WEBVTT 00:00:00.810 --> 00:00:02.500 In the last video, we figured out 00:00:02.500 --> 00:00:06.875 that given a takeoff velocity of 280 kilometers per hour-- 00:00:06.875 --> 00:00:09.250 and if we have a positive value for any of these vectors, 00:00:09.250 --> 00:00:12.580 we assume it's in the forward direction for the runway-- 00:00:12.580 --> 00:00:16.860 given this takeoff velocity, and a constant acceleration of 1 00:00:16.860 --> 00:00:20.260 meter per second per second, or 1 meter per second squared, 00:00:20.260 --> 00:00:22.380 we figured out that it would take an Airbus 00:00:22.380 --> 00:00:28.240 A380 about 78 seconds to take off. 00:00:28.240 --> 00:00:30.020 What I want to figure out in this video 00:00:30.020 --> 00:00:33.110 is, given all of these numbers, how long of a runaway 00:00:33.110 --> 00:00:36.080 does it need, which is a very important question if you want 00:00:36.080 --> 00:00:39.020 to build a runway that can at least allow 00:00:39.020 --> 00:00:40.699 Airbus A380s to take off. 00:00:40.699 --> 00:00:42.990 And you probably want it to be a little bit longer than 00:00:42.990 --> 00:00:45.300 that just in case it takes a little bit longer than expected 00:00:45.300 --> 00:00:45.890 to take off. 00:00:45.890 --> 00:00:48.350 But what is the minimum length of the runway 00:00:48.350 --> 00:00:51.450 given these numbers? 00:00:51.450 --> 00:00:53.870 So we want to figure out the displacement, 00:00:53.870 --> 00:00:57.230 or how far does this plane travel 00:00:57.230 --> 00:01:00.220 as it is accelerating at 1 meter per second squared 00:01:00.220 --> 00:01:05.150 to 280 kilometers per hour, or to 78-- or where 00:01:05.150 --> 00:01:07.630 did I write it over here-- to 78. 00:01:07.630 --> 00:01:10.840 I converted it right over here. 00:01:14.930 --> 00:01:17.410 As it accelerates to 78 meters per second, 00:01:17.410 --> 00:01:21.430 how much land does this thing cover? 00:01:21.430 --> 00:01:23.940 So let's call this, the displacement 00:01:23.940 --> 00:01:26.760 is going to be equal to-- So displacement 00:01:26.760 --> 00:01:31.760 is equal to-- You could view it as velocity times time. 00:01:31.760 --> 00:01:34.490 But the velocity here is changing. 00:01:34.490 --> 00:01:37.110 If we just had a constant velocity for this entire time, 00:01:37.110 --> 00:01:39.230 we could just multiply that times however 00:01:39.230 --> 00:01:41.710 long it's traveling, and it would give us the displacement. 00:01:41.710 --> 00:01:44.000 But here our velocity is changing. 00:01:44.000 --> 00:01:46.740 But lucky for us, we learned-- and I 00:01:46.740 --> 00:01:50.880 encourage you to watch the video on why distance, or actually 00:01:50.880 --> 00:01:54.370 the video on average velocity for constant acceleration-- 00:01:54.370 --> 00:01:57.510 but if you have constant acceleration, 00:01:57.510 --> 00:02:02.600 and that is what we are assuming in this example-- 00:02:02.600 --> 00:02:06.572 so if you assume that your acceleration is constant, 00:02:06.572 --> 00:02:08.030 then you can come up with something 00:02:08.030 --> 00:02:10.030 called an average velocity. 00:02:10.030 --> 00:02:13.210 And the average velocity, if your acceleration is constant, 00:02:13.210 --> 00:02:16.420 if and only if your acceleration is constant, then 00:02:16.420 --> 00:02:20.020 your average velocity will be the average 00:02:20.020 --> 00:02:23.740 of your final velocity and your initial velocity. 00:02:23.740 --> 00:02:27.234 And so in this situation, what is our average velocity? 00:02:27.234 --> 00:02:28.650 Well, our average velocity-- let's 00:02:28.650 --> 00:02:30.320 do it in meters per second-- is going 00:02:30.320 --> 00:02:32.880 to be our final velocity, which is-- let me calculate it 00:02:32.880 --> 00:02:34.450 down here. 00:02:34.450 --> 00:02:38.814 So our average velocity in this example 00:02:38.814 --> 00:02:40.480 is going to be our final velocity, which 00:02:40.480 --> 00:02:45.444 is 78 meters per second, plus our initial velocity. 00:02:45.444 --> 00:02:46.860 Well, what's our initial velocity? 00:02:46.860 --> 00:02:48.870 We're assuming we're starting at a standstill. 00:02:48.870 --> 00:02:52.330 Plus 0, all of that over 2. 00:02:52.330 --> 00:02:56.180 So our average velocity in this situation, 78 divided by 2, 00:02:56.180 --> 00:02:59.480 is 39 meters per second. 00:02:59.480 --> 00:03:03.780 And the value of an average velocity in this situation-- 00:03:03.780 --> 00:03:06.590 actually, average velocity in any situation-- 00:03:06.590 --> 00:03:08.800 but in this situation, we can calculate it this way. 00:03:08.800 --> 00:03:10.300 But the value of an average velocity 00:03:10.300 --> 00:03:12.400 is we can figure out our displacement 00:03:12.400 --> 00:03:21.020 by multiplying our average velocity times the time that 00:03:21.020 --> 00:03:24.340 goes by, times the change in time. 00:03:24.340 --> 00:03:28.190 So we know the change in time is 78 seconds. 00:03:28.190 --> 00:03:30.260 We know our average velocity here 00:03:30.260 --> 00:03:37.100 is 39 meters per second, just the average of 0 and 78, 00:03:37.100 --> 00:03:38.770 39 meters per second. 00:03:38.770 --> 00:03:41.020 Another way to think about it, if you want 00:03:41.020 --> 00:03:42.580 think about the distance traveled, 00:03:42.580 --> 00:03:44.590 this plane is constantly accelerating. 00:03:44.590 --> 00:03:48.350 So let me draw a little graph here. 00:03:48.350 --> 00:03:52.370 This plane's velocity time graph would look something like this. 00:03:52.370 --> 00:03:56.480 So if this is time and this is velocity right over here, 00:03:56.480 --> 00:03:58.280 this plane has a constant acceleration 00:03:58.280 --> 00:03:59.510 starting with 0 velocity. 00:03:59.510 --> 00:04:01.540 It has a constant acceleration. 00:04:01.540 --> 00:04:03.962 This slope right here is constant acceleration. 00:04:03.962 --> 00:04:05.420 It should actually be a slope of 1, 00:04:05.420 --> 00:04:07.260 given the numbers in this example. 00:04:07.260 --> 00:04:10.180 And the distance traveled is the distance that 00:04:10.180 --> 00:04:13.300 is the area under this curve up to 78 seconds, 00:04:13.300 --> 00:04:16.170 because that's how long it takes for it to take off. 00:04:16.170 --> 00:04:19.700 So the distance traveled is this area right over here, which 00:04:19.700 --> 00:04:22.630 we cover in another video, or we give you the intuition of why 00:04:22.630 --> 00:04:26.640 that works and why distance is area under a velocity timeline. 00:04:26.640 --> 00:04:31.350 But what an average velocity is, is some velocity, 00:04:31.350 --> 00:04:34.930 and in this case, it's exactly right in between our final 00:04:34.930 --> 00:04:36.700 and our initial velocities, that if you 00:04:36.700 --> 00:04:39.520 take that average velocity for the same amount of time, 00:04:39.520 --> 00:04:44.540 you would get the exact same area under the curve, 00:04:44.540 --> 00:04:47.060 or you would get the exact same distance. 00:04:47.060 --> 00:04:48.980 So our average velocity is 39 meters 00:04:48.980 --> 00:04:51.290 per second times 78 seconds. 00:04:51.290 --> 00:04:55.640 And let's just get our calculator out for this. 00:04:55.640 --> 00:05:04.220 We have 39 times 78 gives us 3,042. 00:05:04.220 --> 00:05:07.600 So this gives us 3,042. 00:05:07.600 --> 00:05:10.010 And then meters per second times second just leaves us 00:05:10.010 --> 00:05:11.580 with meters. 00:05:11.580 --> 00:05:16.030 So you need a runway of over 3,000 meters 00:05:16.030 --> 00:05:18.000 for one of these suckers to take off, 00:05:18.000 --> 00:05:24.030 or over 3 kilometers, which is like about 1.8 or 1.9 miles, 00:05:24.030 --> 00:05:25.990 just for this guy to take off, which 00:05:25.990 --> 00:05:28.525 I think is pretty fascinating.