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Airbus A380 Take-off Distance

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    In the last video,
    we figured out
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    that given a takeoff velocity
    of 280 kilometers per hour--
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    and if we have a positive
    value for any of these vectors,
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    we assume it's in the forward
    direction for the runway--
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    given this takeoff velocity,
    and a constant acceleration of 1
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    meter per second per second,
    or 1 meter per second squared,
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    we figured out that it
    would take an Airbus
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    A380 about 78
    seconds to take off.
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    What I want to figure
    out in this video
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    is, given all of these
    numbers, how long of a runaway
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    does it need, which is a very
    important question if you want
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    to build a runway that
    can at least allow
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    Airbus A380s to take off.
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    And you probably want it to
    be a little bit longer than
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    that just in case it takes a
    little bit longer than expected
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    to take off.
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    But what is the minimum
    length of the runway
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    given these numbers?
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    So we want to figure
    out the displacement,
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    or how far does
    this plane travel
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    as it is accelerating at
    1 meter per second squared
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    to 280 kilometers per
    hour, or to 78-- or where
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    did I write it
    over here-- to 78.
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    I converted it right over here.
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    As it accelerates to
    78 meters per second,
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    how much land does
    this thing cover?
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    So let's call this,
    the displacement
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    is going to be equal
    to-- So displacement
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    is equal to-- You could view
    it as velocity times time.
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    But the velocity
    here is changing.
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    If we just had a constant
    velocity for this entire time,
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    we could just multiply
    that times however
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    long it's traveling, and it
    would give us the displacement.
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    But here our
    velocity is changing.
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    But lucky for us,
    we learned-- and I
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    encourage you to watch the video
    on why distance, or actually
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    the video on average velocity
    for constant acceleration--
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    but if you have
    constant acceleration,
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    and that is what we are
    assuming in this example--
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    so if you assume that your
    acceleration is constant,
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    then you can come
    up with something
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    called an average velocity.
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    And the average velocity, if
    your acceleration is constant,
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    if and only if your
    acceleration is constant, then
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    your average velocity
    will be the average
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    of your final velocity
    and your initial velocity.
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    And so in this situation,
    what is our average velocity?
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    Well, our average
    velocity-- let's
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    do it in meters per
    second-- is going
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    to be our final velocity,
    which is-- let me calculate it
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    down here.
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    So our average velocity
    in this example
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    is going to be our
    final velocity, which
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    is 78 meters per second,
    plus our initial velocity.
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    Well, what's our
    initial velocity?
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    We're assuming we're
    starting at a standstill.
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    Plus 0, all of that over 2.
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    So our average velocity in this
    situation, 78 divided by 2,
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    is 39 meters per second.
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    And the value of an average
    velocity in this situation--
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    actually, average velocity
    in any situation--
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    but in this situation, we
    can calculate it this way.
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    But the value of
    an average velocity
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    is we can figure
    out our displacement
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    by multiplying our average
    velocity times the time that
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    goes by, times the
    change in time.
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    So we know the change
    in time is 78 seconds.
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    We know our average
    velocity here
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    is 39 meters per second,
    just the average of 0 and 78,
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    39 meters per second.
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    Another way to think
    about it, if you want
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    think about the
    distance traveled,
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    this plane is
    constantly accelerating.
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    So let me draw a
    little graph here.
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    This plane's velocity time graph
    would look something like this.
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    So if this is time and this
    is velocity right over here,
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    this plane has a
    constant acceleration
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    starting with 0 velocity.
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    It has a constant acceleration.
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    This slope right here is
    constant acceleration.
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    It should actually
    be a slope of 1,
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    given the numbers
    in this example.
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    And the distance traveled
    is the distance that
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    is the area under this
    curve up to 78 seconds,
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    because that's how long it
    takes for it to take off.
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    So the distance traveled is
    this area right over here, which
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    we cover in another video, or
    we give you the intuition of why
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    that works and why distance is
    area under a velocity timeline.
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    But what an average velocity
    is, is some velocity,
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    and in this case, it's exactly
    right in between our final
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    and our initial
    velocities, that if you
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    take that average velocity
    for the same amount of time,
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    you would get the exact
    same area under the curve,
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    or you would get the
    exact same distance.
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    So our average
    velocity is 39 meters
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    per second times 78 seconds.
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    And let's just get our
    calculator out for this.
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    We have 39 times
    78 gives us 3,042.
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    So this gives us 3,042.
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    And then meters per second
    times second just leaves us
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    with meters.
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    So you need a runway
    of over 3,000 meters
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    for one of these
    suckers to take off,
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    or over 3 kilometers, which is
    like about 1.8 or 1.9 miles,
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    just for this guy
    to take off, which
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    I think is pretty fascinating.
Title:
Airbus A380 Take-off Distance
Description:

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Video Language:
English
Duration:
05:29
dhbot edited English subtitles for Airbus A380 Take-off Distance
dhbot edited English subtitles for Airbus A380 Take-off Distance
Cearo Willow added a translation

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