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Linear Equations in Slope Intercept Form

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    In this video I'm going to do a
    bunch of examples of finding
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    the equations of lines in
    slope-intercept form.
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    Just as a bit of a review, that
    means equations of lines
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    in the form of y is equal to mx
    plus b where m is the slope
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    and b is the y-intercept.
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    So let's just do a bunch of
    these problems. So here they
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    tell us that a line has a slope
    of negative 5, so m is
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    equal to negative 5.
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    And it has a y-intercept of 6.
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    So b is equal to 6.
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    So this is pretty
    straightforward.
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    The equation of this line
    is y is equal to
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    negative 5x plus 6.
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    That wasn't too bad.
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    Let's do this next
    one over here.
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    The line has a slope of negative
    1 and contains the
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    point 4/5 comma 0.
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    So they're telling us the slope,
    slope of negative 1.
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    So we know that m is equal to
    negative 1, but we're not 100%
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    sure about where the y-intercept
    is just yet.
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    So we know that this equation
    is going to be of the form y
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    is equal to the slope negative
    1x plus b, where b is the
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    y-intercept.
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    Now, we can use this coordinate
    information, the
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    fact that it contains this
    point, we can use that
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    information to solve for b.
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    The fact that the line contains
    this point means that
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    the value x is equal to 4/5, y
    is equal to 0 must satisfy
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    this equation.
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    So let's substitute those in.
    y is equal to 0 when x is
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    equal to 4/5.
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    So 0 is equal to negative
    1 times 4/5 plus b.
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    I'll scroll down a little bit.
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    So let's see, we get a 0 is
    equal to negative 4/5 plus b.
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    We can add 4/5 to both sides
    of this equation.
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    So we get add a 4/5 there.
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    We could add a 4/5 to
    that side as well.
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    The whole reason I did that is
    so that cancels out with that.
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    You get b is equal to 4/5.
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    So we now have the equation
    of the line.
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    y is equal to negative 1 times
    x, which we write as negative
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    x, plus b, which is 4/5,
    just like that.
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    Now we have this one.
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    The line contains the point
    2 comma 6 and 5 comma 0.
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    So they haven't given us the
    slope or the y-intercept
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    explicitly.
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    But we could figure out both
    of them from these
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    coordinates.
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    So the first thing we can do
    is figure out the slope.
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    So we know that the slope m is
    equal to change in y over
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    change in x, which is equal to--
    What is the change in y?
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    Let's start with this
    one right here.
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    So we do 6 minus 0.
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    Let me do it this way.
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    So that's a 6-- I want to make
    it color-coded-- minus 0.
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    So 6 minus 0, that's
    our change in y.
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    Our change in x is 2 minus 5.
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    The reason why I color-coded
    it is I wanted to show you
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    when I used this y term first,
    I used the 6 up here, that I
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    have to use this x term
    first as well.
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    So I wanted to show you, this
    is the coordinate 2 comma 6.
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    This is the coordinate
    5 comma 0.
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    I couldn't have swapped
    the 2 and the 5 then.
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    Then I would have gotten the
    negative of the answer.
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    But what do we get here?
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    This is equal to
    6 minus 0 is 6.
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    2 minus 5 is negative 3.
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    So this becomes negative 6
    over 3, which is the same
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    thing as negative 2.
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    So that's our slope.
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    So, so far we know that the line
    must be, y is equal to
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    the slope-- I'll do that in
    orange-- negative 2 times x
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    plus our y-intercept.
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    Now we can do exactly what we
    did in the last problem.
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    We can use one of these
    points to solve for b.
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    We can use either one.
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    Both of these are on the line,
    so both of these must satisfy
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    this equation.
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    I'll use the 5 comma 0 because
    it's always nice when
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    you have a 0 there.
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    The math is a little
    bit easier.
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    So let's put the 5
    comma 0 there.
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    So y is equal to 0 when
    x is equal to 5.
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    So y is equal to 0 when you have
    negative 2 times 5, when
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    x is equal to 5 plus b.
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    So you get 0 is equal
    to -10 plus b.
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    If you add 10 to both sides of
    this equation, let's add 10 to
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    both sides, these
    two cancel out.
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    You get b is equal to
    10 plus 0 or 10.
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    So you get b is equal to 10.
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    Now we know the equation
    for the line.
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    The equation is y-- let me do it
    in a new color-- y is equal
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    to negative 2x plus b plus 10.
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    We are done.
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    Let's do another one of these.
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    All right, the line contains
    the points 3 comma 5 and
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    negative 3 comma 0.
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    Just like the last problem, we
    start by figuring out the
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    slope, which we will call m.
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    It's the same thing as the rise
    over the run, which is
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    the same thing as the change
    in y over the change in x.
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    If you were doing this for your
    homework, you wouldn't
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    have to write all this.
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    I just want to make sure that
    you understand that these are
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    all the same things.
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    Then what is our change in
    y over change in x?
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    This is equal to, let's start
    with this side first. It's just
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    to show you I could pick
    either of these points.
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    So let's say it's 0 minus
    5 just like that.
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    So I'm using this coordinate
    first. I'm kind of viewing it
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    as the endpoint.
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    Remember when I first learned
    this, I would always be
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    tempted to do the x
    in the numerator.
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    No, you use the y's
    in the numerator.
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    So that's the second
    of the coordinates.
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    That is going to be over
    negative 3 minus 3.
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    This is the coordinate
    negative 3, 0.
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    This is the coordinate 3, 5.
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    We're subtracting that.
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    So what are we going to get?
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    This is going to be equal to--
    I'll do it in a neutral
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    color-- this is going to be
    equal to the numerator is
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    negative 5 over negative 3
    minus 3 is negative 6.
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    So the negatives cancel out.
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    You get 5/6.
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    So we know that the equation is
    going to be of the form y
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    is equal to 5/6 x plus b.
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    Now we can substitute one of
    these coordinates in for b.
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    So let's do.
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    I always like to use the one
    that has the 0 in it.
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    So y is a zero when x is
    negative 3 plus b.
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    So all I did is I substituted
    negative 3 for x, 0 for y.
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    I know I can do that because
    this is on the line.
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    This must satisfy the equation
    of the line.
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    Let's solve for b.
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    So we get zero is equal to, well
    if we divide negative 3
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    by 3, that becomes a 1.
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    If you divide 6 by 3,
    that becomes a 2.
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    So it becomes negative
    5/2 plus b.
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    We could add 5/2 to both
    sides of the equation,
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    plus 5/2, plus 5/2.
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    I like to change my notation
    just so you get
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    familiar with both.
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    So the equation becomes 5/2 is
    equal to-- that's a 0-- is
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    equal to b.
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    b is 5/2.
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    So the equation of our line is
    y is equal to 5/6 x plus b,
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    which we just figured out
    is 5/2, plus 5/2.
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    We are done.
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    Let's do another one.
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    We have a graph here.
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    Let's figure out the equation
    of this graph.
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    This is actually, on some level,
    a little bit easier.
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    What's the slope?
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    Slope is change in y
    over change it x.
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    So let's see what happens.
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    When we move in x, when our
    change in x is 1, so that is
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    our change in x.
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    So change in x is 1.
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    I'm just deciding to change
    my x by 1, increment by 1.
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    What is the change in y?
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    It looks like y changes
    exactly by 4.
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    It looks like my delta y, my
    change in y, is equal to 4
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    when my delta x is equal to 1.
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    So change in y over change in
    x, change in y is 4 when
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    change in x is 1.
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    So the slope is equal to 4.
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    Now what's its y-intercept?
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    Well here we can just
    look at the graph.
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    It looks like it intersects
    y-axis at y is equal to
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    negative 6, or at the
    point 0, negative 6.
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    So we know that b is equal
    to negative 6.
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    So we know the equation
    of the line.
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    The equation of the line is y is
    equal to the slope times x
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    plus the y-intercept.
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    I should write that.
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    So minus 6, that is plus
    negative 6 So that is the
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    equation of our line.
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    Let's do one more of these.
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    So they tell us that f of
    1.5 is negative 3, f of
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    negative 1 is 2.
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    What is that?
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    Well, all this is just a fancy
    way of telling you that the
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    point when x is 1.5, when you
    put 1.5 into the function, the
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    function evaluates
    as negative 3.
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    So this tells us that the
    coordinate 1.5, negative 3 is
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    on the line.
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    Then this tells us that the
    point when x is negative 1, f
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    of x is equal to 2.
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    This is just a fancy way of
    saying that both of these two
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    points are on the line,
    nothing unusual.
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    I think the point of this
    problem is to get you familiar
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    with function notation, for you
    to not get intimidated if
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    you see something like this.
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    If you evaluate the function
    at 1.5, you get negative 3.
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    So that's the coordinate if
    you imagine that y is
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    equal to f of x.
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    So this would be the
    y-coordinate.
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    It would be equal to negative
    3 when x is 1.5.
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    Anyway, I've said it
    multiple times.
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    Let's figure out the
    slope of this line.
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    The slope which is change in y
    over change in x is equal to,
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    let's start with 2 minus this
    guy, negative 3-- these are
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    the y-values-- over, all
    of that over, negative
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    1 minus this guy.
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    Let me write it this way,
    negative 1 minus
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    that guy, minus 1.5.
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    I do the colors because I want
    to show you that the negative
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    1 and the 2 are both coming from
    this, that's why I use
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    both of them first. If I used
    these guys first, I would have
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    to use both the x and the y
    first. If I use the 2 first, I
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    have to use the negative
    1 first. That's why I'm
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    color-coding it.
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    So this is going to be equal
    to 2 minus negative 3.
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    That's the same thing
    as 2 plus 3.
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    So that is 5.
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    Negative 1 minus 1.5
    is negative 2.5.
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    5 divided by 2.5
    is equal to 2.
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    So the slope of this
    line is negative 2.
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    Actually I'll take a little
    aside to show you it doesn't
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    matter what order
    I do this in.
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    If I use this coordinate first,
    then I have to use that
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    coordinate first. Let's
    do it the other way.
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    If I did it as negative 3
    minus 2 over 1.5 minus
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    negative 1, this should be minus
    the 2 over 1.5 minus the
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    negative 1.
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    This should give me
    the same answer.
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    This is equal to what?
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    Negative 3 minus 2 is negative
    5 over 1.5 minus negative 1.
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    That's 1.5 plus 1.
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    That's over 2.5.
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    So once again, this is
    equal the negative 2.
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    So I just wanted to show you,
    it doesn't matter which one
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    you pick as the starting or
    the endpoint, as long as
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    you're consistent.
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    If this is the starting y,
    this is the starting x.
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    If this is the finishing
    y, this has to be
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    the finishing x.
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    But anyway, we know that the
    slope is negative 2.
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    So we know the equation is y is
    equal to negative 2x plus
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    some y-intercept.
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    Let's use one of these
    coordinates.
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    I'll use this one since it
    doesn't have a decimal in it.
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    So we know that y
    is equal to 2.
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    So y is equal to 2 when x
    is equal to negative 1.
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    Of course you have
    your plus b.
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    So 2 is equal to negative 2
    times negative 1 is 2 plus b.
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    If you subtract 2 from both
    sides of this equation, minus
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    2, minus 2, you're subtracting
    it from both sides of this
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    equation, you're going to get
    0 on the left-hand side is
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    equal to b.
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    So b is 0.
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    So the equation of our
    line is just y is
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    equal to negative 2x.
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    Actually if you wanted to write
    it in function notation,
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    it would be that f of x is
    equal to negative 2x.
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    I kind of just assumed that
    y is equal to f of x.
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    But this is really
    the equation.
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    They never mentioned y's here.
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    So you could just write f of x
    is equal to 2x right here.
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    Each of these coordinates
    are the coordinates
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    of x and f of x.
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    So you could even view the
    definition of slope as change
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    in f of x over change in x.
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    These are all equivalent ways
    of viewing the same thing.
Title:
Linear Equations in Slope Intercept Form
Description:

Linear Equations in Slope Intercept Form

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Video Language:
English
Duration:
14:58

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