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Operations on Functions - Grade 11 (General Mathematics)

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    Hi guys, it's me teacher Gon.
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    For today's video, we will do
    operations on functions.
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    This topic is considered as
    the algebra of functions,
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    So let's start.
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    Functions can be added,
    subtracted, multiplied, and divided.
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    Such procedures are called
    "operations of functions" or
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    "algebra of functions."
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    Here inside the box
    are the different operations
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    can be used in functions
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    and here are the functions of
    the different operations.
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    We have f plus g of x that is equal to
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    f of x plus
    g of x.
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    We have here the second one,
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    f minus g of x is equal to
    f of x minus g of x.
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    Third one, we have
    f times g of x
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    is equal to f of x times g of x.
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    The fourth one: f divided by
    g of x is equal to
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    f of x over g of x.
    For addition of functions: given
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    the functions, f of x and g of x,
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    their sum is denoted by
    f plus g of x.
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    So we will use the formula
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    f plus g of x is equal
    to f of x plus g of x.
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    And now for the subtraction of functions,
    given two functions,
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    f of x and g of x,
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    Their difference is denoted by
    f minus g of x
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    is the function defined by
    f minus g of x is equal to
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    f of x minus g of x.
    So let's have an example
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    on how to do addition and
    subtraction of functions.
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    So, we have here:
    Given the functions
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    f of x that is equal to 4x (squared) plus
    3x plus two, and the second function
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    which is g of x is equal to 7x squared
    minus 5x minus one.
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    So, in this given example,
    we are asked to find
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    f plus g of x, meaning we
    need to add the two functions
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    and then we have f minus g of x, where
    we're needing to get the difference
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    of the two functions.
    So let's get started.
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    So, start with addition of functions.
    We have to find f plus g of x
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    wherein your f of x is equal to
    this one, so that is equal to
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    f of x plus g of x.
    You need to substitute the value of
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    f of x. The value of f of x simply is
    4x squared plus 3x plus two.
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    Include that in the parentheses. Plus
    the value of your g of x.
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    For the expression, we have
    7x squared minus 5x minus one.
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    And then all you need to do here is
    to eliminate first the parentheses,
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    and then combine like terms. So we
    have here the like terms, which is
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    4x squared and 7x squared,
    we have 11x squared.
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    And then 3x plus negative 5x, that will
    give you negative 2x.
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    And then for the constants, we have
    two plus negative one,
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    that will give you plus one.
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    So the sum of the two functions
    f of x and g of x, simplified,
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    is 11x squared minus 2x plus one.
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    Now let's move on to find
    f minus g of x
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    wherein we need to do
    subtraction of functions.
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    So the formula that we're going to
    use is simply
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    f minus g of x.
    And then your f of x is
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    4x squared plus 3x plus two
    minus your g of x
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    is 7x squared minus 5x
    minus one.
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    And this time we will multiply
    the negative sign to the
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    7x squared minus 5x minus one.
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    So we will have the new equation,
    4x squared plus 3x plus 2.
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    This one is negative: negative 7x squared,
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    this will be positive: plus 5x,
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    and this is also positive.
    And the last thing you need to do
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    is to combine like terms. So your
    f minus g of x
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    when you combine like terms, we have
    4x squared and then negative 7x squared,
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    we have negative 3x squared, then
    3x plus 5x, that will give you 8x,
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    two plus one is three. Therefore,
    the difference between f of x and g of x
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    simplified is negative 3x squared plus
    8x plus three. So that's it on
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    how to do addition.
    Once we are done with addition and
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    subtraction of functions, let's move on to
    multiplication and division of functions.
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    Given the functions f of x and g of x,
    their product, denoted by f times g of x
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    is the function defined by
    f times g of x is equal to
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    f of x times g of x.
    This formula inside the box
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    is the formula that we're going to use
    in multiplying functions.
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    Now, for the division of functions,
    given the functions f of x and g of x
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    the quotient, denoted by f over g of x,
    is the function defined by the formula
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    f over g of x is equal to f of x over g of
    x again, or in g of x, or your divisor,
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    is not equal to 0.
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    Now let's go look at examples with
    regards to multiplication and division of
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    functions. We have here:
    Given the functions f of x is equal to
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    x squared minus one and g of x is equal
    to x plus one, we are asked to find
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    f times g of x and f over g of x.
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    So let's start with the multiplication
    of functions.
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    So we will use the formula f times g of x
    is equal to f of x times g of x
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    wherein in this given example you need to
    multiply first. Let's get the value of
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    f of x which is x squared minus one...
    x squared minus one.
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    And then multiply by the value of g of x
    which is x plus one. As you can see,
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    we have two binomials, therefore we're
    going to use FOIL method.
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    So, let's multiply. We have x squared
    times x, that will give you x cubed,
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    and then x squared times one, that is
    plus x squared, and then
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    inner terms, negative one times x,
    that'll give you minus x,
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    and the last terms, negative one times
    one, that is negative one. Therefore,
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    the product of the function f of x
    and g of x is simply...
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    x cubed plus x squared minus x minus one.
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    Now let's proceed to the division
    of functions.
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    The formula we're going to use is f over g
    of x is equal to f of x over g of x.
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    So let's substitute the value of f of x
    which is x squared minus one
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    over the value of your g of x, which is
    nonzero,
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    we have x plus one. So how you're going
    to simplify f of x over g of x,
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    as you can see, our numerator is x squared
    minus one, and then your denominator is
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    x plus one. We can apply factoring because
    the numerator has the pattern of
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    difference of two squares, so we can
    factor out your numerator as
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    x plus one times x minus one, so
    that is over x plus one.
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    So we have your x plus one in the
    numerator and x plus one in the
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    denominator, so we can cancel all
    this out, and the remaining expression
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    in your numerator simplified is
    x minus one. So this the quotient of
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    the function f of x and g of x. If you
    have any questions about this topic,
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    you can comment down below and ask
    for clarifications. So, by the way,
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    we will upload another video of this one
    wherein the content of the whole video
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    is more on the examples of operations
    on functions.
Title:
Operations on Functions - Grade 11 (General Mathematics)
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Video Language:
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Duration:
11:05

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