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Normal force and contact force | Forces and Newton's laws of motion | Physics | Khan Academy

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    Let's say that I have a
    huge, maybe frozen over lake,
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    or maybe it's a big pond.
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    So I have a huge surface of
    ice over here-- my best attempt
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    to draw a flat surface
    of ice-- and I'm
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    going to put two
    blocks of ice here.
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    So I'm going to put
    one block of ice
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    just like this, one block
    of ice right over here.
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    And then I'm going to put
    another block of ice right
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    over here.
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    And then another block
    of ice right over here.
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    And these blocks of
    ice are identical.
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    They're both 5 kilograms.
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    They are both 5 kilograms--
    let me write this down.
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    So they are both 5 kilograms.
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    Or both of their masses, I
    should say, are 5 kilograms.
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    And the only difference
    between the two
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    is that relative to
    the pond, this one
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    is stationary-- this
    one is stationary--
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    and this one is moving
    with a constant velocity--
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    constant velocity.
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    Constant velocity in the
    right-wards direction.
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    And let's say that
    its constant velocity
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    is at 5 meters per second--
    5 meters per second.
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    And the whole reason why I made
    blocks of ice on top of ice
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    is that we're going to
    assume, at least for the sake
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    of this video, that
    friction is negligible.
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    Now what does Newton's
    First Law of Motion
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    tell us about something that
    is either not in motion--
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    or you could view this as
    a constant velocity of 0--
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    or something that has
    a constant velocity?
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    Well Newton's First
    Law says, well
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    look, they're going to keep
    their constant velocity
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    or stay stationary, which is
    the constant velocity of 0,
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    unless there is some
    unbalance, unless there
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    is some net force
    acting on an object.
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    So let's just think
    about it here.
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    In either of these
    situations, there
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    must not be any unbalanced
    force acting on them.
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    Or their must not
    be any net force.
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    But if you think
    about it, if we're
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    assuming that these
    things are on Earth,
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    there is a net force
    acting on both of them.
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    Both of them are at the
    surface of the Earth,
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    and they both have
    mass, so there
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    will be the force of
    gravity acting downwards
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    on both of them.
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    There is going to be the
    downward force of gravity
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    on both of these blocks of ice.
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    And that downward force of
    gravity, the force of gravity,
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    is going to be equal to
    the gravitational field
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    near the surface of the
    Earth, times-- which
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    is a vector-- times
    the mass of the object.
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    So times 5 kilograms.
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    This right over here is 9.8
    meters per second squared.
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    So you multiply that times 5.
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    You get 49 kilogram meter
    per second squared, which
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    is the same thing as 49 newtons.
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    So this is a little bit
    of a conundrum here.
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    Newton's First Law
    says, an object at rest
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    will stay at rest, or
    an object in motion
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    will stay in motion, unless
    there is some unbalanced,
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    or unless there
    is some net force.
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    But based on what
    we've drawn right here,
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    it looks like there's
    some type of a net force.
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    It looks like I have 49 newtons
    of force pulling this thing
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    downwards.
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    But you say, no, no no, Sal.
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    Obviously this thing won't
    start accelerating downwards
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    because there's ice here.
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    Its resting on a big
    pool of frozen water.
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    And so my answer to you is,
    well, if that's your answer,
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    then what is the resulting
    force that cancels out
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    with gravity to keep
    these blocks of ice,
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    either one of them,
    from plummeting down
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    to the core of the Earth?
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    From essentially
    going into free fall,
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    or accelerating towards
    the center of the Earth?
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    And you say, well, I guess if
    these things would be falling,
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    if not for the ice,
    the ice must be
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    providing the
    counteracting force.
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    And you are absolutely correct.
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    The ice is providing
    the counteracting force
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    in the opposite direction.
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    So the exact magnitude
    of force, and it
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    is in the opposite direction.
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    And so if the force of gravity
    on each of these blocks of ice
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    are 49 newtons downwards
    it is completely
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    netted off by the force of
    the ice on the block upwards.
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    And that will be a force 49
    newtons upwards in either case.
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    And now, hopefully,
    it makes sense
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    that Newton's First
    Law still holds.
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    We have no net force on this
    in the vertical direction,
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    actually no net force on
    this in either direction.
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    That's why this guy
    has a 0 velocity
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    in the horizontal direction.
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    This guy has a constant velocity
    in the horizontal direction.
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    And neither of them
    are accelerating
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    in the vertical direction.
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    Because you have the force
    of the ice on the block,
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    the ice is supporting
    the block, that's
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    completely
    counteracting gravity.
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    And this force, in this example,
    is called the normal force.
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    This is the normal force--
    it's 49 newtons upwards.
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    This right here is
    the normal force.
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    And we'll talk more about the
    normal force in future videos.
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    The normal force
    is the force, when
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    anything is resting
    on any surface that's
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    perpendicular to that surface.
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    And it's going to start
    to matter a lot when
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    we start thinking about
    friction and all the rest.
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    So what we'll see in future
    videos, when you have something
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    on an incline, and let's say
    I have a block on an incline
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    like this.
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    The normal force
    from the, I guess
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    you could say, this
    wedge on the block,
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    is going to be perpendicular
    to the surface.
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    And if you really think
    about what's happening here,
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    it's fundamentally an
    electromagnetic force.
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    Because if you really zoomed
    in on the molecules of the ice
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    right over here, even better
    the atoms of the ice here.
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    And you really zoomed in on
    the atoms or the molecules
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    of the ice up here, what's
    keeping this top block of ice
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    from falling down
    is that in order
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    for it to go through its
    molecules would have to kind
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    of compress against, or I guess
    it would have to get closer
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    to, the water molecules
    or the individual atoms
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    in this ice down here.
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    And the atoms, let me
    draw it on an atomic level
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    right over here.
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    So maybe, let me draw one
    of this guy's molecules.
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    So you have an oxygen
    with 2 hydrogens
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    and it forms this big
    lattice structure.
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    And we can talk about more of
    that in the chemistry playlist.
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    And let's talk about this ice
    as one of these molecules.
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    So maybe it looks
    something like this.
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    And it has its 2 hydrogens
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    And so what's keeping these guys
    from getting compressed, what's
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    keeping this block of ice
    from going down further,
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    is the repulsion between the
    electrons in this molecule
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    and the electrons
    in that molecule.
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    So on a macro level we view
    this is kind of a contact force.
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    But on a microscopic
    level, on an atomic level,
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    it's really just electromagnetic
    repulsion at work.
Title:
Normal force and contact force | Forces and Newton's laws of motion | Physics | Khan Academy
Description:

The force that keeps a block of ice from falling towards the center of the earth. Created by Sal Khan.

Watch the next lesson: https://www.khanacademy.org/science/physics/forces-newtons-laws/normal-contact-force/v/normal-force-in-an-elevator?utm_source=YT&utm_medium=Desc&utm_campaign=physics

Missed the previous lesson? https://www.khanacademy.org/science/physics/forces-newtons-laws/newtons-laws-of-motion/v/newton-s-third-law-of-motion?utm_source=YT&utm_medium=Desc&utm_campaign=physics

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Video Language:
English
Team:
Khan Academy
Duration:
07:18

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