-
Let's see if we
can give ourselves
-
an intuitive understanding
of the mean value theorem.
-
And as we'll see, once you parse
some of the mathematical lingo
-
and notation, it's actually
a quite intuitive theorem.
-
And so let's just think
about some function, f.
-
So let's say I have
some function f.
-
And we know a few things
about this function.
-
We know that it is
continuous over the closed
-
interval between x equals
a and x is equal to b.
-
And so when we put
these brackets here,
-
that just means closed interval.
-
So when I put a
bracket here, that
-
means we're including
the point a.
-
And if I put the bracket on
the right hand side instead
-
of a parentheses,
that means that we
-
are including the point b.
-
And continuous
just means we don't
-
have any gaps or jumps in
the function over this closed
-
interval.
-
Now, let's also assume that
it's differentiable over
-
the open interval
between a and b.
-
So now we're saying,
well, it's OK
-
if it's not
differentiable right at a,
-
or if it's not
differentiable right at b.
-
And differentiable
just means that there's
-
a defined derivative,
that you can actually
-
take the derivative
at those points.
-
So it's differentiable over the
open interval between a and b.
-
So those are the
constraints we're
-
going to put on ourselves
for the mean value theorem.
-
And so let's just try
to visualize this thing.
-
So this is my function,
that's the y-axis.
-
And then this right
over here is the x-axis.
-
And I'm going to--
let's see, x-axis,
-
and let me draw my interval.
-
So that's a, and then
this is b right over here.
-
And so let's say our function
looks something like this.
-
Draw an arbitrary
function right over here,
-
let's say my function
looks something like that.
-
So at this point right over
here, the x value is a,
-
and the y value is f(a).
-
At this point right
over here, the x value
-
is b, and the y value,
of course, is f(b).
-
So all the mean
value theorem tells
-
us is if we take the
average rate of change
-
over the interval,
that at some point
-
the instantaneous rate
of change, at least
-
at some point in
this open interval,
-
the instantaneous
change is going
-
to be the same as
the average change.
-
Now what does that
mean, visually?
-
So let's calculate
the average change.
-
The average change between
point a and point b,
-
well, that's going to be the
slope of the secant line.
-
So that's-- so this
is the secant line.
-
So think about its slope.
-
All the mean value
theorem tells us
-
is that at some point
in this interval,
-
the instant slope
of the tangent line
-
is going to be the same as
the slope of the secant line.
-
And we can see, just visually,
it looks like right over here,
-
the slope of the tangent line
is it looks like the same
-
as the slope of the secant line.
-
It also looks like the
case right over here.
-
The slope of the tangent
line is equal to the slope
-
of the secant line.
-
And it makes intuitive sense.
-
At some point, your
instantaneous slope
-
is going to be the same
as the average slope.
-
Now how would we write
that mathematically?
-
Well, let's calculate
the average slope
-
over this interval.
-
Well, the average slope
over this interval,
-
or the average change, the
slope of the secant line,
-
is going to be our change
in y-- our change in y
-
right over here--
over our change in x.
-
Well, what is our change in y?
-
Our change in y is
f(b) minus f(a),
-
and that's going to be
over our change in x.
-
Over b minus b minus a.
-
I'll do that in that red color.
-
So let's just remind ourselves
what's going on here.
-
So this right over here,
this is the graph of y
-
is equal to f(x).
-
We're saying that the
slope of the secant line,
-
or our average rate of change
over the interval from a to b,
-
is our change in y-- that the
Greek letter delta is just
-
shorthand for change in
y-- over our change in x.
-
Which, of course,
is equal to this.
-
And the mean value
theorem tells us
-
that there exists-- so
if we know these two
-
things about the
function, then there
-
exists some x value
in between a and b.
-
So in the open interval between
a and b, there exists some c.
-
There exists some
c, and we could
-
say it's a member of the open
interval between a and b.
-
Or we could say some c
such that a is less than c,
-
which is less than b.
-
So some c in this interval.
-
So some c in between it
where the instantaneous rate
-
of change at that
x value is the same
-
as the average rate of change.
-
So there exists some c
in this open interval
-
where the average
rate of change is
-
equal to the instantaneous
rate of change at that point.
-
That's all it's saying.
-
And as we saw this diagram right
over here, this could be our c.
-
Or this could be our c as well.
-
So nothing really--
it looks, you
-
would say f is continuous over
a, b, differentiable over-- f
-
is continuous over the closed
interval, differentiable
-
over the open interval, and
you see all this notation.
-
You're like, what
is that telling us?
-
All it's saying is at some
point in the interval,
-
the instantaneous
rate of change is
-
going to be the same as
the average rate of change
-
over the whole interval.
-
In the next video,
we'll try to give you
-
a kind of a real life example
about when that make sense.