,000 is equal to
2 to the third times 3
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to the third times
5 to the third.
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So any divisor of 27,000 is
going to have to be made up
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of the product of up to three
2's, up to three 3's, and up
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to three 5's.
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So let's try to look
at all the combinations
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and think of a fast
way of summing them.
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So let's just say it
has no fives in it.
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It has no fives in a divisor.
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So if it has no fives, then
it could have up to three
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2's, so let's say
it has zero 2's.
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So I'm just going to
take the powers of 2,
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so if it has zero 2's,
then we'll put a 1
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here, if it has two 2's, it
has to be divisible by 4.
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If it has three 2's, it's
going to be divisible by 8.
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When I say three 2's, I
mean 2 times 2 times 2.
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Now, let's do it with the 3's.
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If you have, oh wait,
I forgot a power.
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If you have zero 2's, that means
it's just divisible by 1 from
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looking at the 2's.
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If you have one 2, it's
divisible by just 2.
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If you have two 2's,
you're divisible by 4.
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And if you have
three 2's, and when
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I mean that I'm saying
2 times 2 times 2,
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that means you're
divisible by 8.
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Let's do the same thing with 3.
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From the point of view of the 3,
if you have no 3's, that means
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at least you're divisible by 1.
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If you have one 3, that
means you're divisible by 3.
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Two 3's, or 3 times 3 means
you're divisible by 9.
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If you have three 3's, it
means you're divisible by 27.
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So let's look at all of
the possible combinations.
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And for this grid that I'm
going to generate right here,
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we assume that you're
not divisible by 5,
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or you're only divisible
by 5 to the zero power.
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So what are all the
possible numbers here?
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Well, you have 1 times 1 is 1.
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That's divisible by 1 and 1.
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You have 1 times 3, which
is 3, 1 times 9 which is 9,
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1 times 27 which is 27.
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So these are all
the numbers that
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are divisible by that have up
to three 3's in them, from zero
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to three 3's in them, and
they have no twos in them.
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If you throw
another two in here,
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you're essentially going to
multiply all of these numbers
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by two.
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If you throw
another two in here,
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you're going to multiply
all of these numbers by 2.
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Now, before I do
this, because I want
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to do this as fast as possible.
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I could figure out
what these numbers are,
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I could multiply them.
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But instead, let's
just take the sum.
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Let's just take the
sum here of this row,
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of this first row
that we just did.
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We have 1 plus 3 plus 9
plus 27, 3 plus 27 is 30,
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1 plus 9 is 10.
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So this is going to be 40.
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Now, whatever these numbers are,
they're all going to be 2 times
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these numbers.
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So the sum is going to be
80, and the sum over here
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is going to be 2 times
the previous row.
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Because here we multiplied by
2, here we're multiplying by 4,
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so it's going to be 160.
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And over here, we just
multiplied by 2 again,
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it's going to be 320.
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Or another way of thinking about
it, whatever the sum is here,
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it's going to be eight times
the sum of the first row.
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And I could, just so
you know what I'm doing,
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I could actually
put numbers here.
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This number would be 8, 24,
72, and whatever 8 times 27,
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I was at 160, 160
plus 56, so it's 216.
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But we don't want to do that.
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We just have to
think about the sums.
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So if you think about all of the
dividers of 27,000 that are not
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divisible by 5-- so
they're only divisible by 5
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to the zero power, I
guess you could say it.
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We've now figured
out their sum, it's
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going to be the sum
of all of these rows.
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So if you take 40
plus 80, you have
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120 plus 160 is 280
plus 320 is 600.
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So this is the situation.
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This is the sum of all of
the combinations of the 2's
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and the 3's that don't
have any 5's in them.
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Now, if you took
the same combination
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of 2's and 3's, so
these added up to 600,
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let me write it over here.
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So no fives Now, if you
did the same exact thing
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that we just did
here, but we just
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multiplied everything by 5.
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So we'd then be looking
at all the combinations
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that have this many twos and
this many threes, and one five,
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what would happen to this sum?
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Well, we would just
multiply it by 5.
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So let's multiply that by 5.
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So you multiply 600 by 5,
you get 30 with two zeroes,
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and so this is one 5 in
the prime factorization
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of the divisors.
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Now, if I wanted two 5's, I
could just multiply by 5 again.
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So if I multiply by 5
again, I get 15,000.
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This is two 5's.
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Another way of
thinking about this,
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if I just multiply
every term here
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by 25, which is essentially
multiplying by 5 times 5,
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this sum is going to be 600
times 25, which is 15,000.
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Now, if I have three
5's than I could just
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multiply this by five again.
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5 times 15 is 50 plus 25 is 75.
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So its 75,000.
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So now I know all the sums.
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If I have no 5's, the
sum of all the divisors
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is 600, if I have one 5,
3,000, so on and so forth.
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If I want the sum of
everything, I just
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take the sum of these numbers.
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Let me scroll down a little bit.
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So I get, well, I
have zero, zero,
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than in the hundreds
place, I only have a six,
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and then 3 plus 5 plus 5 is 13.
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Is that right?
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Yeah, that's 13.
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And then carry the one,
and then I have a 9.
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So 93,600.
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So the sum of all positive
divisors of 27,000, 93,600.
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Hope you found
that entertaining.