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>> So complex numbers consist of two
parts: A real part and an imaginary part,
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and we typically write them then as z a
complex number is equal to a plus j B.
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Because there's two parts it requires
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a complete plane to
represent them graphically.
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A real number we can show
on the real number line,
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an imaginary number we can show
along an imaginary number line.
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But when you've got
both the real and imaginary part,
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we form what is known as
the complex plane where
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the horizontal axis of the plane
is referred to as the real axis,
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and we plot the real value of the
complex number along the horizontal axis.
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The vertical axis becomes
the imaginary axis
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where we plot the imaginary part
of our complex number.
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So, for example here we have
z is equal to two plus j.
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We come over one,
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two units along the real part because
in this case a the real part is two,
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and we go up one unit along
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the imaginary axis because
our imaginary part is one times j.
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So, here we'd have one j,
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two j, three j.
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You can think of J almost as
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a unit vector or a quantity
showing us which axis we're on.
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The distance along this axis is two.
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the distance along this axis
is one times j. All right.
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We here are representing
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this real number or
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this complex number in what is
known as rectangular coordinates,
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a horizontal value and a vertical value.
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As you know we can also represent points in
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a plane using polar coordinates where
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the two coordinate values are
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a angle of rotation away from
the horizontal axis which we call theta,
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and the distance from the origin
out to the point along
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that ray is known as the magnitude
of the complex number.
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So, we can write z in polar form,
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in terms of this magnitude and an angle.
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Now, how did the polar and rectangular
coordinates relate to each other?
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We can go from rectangular to
polar using Pythagorean's theorem.
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So, from rectangular to polar we
can calculate the magnitude of z.
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That's simply equal to,
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using Pythagorean's theorem, the
square root of the two sides.
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Well this is A, so it would be
the square root of A squared,
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and the distance along
the imaginary axis is b.
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So, A squared plus B squared and
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theta the angle is equal
to the inverse tangent
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of the opposite over the adjacent or
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the inverse of the imaginary over the real
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or the inverse tangent of b over a.
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Now, to go from polar coordinates
back to rectangular coordinates,
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we again use the right
triangle and recognize
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that the distance along
the horizontal axis is A,
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that's simply equal to the projection
of that point down onto
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the real axis which of course is
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the magnitude of z times
the cosine of the angle.
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So, A then, is equal to
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the magnitude of z times
the cosine of the angle theta,
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and b, the imaginary component is equal
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to the magnitude of z
times the sine of theta.
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Again, is just for
the projection of this point,
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onto the imaginary axis.
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So, that takes us from polar coordinates,
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back to rectangular coordinates.
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Now let's just do an example real
quick to show how this works.
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In fact let's do it for
this quantity right there.
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The complex number z equals two plus j
given to us in rectangular coordinates,
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how do we get the polar
representation of it?
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While coming down here,
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the magnitude of z is going to equal
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the square root of the real part
squared which is two squared,
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plus the imaginary part.
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The imaginary part is
coming up here one unit,
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again we don't square the j.
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The distance there, for
the geometry in this circuit,
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in this problem, the distance
there is one unit,
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so it'll be one squared and that
equals the square root of five.
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Theta is equal to the arc-tangent
of the imaginary part which is one,
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it's not J, it's one.
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Again, this distance is one unit.
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So, the one imaginary part
over the real part two,
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and that turns out to be 26.6 degrees.
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Now to show how we take it and go back.
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First of all, this number
then in polar coordinates,
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we would represent as square root
of five angle 26.6 degrees.
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Okay? Now, how do we take
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this number in polar form and go
back into rectangular coordinates?
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Well, it tells us right here that A,
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the real part of our number
is equal to A is
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equal to the magnitude of Z which we
found to be the square root of five,
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times the cosine of the angle which
is in this case is 26.6 degrees.
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When you're doing this make sure
you got your calculator is set in
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degrees and not radians if
you're working in degrees.
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That then of course is going to equal A,
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the distance along
the real axis which we know
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and when you can't do that calculation
if you find that is equal to two,
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and b the imaginary part then
is equal to the square root of
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five times the sine of 26.6
degrees which equals one.