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>> In this video, we're
talking about half-lives
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of radioactive nuclei.
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Well, the first thing
is, what is a half-life?
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Well, it's just how much time
it takes for 1/2 of a sample
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of any radioactive nucleus to
decay to where there's only 1/2
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of the amount that
we started with left.
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And one nice thing is
that the half-lifes
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of any given isotope
is constant.
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It doesn't matter how much of
that stuff we have at any time,
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it takes -- whatever
that half-life is,
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that amount of time
for it to decay
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to half the original amount.
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So let's say we have
iodine-131, 20 mg.
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After 1 half-life, we'll
have half of that 20,
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which is 10 left, 10 mg.
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After another half-life,
2 half-lives,
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we'll have half the
10, which is 5 mg left.
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And after the third half-life,
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we'll have of 5,
which is 2.5 mg.
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And whatever this time is,
whatever the half-life is,
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it's the same from here to here,
here to here, here to here.
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It stays constant
for that isotope.
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Of course, different
isotopes have vastly different
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half-lives, from billions of
years to fractions of a second.
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So let's look at some examples.
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And as we look at
these examples,
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it's going to be
important to figure
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out what we're being given
and what we're being asked
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because that's going
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to determine how you
set the problem up.
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In this problem, we're
told that we have carbon-15
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and we're told what its
half-life is, 2.4 seconds.
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What we want to find is
how much of a given amount
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of the sample is left after
a given amount of time.
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So we're told what the
half-life is, how much we start
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with (240 g), and how long
-- how much time has passed,
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12 seconds have gone by.
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So this is going to
be a 2-step problem.
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First step's always going to
be, in a problem like this
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where we want to know how
much of this stuff is left,
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is we want to find out how
many half-lives have gone by.
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All you do to do that is take
the amount of time that's passed
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and divide by the half-life.
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So 12 seconds have gone
by, divided by 2.4 seconds
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for each half-life, and that
tells us 5 half-lives have
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gone by.
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Now that we know that, we can
approach it one of two ways.
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Either, we can take how
much we started with
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and cut in half, 5 times.
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So 240 divided by 2 is
120, that's 1 half-life --
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divided by 2 again, that's 2
half-lives is 60 -- 30, 15.
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And after 5 half-lives, we
see that we have 7.5 g left
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and that's the answer.
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Another way to do that
-- and this always works.
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Again, when the problem is
we want to find out how much
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of the sample is left and you're
told what the half-life is
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and how much time has gone
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by so you can figure how
many half-lives there are
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and how much you start with,
that was 240 g, times 1/2 raised
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to the power of however many
half-lives have gone by.
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In this case, 5 --
the power of 5 here is
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because 5 half-lives
have gone by.
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And it's always 1/2 here though.
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So if you plus this
into your calculator,
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you'll get the answer --
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7.5 g. You can do this
type of problem either way,
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whatever is easier for you.
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The other type of
problem we can --
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another type of problem we
can do this is we can figure
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out how long it takes
for a given sample
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to decay to a certain amount.
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So we have cesium-137,
this isotope,
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and we're told what its
half-life is, 30 years.
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We want to know how long it
takes for a 60 g sample to decay
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to 7.5 g. So we're told
what the half-life is.
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We're told how much we start
with, how much we end up with,
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and we want to find
out how long it takes.
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So, once more, the first
thing, we're going to want
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to do is find out how many
half-lives have gone by.
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So if we take how much we
start with, cut it in half,
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keep cutting it in
half until we get
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to the amount we're told we have
-- so 60 divided by 30 is --
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I mean, excuse me -- 60 divided
by 2 is 30, that's 1 half-life,
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30 divided by 2 is 15,
that's 2 half-lives.
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And 15 divided by 2 is 7.5.
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So 3 half-lives have gone by.
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So now that we know how many
half-lives have gone by,
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we want to find out how
much time has gone by.
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Well, we know how much time goes
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by for each half-life
-- 30 years, right?
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So we just take the number
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of half-lives times
the half-life itself --
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in other words, the
time per 1 half-life.
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And that tells us
that, in this case,
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90 years will have gone by.
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So another type of
problem we can do
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with half-lives is like this.
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So we have 1.2 mg
of phosphorous-32.
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And we know that it
decays to .30 mg --
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1.2 mg to .30 mg in 28.6 days.
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What's the half-life?
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So here, we're told how much
we start with, how much we end
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up with, how long has
gone by, and we're trying
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to find the half-life.
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So, once more, we figure out how
many half-lives have gone by.
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So we start with 1.2.
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Cut it in half.
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That gives us .60,
that's 1 half-life.
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Cut that in half, .30.
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That's 2 half-lives.
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That's how much we have.
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So we know that 2
half-lives have gone by.
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We also know that the
total time is 28.6 days.
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So if we just take the
total time, 28.6 days,
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divided by the number of
half-lives, 2 in this case,
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that gives us the
time per half-life,
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14.3 days per half-life, or
we say that the half-life
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for t 1/2 is equal to 14.3 days.