Points on line of reflection | Transformations | Geometry | Khan Academy
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0:00 - 0:03- [Voiceover] We're asked to
use the "Reflection" tool to -
0:03 - 0:06define a reflection that
will map line segment ME, -
0:06 - 0:11line segment ME, onto the
other line segment below. -
0:11 - 0:13So we want to map ME to
this segment over here -
0:13 - 0:15and we want to use a Reflection.
-
0:15 - 0:17Let's see what they expect from us
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0:17 - 0:18if we want to add a Reflection.
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0:18 - 0:20So if I click on this it says
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0:20 - 0:22Reflection over the line from,
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0:22 - 0:23and then we have two coordinate pairs.
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0:23 - 0:25So they want us to define
the line that we're going -
0:25 - 0:29to reflect over with
two points on that line. -
0:29 - 0:30So let's see if we can do that.
-
0:30 - 0:32To do that I think I need
to write something down -
0:32 - 0:35so let me get my scratch pad out
-
0:35 - 0:37and I copied and pasted the same diagram.
-
0:38 - 0:40And the line of reflection,
one way to think about it, -
0:40 - 0:43we want to map point E,
we want to map point E, -
0:43 - 0:46to this point right over here.
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0:46 - 0:48We want to map point M
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0:49 - 0:51to this point over here.
-
0:52 - 0:55And so between any point
and its corresponding point -
0:55 - 0:58on the image after the reflection,
-
0:58 - 1:01these should be equidistant
from the line of reflection. -
1:01 - 1:03This and this should
be equidistant from the -
1:03 - 1:04line of reflection.
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1:04 - 1:06This and this should be E,
and this point should be -
1:06 - 1:09equidistant from the line of reflection.
-
1:09 - 1:11Or another way of thinking about
it, that line of reflection -
1:11 - 1:14should contain the midpoint
between these two magenta points -
1:14 - 1:17and it should contain the
midpoint between these two -
1:17 - 1:20deep navy blue points.
-
1:20 - 1:22So let's just calculate the midpoints.
-
1:22 - 1:25So we could do that with a
little bit of mathematics. -
1:25 - 1:28The coordinates for E
right over here, that is, -
1:28 - 1:29let's see that is
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1:30 - 1:31x equals negative four,
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1:32 - 1:35y is equal to negative four,
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1:36 - 1:38and the coordinates for the
corresponding point to E -
1:38 - 1:40in the image.
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1:40 - 1:44This is x is equal to
two, x is equal to two, -
1:44 - 1:46and y is equal to negative six.
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1:47 - 1:48So what's the midpoint between
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1:48 - 1:49negative four, negative four,
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1:49 - 1:51and two, comma, negative six?
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1:51 - 1:53Well you just have to take
the average of the x's -
1:53 - 1:54and take the average of the y's.
-
1:54 - 1:56Let me do that, actually
I'll do it over here. -
1:56 - 1:58So if I take the average
of the x's it's going to be -
1:58 - 2:01negative four, negative four,
-
2:01 - 2:04plus two, plus two,
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2:04 - 2:07over two, that's the average of the x's.
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2:07 - 2:09And then the average of
the y's, it's going to be -
2:09 - 2:12negative four plus negative six over two.
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2:12 - 2:15Negative four plus negative six,
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2:15 - 2:19over two and then close the parentheses.
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2:19 - 2:23Let's see, negative four
plus two is negative two, -
2:23 - 2:24divided by two is negative one.
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2:24 - 2:27So it's going to be negative one, comma.
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2:27 - 2:29Negative four plus negative six,
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2:29 - 2:30that's the same thing as
negative four minus six -
2:30 - 2:32which is going to be negative 10.
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2:32 - 2:34Divided by two is negative five.
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2:36 - 2:37Let me do that in a blue color
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2:37 - 2:39so you see where it came from.
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2:39 - 2:41Is going to be negative five.
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2:42 - 2:43So there you have it.
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2:43 - 2:45That's going to be the midpoint between E
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2:45 - 2:47and the corresponding point on its image.
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2:47 - 2:50So let's see if I can plot that.
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2:50 - 2:51So this is going to be,
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2:51 - 2:54this point right over here is going to be
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2:54 - 2:57negative one, comma, negative five.
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2:57 - 2:58So x is negative one,
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2:58 - 2:59y is negative five.
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2:59 - 3:01So it's this point right over here
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3:01 - 3:03and it does indeed look like the midpoint.
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3:03 - 3:05It looks like it's
equidistant between and E -
3:05 - 3:06and this point right over here.
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3:06 - 3:10And so this should sit on
the line of reflection. -
3:10 - 3:12So now let's find the midpoint
between M and this point -
3:12 - 3:13right over here.
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3:13 - 3:16The coordinates of M
are x is negative five, -
3:17 - 3:19and y is equal to three.
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3:20 - 3:24The coordinates here
are x is equal to seven -
3:24 - 3:27and y is equal to negative one.
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3:28 - 3:30So the midpoint, the x
coordinate of the midpoint, -
3:30 - 3:32is going to be the
average of the x's here. -
3:32 - 3:35So let's see it's going
to be negative five -
3:35 - 3:37plus seven over two.
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3:37 - 3:39And the y coordinate of the
midpoint is going to be the -
3:39 - 3:40average of the y coordinates.
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3:40 - 3:44So three plus negative one over two.
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3:44 - 3:48Let's see, negative five of plus seven is
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3:48 - 3:50positive two, over two is one.
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3:51 - 3:54Three minus one, three plus negative one,
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3:54 - 3:56that's positive two over two is one.
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3:56 - 3:59So the point one, comma, one
is a midpoint between these two -
3:59 - 4:02so one, comma, one, just like that.
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4:02 - 4:04So the line of reflection
is going to contain -
4:04 - 4:05these two points.
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4:05 - 4:07And two points define a line.
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4:08 - 4:09Let me draw the line of reflection,
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4:09 - 4:11just 'cause we did all of this work,
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4:11 - 4:14the line of reflection is
going to look something like, -
4:17 - 4:19I want to draw this a little
bit straighter than that, -
4:19 - 4:24it's going to look something like this.
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4:24 - 4:26And this makes sense that
this is a line of reflection. -
4:27 - 4:29I missed that magenta point a little bit,
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4:30 - 4:32so let me go through the magenta point.
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4:32 - 4:33Okay, there you go.
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4:33 - 4:35This makes sense that this
is a line of reflection -
4:35 - 4:38'cause you see that you
pick an arbitrary point -
4:38 - 4:39on segment ME,
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4:39 - 4:41say that point,
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4:41 - 4:43and if you reflected over this line.
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4:43 - 4:46This is the shortest
distance from the line. -
4:46 - 4:49You just go onto the other
side of the line equal distant -
4:49 - 4:51and you get to its corresponding point
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4:51 - 4:52on the image.
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4:52 - 4:55So it makes a lot of sense
that these are mirror images -
4:55 - 4:57if this is kind of the mirror here.
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4:57 - 5:00And you can image that this
is kind of the surface of -
5:00 - 5:02the water, if you're
looking at it at an angle. -
5:02 - 5:03I don't know if that helps you or not.
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5:03 - 5:06But anyway we found two points.
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5:06 - 5:09We found two points that
define that line of reflection -
5:09 - 5:11so now let's use the tool to type them in.
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5:11 - 5:13One is negative one, negative five.
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5:13 - 5:14The other is one, comma, one
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5:14 - 5:15so let me see if I can remember that.
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5:15 - 5:17I have a bad memory.
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5:18 - 5:22So one is negative one,
comma, negative five. -
5:23 - 5:25And then the other one is one, comma, one.
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5:25 - 5:27And we see it worked.
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5:27 - 5:28We see it worked.
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5:28 - 5:31When I did that, it actually
made the reflection happen -
5:31 - 5:33and notice it completely
went from this point -
5:33 - 5:37and now our blue is over the
image that we wanted to get to. -
5:37 - 5:39So we are done.
- Title:
- Points on line of reflection | Transformations | Geometry | Khan Academy
- Description:
-
Points on line of reflection
Practice this lesson yourself on KhanAcademy.org right now:
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- Duration:
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Ouki Douki edited English subtitles for Points on line of reflection | Transformations | Geometry | Khan Academy |