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Graphs of rational functions: horizontal asymptote | Algebra II | High School Math | Khan Academy

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    - [Voiceover] Let f of x
    equal negative x squared
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    plus a x plus b
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    over x squared plus c x plus d
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    where a, b, c, and d
    are unknown constants.
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    Which of the following is a possible graph
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    of y is equal to f of x?
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    And they told us dashed
    lines indicate asymptotes.
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    So this is really interesting here.
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    And they gave us four choices.
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    We see four of them,
    three of them right now.
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    Then if I scroll over bit over,
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    you can see choice D.
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    And so I encourage you to pause the video
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    and think about how we can figure it out
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    because it is interesting
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    because they haven't
    given us a lot of details.
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    They haven't given us
    what these coefficients
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    or these constants are going to be.
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    All right, now let's think about it.
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    So one thing we could think about is
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    horizontal asymptotes.
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    So let's think about what happens
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    as x approaches positive
    or negative infinity.
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    Well, as x, so as x approaches
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    infinity or x approaches
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    negative infinity, f of x.
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    F of x is going to be
    approximately equal to.
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    Well, we're going to look
    at the highest degree terms
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    because these are going to dominate
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    as the magnitude of x,
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    the absolute value of
    x becomes very large.
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    So f of x is going to be
    approximately negative x squared
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    over x squared which is equal to negative
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    or we could another way to think about it.
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    This is the same thing as negative one.
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    So f of x is going to approach,
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    f of x is going to approach negative one.
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    In either direction, as
    x approaches infinity
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    or x approaches negative infinity.
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    So we have a horizontal asymptote
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    at y equals negative one.
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    Let's see, choice A here,
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    it does look like they
    have a horizontal asymptote
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    at y is equal to negative one
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    right over there.
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    And we can verify that
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    because each hash mark is two.
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    We go from two to zero
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    to negative two to negative four.
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    So this does look like
    it's a negative one.
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    So just based only on
    the horizontal asymptote,
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    choice A looks good.
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    Choice B, we have a horizontal asymptote
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    at y is equal to positive two.
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    So we can rule that out.
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    We know that a horizontal asymptote
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    as x approaches positive
    or negative infinity
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    is at negative one,
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    y equals negative one.
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    Here, our horizontal asymptote is
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    at y is equal to zero.
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    The graph approaches,
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    it approaches the x axis
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    from either above or below.
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    So it's not the horizontal asymptote.
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    It's not y equals negative one.
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    So we can rule that one out.
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    And then similarly, over here,
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    our horizontal asymptote is
    not y equals negative one.
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    Our horizontal asymptote
    is y is equal to zero
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    so we can rule that one out.
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    And that makes sense
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    because really they only
    gave us enough information
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    to figure out the horizontal asymptote.
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    They didn't give us enough information
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    to figure out how many roots
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    or what happens in the interval
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    and all of those types of things.
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    How many zeros and all that
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    because we don't know what the actual
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    coefficients or constants
    of the quadratic are.
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    All we know is what happens as
    the x squared terms dominate.
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    This thing is going to
    approach negative one.
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    And so we picked choice A.
Title:
Graphs of rational functions: horizontal asymptote | Algebra II | High School Math | Khan Academy
Description:

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Video Language:
English
Team:
Khan Academy
Duration:
03:16

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