-
Voiceover:On the right-hand side we have
-
a bunch of expressions
that are just ratios
-
of different information
given in these two diagrams.
-
Then over here on the left we have
-
the sine taken of angle MKJ,
-
cosine of angle MKJ, and
tangent of angle MKJ.
-
Angle MKJ is this angle right over here
-
same thing as theta, so these two angles.
-
These two angles have the same measure.
-
We see that right over there.
-
What we want to do is figure out
-
which of these expressions are equivalent
-
to which of these
expressions right over here.
-
I encourage you to pause the video
-
and try to work this through on your own.
-
Assuming you've had a go at it,
-
let's try to work this out.
-
When you look at this diagram,
-
it looks like the
intention here on the left
-
is this evokes the unit circle definition
-
of trig functions because
this is a unit circle
-
right over here,
-
and this evokes kind of
the soh cah toa definition
-
because we're just kind of in a
-
plain, vanilla right triangle.
-
Just to remind ourselves,
-
let's just remind ourselves of soh cah toa
-
because I have a feeling
it might be useful.
-
Sine is opposite over hypotenuse.
-
Cosine is adjacent over hypotenuse,
-
and tangent is opposite over adjacent.
-
We can refer to this and we can also
-
remind ourselves of the
unit circle definition
-
of trig functions that
the cosine of an angle
-
is the X coordinate and that the sine
-
of where this ray
intersects the unit circle,
-
and the sine of this angle is going to be
-
the Y coordinate.
-
What we'll see through this video
-
is that they actually, the
unit circle definition,
-
is just an extension of soh cah toa.
-
Let's look first at X over one.
-
We have X, X is the X coordinate.
-
That's also the length of this side
-
right over here,
-
relative to this angle, theta.
-
That is the adjacent side.
-
So X is equal to the adjacent side.
-
What is one?
-
Well, this is a unit circle.
-
One is the length of the radius
-
which for this right triangle
is also the hypotenuse.
-
If we apply the soh cah toa definition,
-
X over one is adjacent over hypotenuse,
-
adjacent over hypotenuse,
-
adjacent over hypotenuse, that's cosine.
-
That's going to be this is
equal to cosine of theta,
-
but theta is the same thing as angle MKJ.
-
They have the same measure so cosine
-
of angle MKJ is equal to cosine of theta
-
which is equal to X over one.
-
Now let's move over to Y over one.
-
Well, Y is going to be
the length of this side
-
right over here.
-
Y is going to be, let
me do this in the blue.
-
Y is going to be this length
relative to angle theta.
-
That is the opposite side.
-
That is the opposite side.
-
Now which trig function is
opposite over hypotenuse?
-
Opposite over hypotenuse?
-
That's sine of theta.
-
Sine of theta.
-
So sine of angle MKJ is the same thing
-
as sine of theta.
-
We see that they have the same measure,
-
and now we see that's the same thing
-
as Y over one.
-
Now for both of these I used
the soh cah toa definition,
-
but we could have also used
the unit circle definition.
-
X over one, that's the same thing.
-
That's the same thing as X,
-
and the unit circle definition says
-
the X coordinate of where this,
-
I guess you could say, the
terminal side of this angle,
-
this ray right over here,
-
intersects the unit circle.
-
That by definition, by
the unit circle definition
-
is the cosine of this angle.
-
X is equal to the cosine of this angle,
-
and the unit circle definition,
-
the Y coordinate is equal
to the sine of this angle.
-
We could have written
this as instead of X, Y,
-
we could have written
this as cosine of theta,
-
sine theta just like that,
but let's keep going.
-
Now we have X over Y.
-
We have adjacent over,
-
we have adjacent over opposite.
-
So this is equal to
adjacent over opposite.
-
Tangent is opposite over adjacent,
-
not adjacent over opposite.
-
This is the reciprocal of tangent.
-
This right over here, if we had to,
-
this is equal to one
over tangent of theta.
-
We later learn about
cotangent and all of that
-
which is essentially this,
-
but it's not one of our choices.
-
So we can rule this one out.
-
Then we have Y over X.
-
Well, this is looking good.
-
This is Y is opposite.
-
Opposite.
-
X is adjacent relative to angle theta.
-
Adjacent.
-
So this is the tangent of theta.
-
This is equal to tangent of theta.
-
Tangent of angle MKJ is the same thing
-
as tangent of theta which is equal,
-
which is equal to Y over X.
-
Now let's look at J over K, so J over K.
-
Now we're moving over to this triangle,
-
J over K.
-
Relative to this angle because this
-
is the angle that we care about,
-
J is the length of the adjacent side,
-
and K is the length of the opposite side,
-
of the opposite side.
-
This is adjacent over opposite.
-
This is equal to adjacent over opposite.
-
Tangent is opposite over adjacent
-
not adjacent over opposite.
-
So once again this is the reciprocal
-
of the tangent function
not one of the choices
-
right over here so we
can rule that one out.
-
Now K over J.
-
Well, now this is opposite over adjacent.
-
Opposite over adjacent.
-
That is equal to tangent of theta.
-
This is equal to tangent of theta,
-
or tangent of angle MKJ.
-
This is equal to K over J.
-
Now we have M over J, M over J.
-
Hypotenuse over adjacent side.
-
This of course is equal to the hypotenuse.
-
Hypotenuse over adjacent.
-
Well, if it was adjacent over hypotenuse,
-
we'd be dealing with cosine,
-
but this is the reciprocal of that.
-
This is actually one
over the cosine of theta
-
not one of our choices,
-
not one of our choices here so I'll just
-
rule that one out over there.
-
Then we have it's reciprocal, J over M.
-
That's adjacent over hypotenuse.
-
Adjacent over hypotenuse is cosine.
-
This is equal to cosine of theta,
-
or cosine of angle MKJ so
we could write it down.
-
This is equivalent to J over M.
-
Then one last one, K over M.
-
Well, that's opposite over hypotenuse,
-
opposite over hypotenuse.
-
That's going to be sine of theta.
-
This right over here is
equal to sine of theta
-
which is the same thing
as sine of angle MKJ
-
which is the same thing as
all of these expressions.
-
This is equal to K over M,
-
and we are done.