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SAT Prep: Test 3 Section 4 Part 4

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    Welcome back.
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    I almost ran out of time in that
    last video, so let's just
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    start from the beginning for
    problem number fourteen.
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    So I drew the figure, and they
    told us that this line is
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    perpendicular to that line,
    and they drew it here.
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    And that this is perpendicular
    to that, and
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    they drew it there.
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    They told us this was 125
    degrees, this is x.
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    And then the one piece of
    information they tell us, is
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    that LN, this line,
    is equal to LM.
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    And I marked it here.
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    What we said at the end of the
    last video was, well if these
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    two sides are equal, we also
    know from geometry class, that
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    the base angles are also
    going to be equal.
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    And then let's see what we can
    do with that, whether we can
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    figure out x.
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    Well the first step we can do,
    is we can say, well if this is
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    125 degrees, what is this
    angle right here?
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    Well they're going to have to
    add up to 180, because they're
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    supplementary.
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    So this is going to be,
    what's 180 minus 125?
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    Well what's 80 minus 25?
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    It's 55 degrees.
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    So if that's 55, then this
    is also going to be 55.
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    And then if these are both 55,
    what is this angle up here?
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    Well they're all in a triangle,
    so they have
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    to add up to 180.
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    So 55 plus 55 is 110, so this
    one has to be 70 degrees.
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    Or 180 minus 110.
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    You have to add up
    to 180 degrees.
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    So this is 70 degrees
    right here.
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    And now can we figure out
    what this angle is here?
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    This is what I call
    the angle game.
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    You just have to keep figuring
    out of angles.
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    Well if this is 70 degrees, this
    angle plus this angle,
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    they're going to be
    complementary.
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    They're going to come out to
    90, because this is 90.
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    So all we have left is
    90 degrees here.
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    So if these two have to
    add up to 90 degrees,
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    then this is 20 degrees.
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    That says 20.
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    I know I wrote it really
    small, you
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    probably can't read it.
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    We know that this whole thing is
    a right angle because this
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    is a right angle.
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    So if this is 90, we know that
    this whole thing is 90.
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    So this is 20.
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    And now finally, I think
    we're ready for x.
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    Because x plus 90 plus 20 has
    to be equal to 180 because
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    it's in the same triangle.
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    So x plus 90 plus 20
    is equal to 180.
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    x plus 110 is equal to 180.
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    x is equal to 70 degrees.
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    And we are done.
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    Next problem.
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    Problem number fifteen.
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    A measuring cup contains 1/5
    a cup of orange juice.
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    It is then filled to the 1 cup
    mark that is a mixture
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    containing equal amounts of
    orange, grapefruit and
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    pineapple juices.
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    What fraction of the final
    mixture is orange juice?
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    This is interesting.
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    You have 1/5 already orange
    juice, and then the next 4/5
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    is going to be equal parts--
    because we're going to fill to
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    the 1 cup mark.
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    It's going to be equal parts
    orange, grapefruit-- I'll just
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    write grape-- and pineapple.
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    So the next 4/5 is going to be
    split amongst these three, and
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    it's equally.
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    So how much more orange juice
    are we putting in?
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    We took 4/5, and 1/3 of
    this 4/5 is going
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    to be orange juice.
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    So the amount of orange juice
    we're putting in now is 1/3
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    times the 4/5.
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    So we're putting in
    4/15 orange juice.
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    And we already had
    1/5 orange juice.
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    So 1/5 plus 4/15.
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    That equals 3/15 plus 4/15,
    which equals 7/15.
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    That is the final mixture
    of orange juice.
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    And doesn't that make
    sense intuitively?
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    That makes sense because there's
    20% orange juice, and
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    then we're adding maybe a little
    bit less than a 1/4.
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    So we'll have a little bit less
    than 1/2 in the glass.
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    All right.
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    Next problem.
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    I don't know, my cousin's
    answer seems a little
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    suspicious.
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    She had marked up this book.
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    All right.
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    Problem number sixteen.
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    If a plus 2b is equal
    to 125% of 4b.
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    So that equals 125%.
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    If you want to write 125%
    as a decimal, which I
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    like to do, it's 1.25.
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    125% of 4b, what is the
    value of a over b?
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    So we want to figure
    out a over b.
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    Let's just solve this thing.
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    So a plus 2b is equal to,
    what's 1.25 times 4?
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    If you have $1.25 and
    you have that 4
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    times, it's $5.00, right?
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    4 times 1 and then 4 times
    a quarter, that's another
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    dollar, so that's 5b.
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    And then subtract 2b
    from both sides.
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    You get a is equal to 3b.
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    Divide both sides by b,
    and you get a over
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    b is equal to 3.
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    And you are done the problem.
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    Problem number seventeen.
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    They have a number line.
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    This number line, let me see
    how much I have to draw of
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    this number line, to minimize
    my drawing.
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    They say 0 is here, 1 is here.
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    How many hash marks are there?
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    1, 2, 3, 4, 5, 6,
    7, 8 hash marks.
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    Oh it says there.
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    On the number line above, there
    are 9 equal intervals
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    between 0 and 1.
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    What is the value of x?
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    So there's 1, 2, 3,
    4, 5, 6, 7, 8, 9.
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    I have 9 equal intervals, and
    then x is right-- I'm just
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    going to make sure I
    draw it correctly.
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    We have 2 marks, and
    then we have x.
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    And actually we have the
    square root of x.
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    So they're 9 equal
    intervals, right?
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    So we could just do this is 1/9,
    this is 2/9, this is 3/9,
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    4/9, this is 8/9, this is 9/9.
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    This is 8/9, this is 7/9, this
    is 6/9, this is 5/9, because 9
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    equal intervals.
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    So we know that the square root
    of x is equal to 6/9.
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    Square both sides.
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    What's 6/9?
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    That's the same thing as 2/3.
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    So you square both sides.
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    You get x is equal to 4/9.
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    2 squared, 3 squared.
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    We are done.
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    Next problem.
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    Problem eighteen.
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    In the xy-coordinate plane, the
    distance between point B--
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    so B is the point 10 comma 18.
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    The distance between the point
    B and the point A-- A is
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    point x comma 3.
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    So the distance is 17 between
    these points.
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    What is one possible
    value of x?
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    So this is the distance formula,
    and the distance
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    formula is really just the
    Pythagorean theorem.
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    What we do is we say, well the
    distance squared is equal to
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    the change in x squared, plus
    the change in y squared.
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    And this is really just the
    Pythagorean theorem.
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    If you haven't learned that yet,
    actually I don't think
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    I've done a distance formula
    video, that's on my to-do
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    list. But I'll do that.
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    It's just the Pythagorean
    theorem.
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    The distance squared, so 17
    squared, is equal to-- what's
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    the change in x?
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    So let's just call that 10 minus
    x squared plus-- and
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    then we know that change
    in y-- so 18 minus 3.
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    So it's 15 squared.
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    I know 15 squared is 225.
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    This is going to be equal
    to x squared minus 20x.
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    It could be plus 100.
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    What's 17 squared?
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    17 times 17?
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    7 times 7 is 49.
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    1 times 7 is 7, plus 4 is 11.
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    0 plus 17.
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    It is 289.
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    And so then we can subtract
    289 from both sides.
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    So you get 0 is equal to x
    squared minus 20x plus-- add
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    these two together--
    325 minus 289.
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    I only have 10 seconds
    left, so I'll do
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    it in the next video.
Title:
SAT Prep: Test 3 Section 4 Part 4
Description:

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Video Language:
English
Team:
Khan Academy
Duration:
09:45

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