1 00:00:00,450 --> 00:00:03,570 In this video I'm going to do a bunch of examples of finding 2 00:00:03,570 --> 00:00:07,170 the equations of lines in slope-intercept form. 3 00:00:07,170 --> 00:00:09,610 Just as a bit of a review, that means equations of lines 4 00:00:09,610 --> 00:00:17,050 in the form of y is equal to mx plus b where m is the slope 5 00:00:17,050 --> 00:00:21,200 and b is the y-intercept. 6 00:00:21,200 --> 00:00:24,870 So let's just do a bunch of these problems. So here they 7 00:00:24,870 --> 00:00:28,900 tell us that a line has a slope of negative 5, so m is 8 00:00:28,900 --> 00:00:30,740 equal to negative 5. 9 00:00:30,740 --> 00:00:34,290 And it has a y-intercept of 6. 10 00:00:34,290 --> 00:00:36,300 So b is equal to 6. 11 00:00:36,300 --> 00:00:37,985 So this is pretty straightforward. 12 00:00:37,985 --> 00:00:41,530 The equation of this line is y is equal to 13 00:00:41,530 --> 00:00:47,550 negative 5x plus 6. 14 00:00:47,550 --> 00:00:49,570 That wasn't too bad. 15 00:00:49,570 --> 00:00:51,570 Let's do this next one over here. 16 00:00:51,570 --> 00:00:54,300 The line has a slope of negative 1 and contains the 17 00:00:54,300 --> 00:00:57,320 point 4/5 comma 0. 18 00:00:57,320 --> 00:01:00,600 So they're telling us the slope, slope of negative 1. 19 00:01:00,600 --> 00:01:05,230 So we know that m is equal to negative 1, but we're not 100% 20 00:01:05,230 --> 00:01:09,190 sure about where the y-intercept is just yet. 21 00:01:09,190 --> 00:01:12,510 So we know that this equation is going to be of the form y 22 00:01:12,510 --> 00:01:19,300 is equal to the slope negative 1x plus b, where b is the 23 00:01:19,300 --> 00:01:20,460 y-intercept. 24 00:01:20,460 --> 00:01:23,650 Now, we can use this coordinate information, the 25 00:01:23,650 --> 00:01:25,870 fact that it contains this point, we can use that 26 00:01:25,870 --> 00:01:28,590 information to solve for b. 27 00:01:28,590 --> 00:01:31,530 The fact that the line contains this point means that 28 00:01:31,530 --> 00:01:37,690 the value x is equal to 4/5, y is equal to 0 must satisfy 29 00:01:37,690 --> 00:01:38,265 this equation. 30 00:01:38,265 --> 00:01:43,120 So let's substitute those in. y is equal to 0 when x is 31 00:01:43,120 --> 00:01:44,090 equal to 4/5. 32 00:01:44,090 --> 00:01:50,170 So 0 is equal to negative 1 times 4/5 plus b. 33 00:01:50,170 --> 00:01:52,810 I'll scroll down a little bit. 34 00:01:52,810 --> 00:01:58,110 So let's see, we get a 0 is equal to negative 4/5 plus b. 35 00:01:58,110 --> 00:02:02,040 We can add 4/5 to both sides of this equation. 36 00:02:02,040 --> 00:02:04,250 So we get add a 4/5 there. 37 00:02:04,250 --> 00:02:07,320 We could add a 4/5 to that side as well. 38 00:02:07,320 --> 00:02:10,100 The whole reason I did that is so that cancels out with that. 39 00:02:10,100 --> 00:02:12,130 You get b is equal to 4/5. 40 00:02:16,250 --> 00:02:19,180 So we now have the equation of the line. 41 00:02:19,180 --> 00:02:23,040 y is equal to negative 1 times x, which we write as negative 42 00:02:23,040 --> 00:02:32,500 x, plus b, which is 4/5, just like that. 43 00:02:32,500 --> 00:02:34,480 Now we have this one. 44 00:02:34,480 --> 00:02:39,580 The line contains the point 2 comma 6 and 5 comma 0. 45 00:02:39,580 --> 00:02:42,540 So they haven't given us the slope or the y-intercept 46 00:02:42,540 --> 00:02:43,030 explicitly. 47 00:02:43,030 --> 00:02:45,350 But we could figure out both of them from these 48 00:02:45,350 --> 00:02:45,650 coordinates. 49 00:02:45,650 --> 00:02:48,270 So the first thing we can do is figure out the slope. 50 00:02:48,270 --> 00:02:53,750 So we know that the slope m is equal to change in y over 51 00:02:53,750 --> 00:02:58,100 change in x, which is equal to-- What is the change in y? 52 00:02:58,100 --> 00:02:59,490 Let's start with this one right here. 53 00:02:59,490 --> 00:03:00,985 So we do 6 minus 0. 54 00:03:04,210 --> 00:03:05,070 Let me do it this way. 55 00:03:05,070 --> 00:03:10,410 So that's a 6-- I want to make it color-coded-- minus 0. 56 00:03:10,410 --> 00:03:14,340 So 6 minus 0, that's our change in y. 57 00:03:14,340 --> 00:03:24,190 Our change in x is 2 minus 5. 58 00:03:24,190 --> 00:03:26,320 The reason why I color-coded it is I wanted to show you 59 00:03:26,320 --> 00:03:30,890 when I used this y term first, I used the 6 up here, that I 60 00:03:30,890 --> 00:03:33,380 have to use this x term first as well. 61 00:03:33,380 --> 00:03:36,730 So I wanted to show you, this is the coordinate 2 comma 6. 62 00:03:36,730 --> 00:03:38,590 This is the coordinate 5 comma 0. 63 00:03:38,590 --> 00:03:41,650 I couldn't have swapped the 2 and the 5 then. 64 00:03:41,650 --> 00:03:45,030 Then I would have gotten the negative of the answer. 65 00:03:45,030 --> 00:03:46,080 But what do we get here? 66 00:03:46,080 --> 00:03:51,210 This is equal to 6 minus 0 is 6. 67 00:03:51,210 --> 00:03:54,770 2 minus 5 is negative 3. 68 00:03:54,770 --> 00:03:58,910 So this becomes negative 6 over 3, which is the same 69 00:03:58,910 --> 00:04:01,310 thing as negative 2. 70 00:04:01,310 --> 00:04:02,250 So that's our slope. 71 00:04:02,250 --> 00:04:06,920 So, so far we know that the line must be, y is equal to 72 00:04:06,920 --> 00:04:12,580 the slope-- I'll do that in orange-- negative 2 times x 73 00:04:12,580 --> 00:04:15,160 plus our y-intercept. 74 00:04:15,160 --> 00:04:17,779 Now we can do exactly what we did in the last problem. 75 00:04:17,779 --> 00:04:20,579 We can use one of these points to solve for b. 76 00:04:20,579 --> 00:04:22,029 We can use either one. 77 00:04:22,029 --> 00:04:25,920 Both of these are on the line, so both of these must satisfy 78 00:04:25,920 --> 00:04:26,900 this equation. 79 00:04:26,900 --> 00:04:29,800 I'll use the 5 comma 0 because it's always nice when 80 00:04:29,800 --> 00:04:31,020 you have a 0 there. 81 00:04:31,020 --> 00:04:32,820 The math is a little bit easier. 82 00:04:32,820 --> 00:04:34,510 So let's put the 5 comma 0 there. 83 00:04:34,510 --> 00:04:38,900 So y is equal to 0 when x is equal to 5. 84 00:04:38,900 --> 00:04:43,820 So y is equal to 0 when you have negative 2 times 5, when 85 00:04:43,820 --> 00:04:47,700 x is equal to 5 plus b. 86 00:04:47,700 --> 00:04:52,650 So you get 0 is equal to -10 plus b. 87 00:04:52,650 --> 00:04:57,820 If you add 10 to both sides of this equation, let's add 10 to 88 00:04:57,820 --> 00:05:00,680 both sides, these two cancel out. 89 00:05:00,680 --> 00:05:03,970 You get b is equal to 10 plus 0 or 10. 90 00:05:03,970 --> 00:05:06,420 So you get b is equal to 10. 91 00:05:06,420 --> 00:05:07,935 Now we know the equation for the line. 92 00:05:07,935 --> 00:05:14,110 The equation is y-- let me do it in a new color-- y is equal 93 00:05:14,110 --> 00:05:22,280 to negative 2x plus b plus 10. 94 00:05:22,280 --> 00:05:23,470 We are done. 95 00:05:23,470 --> 00:05:24,720 Let's do another one of these. 96 00:05:28,180 --> 00:05:31,270 All right, the line contains the points 3 comma 5 and 97 00:05:31,270 --> 00:05:32,890 negative 3 comma 0. 98 00:05:32,890 --> 00:05:36,380 Just like the last problem, we start by figuring out the 99 00:05:36,380 --> 00:05:40,380 slope, which we will call m. 100 00:05:40,380 --> 00:05:44,830 It's the same thing as the rise over the run, which is 101 00:05:44,830 --> 00:05:48,190 the same thing as the change in y over the change in x. 102 00:05:48,190 --> 00:05:50,070 If you were doing this for your homework, you wouldn't 103 00:05:50,070 --> 00:05:50,870 have to write all this. 104 00:05:50,870 --> 00:05:52,920 I just want to make sure that you understand that these are 105 00:05:52,920 --> 00:05:55,150 all the same things. 106 00:05:55,150 --> 00:05:58,520 Then what is our change in y over change in x? 107 00:05:58,520 --> 00:06:02,280 This is equal to, let's start with this side first. It's just 108 00:06:02,280 --> 00:06:03,980 to show you I could pick either of these points. 109 00:06:03,980 --> 00:06:14,050 So let's say it's 0 minus 5 just like that. 110 00:06:14,050 --> 00:06:17,000 So I'm using this coordinate first. I'm kind of viewing it 111 00:06:17,000 --> 00:06:19,770 as the endpoint. 112 00:06:19,770 --> 00:06:22,420 Remember when I first learned this, I would always be 113 00:06:22,420 --> 00:06:24,160 tempted to do the x in the numerator. 114 00:06:24,160 --> 00:06:25,990 No, you use the y's in the numerator. 115 00:06:25,990 --> 00:06:28,470 So that's the second of the coordinates. 116 00:06:28,470 --> 00:06:38,435 That is going to be over negative 3 minus 3. 117 00:06:41,250 --> 00:06:44,370 This is the coordinate negative 3, 0. 118 00:06:44,370 --> 00:06:46,420 This is the coordinate 3, 5. 119 00:06:46,420 --> 00:06:47,980 We're subtracting that. 120 00:06:47,980 --> 00:06:49,310 So what are we going to get? 121 00:06:49,310 --> 00:06:52,570 This is going to be equal to-- I'll do it in a neutral 122 00:06:52,570 --> 00:06:56,210 color-- this is going to be equal to the numerator is 123 00:06:56,210 --> 00:07:02,010 negative 5 over negative 3 minus 3 is negative 6. 124 00:07:02,010 --> 00:07:03,650 So the negatives cancel out. 125 00:07:03,650 --> 00:07:05,930 You get 5/6. 126 00:07:05,930 --> 00:07:08,700 So we know that the equation is going to be of the form y 127 00:07:08,700 --> 00:07:15,560 is equal to 5/6 x plus b. 128 00:07:15,560 --> 00:07:18,600 Now we can substitute one of these coordinates in for b. 129 00:07:18,600 --> 00:07:19,440 So let's do. 130 00:07:19,440 --> 00:07:21,310 I always like to use the one that has the 0 in it. 131 00:07:21,310 --> 00:07:33,270 So y is a zero when x is negative 3 plus b. 132 00:07:33,270 --> 00:07:37,810 So all I did is I substituted negative 3 for x, 0 for y. 133 00:07:37,810 --> 00:07:40,860 I know I can do that because this is on the line. 134 00:07:40,860 --> 00:07:44,040 This must satisfy the equation of the line. 135 00:07:44,040 --> 00:07:45,600 Let's solve for b. 136 00:07:45,600 --> 00:07:49,990 So we get zero is equal to, well if we divide negative 3 137 00:07:49,990 --> 00:07:51,830 by 3, that becomes a 1. 138 00:07:51,830 --> 00:07:54,890 If you divide 6 by 3, that becomes a 2. 139 00:07:54,890 --> 00:08:02,380 So it becomes negative 5/2 plus b. 140 00:08:02,380 --> 00:08:05,280 We could add 5/2 to both sides of the equation, 141 00:08:05,280 --> 00:08:08,630 plus 5/2, plus 5/2. 142 00:08:08,630 --> 00:08:10,850 I like to change my notation just so you get 143 00:08:10,850 --> 00:08:12,520 familiar with both. 144 00:08:12,520 --> 00:08:17,800 So the equation becomes 5/2 is equal to-- that's a 0-- is 145 00:08:17,800 --> 00:08:19,600 equal to b. 146 00:08:19,600 --> 00:08:22,090 b is 5/2. 147 00:08:22,090 --> 00:08:31,940 So the equation of our line is y is equal to 5/6 x plus b, 148 00:08:31,940 --> 00:08:37,820 which we just figured out is 5/2, plus 5/2. 149 00:08:37,820 --> 00:08:38,710 We are done. 150 00:08:38,710 --> 00:08:41,280 Let's do another one. 151 00:08:41,280 --> 00:08:43,500 We have a graph here. 152 00:08:43,500 --> 00:08:45,300 Let's figure out the equation of this graph. 153 00:08:45,300 --> 00:08:46,900 This is actually, on some level, a little bit easier. 154 00:08:46,900 --> 00:08:47,740 What's the slope? 155 00:08:47,740 --> 00:08:52,250 Slope is change in y over change it x. 156 00:08:52,250 --> 00:08:53,310 So let's see what happens. 157 00:08:53,310 --> 00:08:57,900 When we move in x, when our change in x is 1, so that is 158 00:08:57,900 --> 00:08:58,940 our change in x. 159 00:08:58,940 --> 00:09:00,850 So change in x is 1. 160 00:09:00,850 --> 00:09:04,130 I'm just deciding to change my x by 1, increment by 1. 161 00:09:04,130 --> 00:09:05,900 What is the change in y? 162 00:09:05,900 --> 00:09:10,390 It looks like y changes exactly by 4. 163 00:09:10,390 --> 00:09:14,980 It looks like my delta y, my change in y, is equal to 4 164 00:09:14,980 --> 00:09:20,690 when my delta x is equal to 1. 165 00:09:20,690 --> 00:09:24,340 So change in y over change in x, change in y is 4 when 166 00:09:24,340 --> 00:09:26,220 change in x is 1. 167 00:09:26,220 --> 00:09:30,380 So the slope is equal to 4. 168 00:09:30,380 --> 00:09:32,190 Now what's its y-intercept? 169 00:09:32,190 --> 00:09:33,720 Well here we can just look at the graph. 170 00:09:33,720 --> 00:09:38,260 It looks like it intersects y-axis at y is equal to 171 00:09:38,260 --> 00:09:41,600 negative 6, or at the point 0, negative 6. 172 00:09:41,600 --> 00:09:44,180 So we know that b is equal to negative 6. 173 00:09:46,950 --> 00:09:48,875 So we know the equation of the line. 174 00:09:48,875 --> 00:09:56,630 The equation of the line is y is equal to the slope times x 175 00:09:56,630 --> 00:09:59,030 plus the y-intercept. 176 00:09:59,030 --> 00:10:01,850 I should write that. 177 00:10:01,850 --> 00:10:07,840 So minus 6, that is plus negative 6 So that is the 178 00:10:07,840 --> 00:10:09,800 equation of our line. 179 00:10:09,800 --> 00:10:12,980 Let's do one more of these. 180 00:10:12,980 --> 00:10:17,170 So they tell us that f of 1.5 is negative 3, f of 181 00:10:17,170 --> 00:10:18,750 negative 1 is 2. 182 00:10:18,750 --> 00:10:19,970 What is that? 183 00:10:19,970 --> 00:10:23,830 Well, all this is just a fancy way of telling you that the 184 00:10:23,830 --> 00:10:30,530 point when x is 1.5, when you put 1.5 into the function, the 185 00:10:30,530 --> 00:10:33,490 function evaluates as negative 3. 186 00:10:33,490 --> 00:10:36,750 So this tells us that the coordinate 1.5, negative 3 is 187 00:10:36,750 --> 00:10:38,270 on the line. 188 00:10:38,270 --> 00:10:41,960 Then this tells us that the point when x is negative 1, f 189 00:10:41,960 --> 00:10:44,420 of x is equal to 2. 190 00:10:44,420 --> 00:10:47,540 This is just a fancy way of saying that both of these two 191 00:10:47,540 --> 00:10:51,400 points are on the line, nothing unusual. 192 00:10:51,400 --> 00:10:54,380 I think the point of this problem is to get you familiar 193 00:10:54,380 --> 00:10:56,870 with function notation, for you to not get intimidated if 194 00:10:56,870 --> 00:10:57,970 you see something like this. 195 00:10:57,970 --> 00:11:01,540 If you evaluate the function at 1.5, you get negative 3. 196 00:11:01,540 --> 00:11:04,440 So that's the coordinate if you imagine that y is 197 00:11:04,440 --> 00:11:06,020 equal to f of x. 198 00:11:06,020 --> 00:11:06,950 So this would be the y-coordinate. 199 00:11:06,950 --> 00:11:09,250 It would be equal to negative 3 when x is 1.5. 200 00:11:09,250 --> 00:11:10,840 Anyway, I've said it multiple times. 201 00:11:10,840 --> 00:11:13,280 Let's figure out the slope of this line. 202 00:11:13,280 --> 00:11:20,020 The slope which is change in y over change in x is equal to, 203 00:11:20,020 --> 00:11:27,460 let's start with 2 minus this guy, negative 3-- these are 204 00:11:27,460 --> 00:11:32,880 the y-values-- over, all of that over, negative 205 00:11:32,880 --> 00:11:40,140 1 minus this guy. 206 00:11:40,140 --> 00:11:43,330 Let me write it this way, negative 1 minus 207 00:11:43,330 --> 00:11:48,440 that guy, minus 1.5. 208 00:11:48,440 --> 00:11:50,340 I do the colors because I want to show you that the negative 209 00:11:50,340 --> 00:11:54,060 1 and the 2 are both coming from this, that's why I use 210 00:11:54,060 --> 00:11:57,500 both of them first. If I used these guys first, I would have 211 00:11:57,500 --> 00:12:00,495 to use both the x and the y first. If I use the 2 first, I 212 00:12:00,495 --> 00:12:02,080 have to use the negative 1 first. That's why I'm 213 00:12:02,080 --> 00:12:03,390 color-coding it. 214 00:12:03,390 --> 00:12:08,360 So this is going to be equal to 2 minus negative 3. 215 00:12:08,360 --> 00:12:10,370 That's the same thing as 2 plus 3. 216 00:12:10,370 --> 00:12:11,620 So that is 5. 217 00:12:16,480 --> 00:12:20,040 Negative 1 minus 1.5 is negative 2.5. 218 00:12:23,830 --> 00:12:27,770 5 divided by 2.5 is equal to 2. 219 00:12:27,770 --> 00:12:30,250 So the slope of this line is negative 2. 220 00:12:30,250 --> 00:12:32,130 Actually I'll take a little aside to show you it doesn't 221 00:12:32,130 --> 00:12:34,480 matter what order I do this in. 222 00:12:34,480 --> 00:12:36,180 If I use this coordinate first, then I have to use that 223 00:12:36,180 --> 00:12:38,140 coordinate first. Let's do it the other way. 224 00:12:38,140 --> 00:12:54,180 If I did it as negative 3 minus 2 over 1.5 minus 225 00:12:54,180 --> 00:12:59,810 negative 1, this should be minus the 2 over 1.5 minus the 226 00:12:59,810 --> 00:13:01,060 negative 1. 227 00:13:03,300 --> 00:13:04,780 This should give me the same answer. 228 00:13:04,780 --> 00:13:06,130 This is equal to what? 229 00:13:06,130 --> 00:13:12,860 Negative 3 minus 2 is negative 5 over 1.5 minus negative 1. 230 00:13:12,860 --> 00:13:14,520 That's 1.5 plus 1. 231 00:13:14,520 --> 00:13:16,610 That's over 2.5. 232 00:13:16,610 --> 00:13:18,840 So once again, this is equal the negative 2. 233 00:13:18,840 --> 00:13:20,340 So I just wanted to show you, it doesn't matter which one 234 00:13:20,340 --> 00:13:23,090 you pick as the starting or the endpoint, as long as 235 00:13:23,090 --> 00:13:23,980 you're consistent. 236 00:13:23,980 --> 00:13:26,650 If this is the starting y, this is the starting x. 237 00:13:26,650 --> 00:13:28,370 If this is the finishing y, this has to be 238 00:13:28,370 --> 00:13:29,500 the finishing x. 239 00:13:29,500 --> 00:13:33,100 But anyway, we know that the slope is negative 2. 240 00:13:33,100 --> 00:13:36,540 So we know the equation is y is equal to negative 2x plus 241 00:13:36,540 --> 00:13:39,170 some y-intercept. 242 00:13:39,170 --> 00:13:40,720 Let's use one of these coordinates. 243 00:13:40,720 --> 00:13:43,430 I'll use this one since it doesn't have a decimal in it. 244 00:13:43,430 --> 00:13:47,450 So we know that y is equal to 2. 245 00:13:47,450 --> 00:13:52,630 So y is equal to 2 when x is equal to negative 1. 246 00:13:55,140 --> 00:13:57,290 Of course you have your plus b. 247 00:13:57,290 --> 00:14:02,710 So 2 is equal to negative 2 times negative 1 is 2 plus b. 248 00:14:02,710 --> 00:14:06,390 If you subtract 2 from both sides of this equation, minus 249 00:14:06,390 --> 00:14:10,370 2, minus 2, you're subtracting it from both sides of this 250 00:14:10,370 --> 00:14:12,480 equation, you're going to get 0 on the left-hand side is 251 00:14:12,480 --> 00:14:14,520 equal to b. 252 00:14:14,520 --> 00:14:15,670 So b is 0. 253 00:14:15,670 --> 00:14:18,430 So the equation of our line is just y is 254 00:14:18,430 --> 00:14:19,680 equal to negative 2x. 255 00:14:22,040 --> 00:14:23,870 Actually if you wanted to write it in function notation, 256 00:14:23,870 --> 00:14:28,190 it would be that f of x is equal to negative 2x. 257 00:14:28,190 --> 00:14:30,810 I kind of just assumed that y is equal to f of x. 258 00:14:30,810 --> 00:14:32,420 But this is really the equation. 259 00:14:32,420 --> 00:14:33,990 They never mentioned y's here. 260 00:14:33,990 --> 00:14:37,890 So you could just write f of x is equal to 2x right here. 261 00:14:37,890 --> 00:14:40,190 Each of these coordinates are the coordinates 262 00:14:40,190 --> 00:14:42,610 of x and f of x. 263 00:14:46,960 --> 00:14:49,960 So you could even view the definition of slope as change 264 00:14:49,960 --> 00:14:53,320 in f of x over change in x. 265 00:14:53,320 --> 00:14:57,090 These are all equivalent ways of viewing the same thing.