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- [Voiceover] Today we
are going to be talking
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about the Reaction Quotient, Q.
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In this video, I'm going to go over,
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how you calculate Q and how you use it.
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We're gonna start with
and example reaction
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between sulfur dioxide,
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S02 gas,
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which will react with oxygen gas,
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and this is a reversible reaction
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that makes
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sulfur trioxide
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or SO3.
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We should make sure this
is a balanced reaction.
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We have two sulfur dioxdes
reacting with one O2
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to give
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2S03.
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At equilibrium we can calculate
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the equilibrium constant, Kc.
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So, at equilibrium
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we know the concentrations
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should be constant because the rate of the
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forward and backward
reactions are the same.
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And if we plug those concentrations in
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to this expression, we will get Kc.
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So,
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Kc is
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the product concentration raised
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to the second power so that's from
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this stoichiometric coefficient.
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And then our reactant concentrations,
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so S02
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squared
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and the concentration of O2.
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So we know at some temperature,
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if you plug in the
equilibrium concentrations,
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Kc is equal to 4.3.
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But what if we're interested in looking
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at the reaction and it's not
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at equilibrium yet or
maybe we just don't know
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if it's at equilibrium.
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In that case,
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when you're not sure it's
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at equilibrium or really at any point
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in your reaction or any time,
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we can calculate the Reaction Quotient, Q.
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So Qc
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is equal to
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the concentration of our product
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squared,
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so the concentration of the product
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raised to
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the stoichiometric coefficient
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times the reactant concentrations,
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also raised to their
stoichiometric coefficients.
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So S02 squared
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and O2.
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So you may be wondering at this point,
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what's the difference?
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The equation for Qc and Kc will
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always look exactly the same
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and the main difference
is when you use them.
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The equilibrium constant K you calculate
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only with the equilibrium concentrations.
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So the c means everything
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is in terms of the molar concentration.
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And for the reaction quotient, Q,
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again everything is in terms of molar
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concentration but we can calculate it
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with any concentrations and we don't
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have to be at equilibrium.
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Molar concentration...
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So let's calculate this
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for a set of example concentrations.
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At some point in our reaction we have
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the following concentrations.
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We have 0.10
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molar
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S02,
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0.30
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molar
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O2,
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and 3.5
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molar of our product.
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So if we plug these numbers into
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our expression for Qc,
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we get
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3.5 molar
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squared
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in the numerator
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and 0.10 squared
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times 0.3
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in the denominator.
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So if I plug this into my calculator,
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I get that Qc
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with this set of concentrations
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is 4,083.
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So now we know how to calculate Qc.
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So next we're going to talk about
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what it tells you.
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So there are three possible scenarios.
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So when Q
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is equal to K,
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that tells us we're at equilibrium.
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So, if at any point you're not sure
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if your concentrations are the
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equilibrium concentrations,
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you can calculate Q
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and check if it's equal to K.
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And in this case, it's not.
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So the other two possibilities are
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that Q is greater than K,
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which is the case here.
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Or Q can be less than K.
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So let's go through both
of those possibilities.
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We can draw all of the
possible values of Q
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on a number line
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or a Q line.
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So Q can have values anywhere
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from zero
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to infinity.
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When you have no product
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your numerator is zero
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and Q is equal to zero.
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So that tells us
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Q equals zero
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when you have all reactants
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and no products.
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And then if you have no reactants left
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and all products,
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we have zero in the denominator
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and that gives us a Q value of infinity.
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So that means at Q equals infinity,
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we have all products.
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Then we have a bunch of values in between.
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And I'm gonna just write
some intermediate values
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in here
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but the actual intermediate values here
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aren't super important.
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We're mostly gonna wanna
compare the relative
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values of our Q and K.
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So Q here is equal to 4,083,
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which I will place
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right around here.
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So that's Qc
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and our K
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in yellow
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is 4.3.
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So we'll place that right around here.
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So we can see that
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our Q is larger than K
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and it's closer to having all products.
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At the concentrations we have up here,
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we have way more products than we should
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at equilibrium.
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So our reaction is gonna try to adjust
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the concentrations to get to equilibrium.
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And what that means in
terms of our number line
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is that our concentrations are gonna shift
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so that Q can get closer to K.
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Since our shift is to the right,
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and it's moving towards all reactants,
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our reaction is going to favor reactants
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to get to equilibrium.
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So when Q is greater than K, like here,
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we're going to favor
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reactants...
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reactants.
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And then the last scenario
when Q is less than K
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our reaction will
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favor products.
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And we can show that
also on our number line.
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If we had a different
set of concentrations,
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where Q was less than K,
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which I will show
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using this color here.
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If we had, say, a Q value around here
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then our shift would be
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to the right
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towards making more products
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and therefore that would mean our reaction
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is gonna try to reach equilibrium
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by favoring the forward reaction.
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So that's how you calculate
Q and how you use it
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to see how the reaction concentrations
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will shift to get to equilibrium.
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In our next video, we'll go over
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an example problem using Q and trying
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to figure out how the
reactant concentrations
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will shift for another reaction.