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I have three word problems here.
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And what I want to
do in this video
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is not solve the word problems
but just set up the equation
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that we could solve to get the
answer to the word problems.
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And essentially, we're
going to be setting up
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proportions in either case.
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So in this first problem, we
have 9 markers cost $11.50.
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And then they ask us, how
much would 7 markers cost?
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And let's just set x to
be equal to our answer.
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So x is equal to the
cost of 7 markers.
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So the way to solve
a problem like this
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is to set up two ratios and then
set them equal to each other.
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So you could say that the ratio
of 9 markers to the cost of 9
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markers, so the ratio of
the number of markers, so 9,
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to the cost of the
9 markers, to 11.50,
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this should be equal to
the ratio of our new number
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of markers, 7, to whatever
the cost of the 7 markers are,
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to x.
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Let me do x in green.
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So this is a completely
valid proportion here.
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The ratio of 9 markers
to the cost of 9 markers
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is equal to 7 markers to
the cost of 7 markers.
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And then you could
solve this to figure out
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how much those 7
markers would cost.
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And you could flip
both sides of this,
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and it would still be a
completely valid ratio.
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You could have 11.50 to 9.
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The ratio between the cost
of the markers to the number
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of markers you're
buying, 11.50 to 9,
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is equal to the ratio of the
cost of 7 markers to the number
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of markers, which
is obviously 7.
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So all I would do is flip
both sides of this equation
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right here to get
this one over here.
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You could also think about
the ratios in other ways.
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You could say that the ratio
of 9 markers to 7 markers
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is going to be the same as
the ratio of their costs,
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is going to be equal to the
ratio of the cost of 9 markers
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to the cost of 7 markers.
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And then, obviously, you could
flip both of these sides.
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Let me do that in the
same magenta color.
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The ratio of 7
markers to 9 markers
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is the same thing as
the ratio of the cost
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of 7 markers to the
cost of 9 markers.
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So that is 11.50.
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So all of these would be valid
proportions, valid equations
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that describe what's
going on here.
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And then you would just have
to essentially solve for x.
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So let's do this
one right over here.
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7 apples cost $5.
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How many apples can
I buy it with $8?
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So one again, we're going to
assume that what they're asking
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is how many apples--
let's call that x.
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x is what we want to solve for.
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So 7 apples costs $5.
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So we have the ratio between
the number of apples, 7,
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and the cost of
the apples, 5, is
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going to be equal to the
ratio between another number
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of apples, which is now x, and
the cost of that other number
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of apples.
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And it's going to be $8.
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And so notice here in this first
situation, what was unknown
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was the cost.
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So we kind of had
the number of apples
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to cost, the number
of apples to cost.
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Now in this example, the
unknown is the number of apples,
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so number of apples to cost,
number of apples to cost.
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And we could do all of the
different scenarios like this.
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You could also say the
ratio between 7 apples
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and x apples is
going to be the same
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as the ratio between
the cost of 7 apples
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and the cost of 8 apples.
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Obviously, you can
flip both sides
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of these in either
of these equations
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to get two more equations.
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And any of these would
be valid equations.
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Now let's do this last one.
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I'll use new colors here.
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A cake recipe for 5
people requires 2 eggs.
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So we want to know how many
eggs-- so this we'll call x.
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And you don't always
have to call it x.
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You could call it e for eggs.
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Well, e isn't a good
idea, because e represents
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another number once you
get to higher mathematics.
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But you could call them y
or z or any variable-- a,
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b, or c, anything.
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How many eggs do we need
for a 15-person cake?
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So you could say the ratio of
people to eggs is constant.
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So if we have 5 people for
2 eggs, then for 15 people,
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we are going to need x eggs.
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This ratio is going
to be constant.
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5/2 is equal to 15/x.
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Or you could flip
both sides of this.
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Or you could say the
ratio between 5 and 15
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is going to be equal to the
ratio between the number
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of eggs for 5 people-- let me
do that in that blue color--
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and the number of
eggs for 15 people.
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And obviously, you could flip
both sides of this equation.
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So all of these,
we've essentially
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set up the proportions
that describe
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each of these problems.
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And then you can
go later and solve
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for x to actually
get the answer.