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Unit Circle Definition of Trig Functions

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    Hello.
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    Well, welcome to the next
    presentation in the
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    trigonometry modules.
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    Just to start off a little
    bit, let's review what
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    we've done so far.
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    In the last couple modules, we
    learned the definitions-- or at
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    least, I guess, we could call
    it a partial definition-- of
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    the sine, the cosine, and
    the tangent functions.
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    And the mnemonic we used to
    memorize that was sohcahtoa.
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    Let me write that down.
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    Sohcahtoa.
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    And what that told us is, let's
    say we had a right triangle.
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    Let me draw a right triangle.
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    This is a right angle here.
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    This is the hypotenuse.
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    Let me label the hypotenuse, h.
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    Let me label this-- and so we
    want to figure out, we want to
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    use this angle right here.
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    Theta, we'll call this theta.
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    Whatever.
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    Then this is the adjacent side,
    and this is the opposite side.
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    And that's an o.
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    So soh tells us that sine
    is equal to opposite
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    over hypotenuse.
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    Cosine is equal to
    adjacent over hypotenuse.
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    And tangent is equal to
    opposite over adjacent.
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    And I think, by this point--
    and especially if you did some
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    of the exercises on the Khan
    Academy-- that should be second
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    nature and should make
    a lot of sense to you.
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    But this definition, using a
    right triangle like this,
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    actually breaks down
    at certain points.
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    Actually, at a lot of points.
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    For example, what happens
    as this angle right here
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    approaches 90 degrees?
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    You can't have two 90
    degree angles in a right
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    triangle, can you?
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    Then it would be like a
    rectangle or something.
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    But you could actually probably
    figure out what happens as
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    it approaches 90 degrees.
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    But the definition, this
    definition, breaks
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    down for that.
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    Also, what happens if
    this angle is negative?
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    Or what happens if this angle
    is more than 90 degrees?
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    Or what happens if
    it's 800 degrees?
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    Or you know, 8 pi radians?
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    Not that 800 and 8 pi
    radians are the same thing.
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    But obviously, this definition
    starts to break down.
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    Because we couldn't even
    draw a right triangle that
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    has those properties.
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    So now I'm going to introduce
    you to an extension
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    of this definition.
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    It's really the same thing, but
    it allows the sine, the cosine,
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    and the tangent functions to be
    defined for angles greater than
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    or equal to pi over 2, or 90
    degrees, or less than 0.
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    So let's draw a unit circle.
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    So this is just the coordinate
    axis, and here is a
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    circle of radius 1.
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    And let's make-- let me see.
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    Let me make sure I'm using
    the correct pen tool.
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    OK.
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    So let's call this right
    here-- so this is theta.
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    This is an angle, right?
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    Between the x-axis and this
    line I just drew here.
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    And this is a radius, right?
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    And we said that this
    has a radius 1.
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    So the length of this
    line is 1, right?
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    Because it just goes
    from the origin to the
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    outside of the circle.
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    So it has a radius of 1.
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    And now I'm going to draw
    a right triangle again.
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    Let me just drop a
    line from here.
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    So there I have a
    right triangle.
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    So if we use the old
    definition we learned before.
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    Let's just focus
    on sine for now.
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    So sine is equal to
    opposite over hypotenuse.
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    Let's apply that to this
    right triangle right here.
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    This is the right angle.
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    So what's the opposite
    angle of this?
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    What's the opposite
    side from this angle?
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    I'm going to change to yellow.
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    It's this side, right?
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    This is the opposite side.
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    And what's the hypotenuse?
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    The hypotenuse is just
    this radius, right?
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    And let's just say that this
    point, where it intersects
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    the circle-- let's call this
    point right here x comma y.
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    So what's the height of
    this opposite side?
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    Well, it's y, right?
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    Because it's just the
    height of that point.
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    This is of height y.
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    So sine of this angle right
    here, sine of theta, is
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    going to equal the opposite
    side-- which is this yellow
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    side, which is just the
    y-coordinate-- is going to
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    equal y over the hypotenuse.
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    The hypotenuse is
    this pink side here.
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    And what's the length
    of the hypotenuse?
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    Well, it's the radius
    of this unit circle.
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    So it's 1.
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    And y divided by 1?
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    Well, that's just y.
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    So we see that sine of
    theta is equal to y.
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    Let's do the same thing
    for cosine of theta.
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    Well, we know that cosine
    is equal to adjacent
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    over hypotenuse.
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    Well, what's the
    adjacent side here?
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    I'm running out of colors.
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    The adjacent side is this
    bottom side, right here.
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    So that would equal-- so
    if I said-- I'm running
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    out of space, too.
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    Cosine of theta would equal
    this gray side-- which is
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    the adjacent side--
    and what is that?
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    What is this length?
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    What is the length
    of this side?
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    Well, it's just x, right?
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    If this is the point x, y then
    this distance here is x and we
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    already learned this distance--
    or we already observed--
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    that this distance is y.
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    So this distance being
    just x, we know that the
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    adjacent length is x.
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    So we say cosine of theta is
    equal to x over the hypotenuse.
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    And once again, the
    hypotenuse is 1.
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    So cosine of theta
    is equal to x.
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    I know what you're thinking.
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    Sal, that's very nice and cute.
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    Cosine of theta equals x,
    sine of theta equals y.
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    But how is this really
    different from what we
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    were doing before?
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    Well, if I define it this way,
    now all of a sudden when the
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    angle becomes 90 degrees,
    now I can actually define
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    what sine of theta is.
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    Sine of theta now is just y.
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    Is just the y-coordinate,
    which is 1.
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    If theta is equal to-- I'm
    going to make sure it's very
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    messy right here-- if theta
    is equal to 90 degrees,
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    or pi over 2 radians.
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    This is pi over 2.
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    This angle right here.
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    And similar, cosine
    of pi over 2 is 0.
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    Because the x-coordinate
    right here is 0.
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    Let me do it with a
    couple more examples.
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    Oh, I'm forgetting the
    tangent function.
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    And you could probably
    figure out now, what is the
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    definition now we can use
    for the tangent function?
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    Well, going back-- let's
    use this green theta here.
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    Because it's kind
    of a normal angle.
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    So in this green angle
    here, tangent is
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    opposite over adjacent.
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    So tangent now, we
    can define as y/x.
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    And remember, these y's and x's
    that we're using are the point
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    on the unit circle where the
    angle that's defined by this--
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    by whatever-- where the radius
    that is subtended by this
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    angle, or I guess the arc,
    intersects-- actually,
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    I'm getting confused
    with terminology.
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    It's where this line
    intersects the circumference.
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    The coordinate of that-- the
    sine of theta is equal to y.
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    The cosine of theta
    is equal to x.
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    And the tangent of
    theta is equal to y/x.
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    Let's do a couple of examples
    and hopefully this'll make a
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    little bit more sense to you.
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    Let me try to really fast
    draw a new unit circle.
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    So that's my unit circle.
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    And here's the coordinate axis.
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    It's one of them.
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    And here is the other one.
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    So if we use the angle-- let's
    use the angle pi over 2, right?
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    Theta equals pi over 2.
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    Well, pi over 2 is right here.
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    It's a 90 degree angle, if
    you wanted to use degrees.
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    And now, we just figure
    out where it intersects
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    the unit circle.
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    And once again, this is
    a unit circle, so it
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    has a radius of 1.
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    So we can see that sine of pi
    over 2 equals the y-coordinate
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    where it intersects
    the unit circle.
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    So that's just 1.
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    What's cosine of pi over 2?
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    Well, it's just the
    x-coordinate, where you
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    intersect the unit circle.
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    And the x-coordinate here is 0.
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    And what's the tangent
    of pi over 2?
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    This is interesting.
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    The tangent of pi over 2.
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    Well, the tangent we
    defined now as y/x.
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    So the y-coordinate, this
    is the point 0, 1, right?
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    The y-coordinate is 1.
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    So it equals 1/0.
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    So this is undefined.
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    So still, we don't have a
    tangent function that can
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    define itself at
    certain points.
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    But in the next module, we're
    actually going to graph this.
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    And you'll see that it
    approaches infinity.
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    And similarly, we could try to
    find the functions for when
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    theta equals pi, right?
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    That's like 180 degrees.
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    That's this point right here.
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    So sine of pi.
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    What's the y-coordinate
    at this point?
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    Well, this point is
    negative 1 comma 0.
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    So the y-coordinate is 0.
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    What's the x-coordinate?
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    Cosine of pi.
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    That's negative 1.
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    And of course, what's the
    tangent of pi radians?
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    It's y/x.
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    So it's 0 over negative
    1, which equals 0.
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    Hopefully this makes sense.
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    Now in the next module I'll
    actually graph these points.
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    And you'll see how it all comes
    together and why it is useful
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    to define the sine, the cosine,
    the tangent functions this way.
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    See you soon.
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    Bye.
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Title:
Unit Circle Definition of Trig Functions
Description:

Using the unit circle to define the sine, cosine, and tangent functions

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Video Language:
English
Duration:
10:11

English subtitles

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