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Ideal Gas Example 4

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    I think it makes sense to keep doing a few more problems just
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    so you really get intimately comfortable
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    with PV equals nRT, or the ideal gas equation.
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    So we have 98 milliliters of an unknown gas.
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    They say weighs in the problem, but I'll use mass.
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    Its mass is 0.081 grams.
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    You shouldn't say weighs 0.081 grams. This is mass.
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    Weight would be in newtons if we're in the metric system
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    at standard temperature and pressure.
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    Calculate the molar mass of the gas.
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    So they want to know the mass per mole.
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    So the molar mass, or the mass per mole.
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    Now, we could just substitute this into PV is equal to nRT.
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    We know what standard temperature and pressure are.
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    Standard temperature is 273 degrees Kelvin.
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    Standard pressure is 1 atmosphere.
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    And then, of course, they're giving us 98 milliliters.
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    And then you can just solve for how many moles we have.
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    And naturally we'll do that.
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    But the other way to think about it is that
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    at standard temperature and pressure, an ideal gas
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    -- and we did this two videos ago.
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    We said 1 mole of an ideal gas at standard temperature and pressure
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    will fill up a volume of 22.4 liters.
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    And I'm normally not a big fan of memorizing things,
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    but this might be something handy to memorize
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    if you want to get through your chemistry test fast.
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    But you can always derive this if you know
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    what standard temperature and pressure is by PV equals nRT.
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    But if you know that 1 mole is going to take up that much space,
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    so one mole is to 22.4 liters, as how many moles,
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    let's say x moles in this question.
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    We want to figure out how many moles of the gas we have
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    and we know we are at 98 milliliters, so 0.098,
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    so we set up this proportional equation
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    and we could figure out how many moles we're dealing with.
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    If 1 mole takes up 22.4 liters,
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    then our number of moles are going to take up 0.098,
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    and this is an ideal gas in both circumstances.
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    So we could say 22.4x is equal to 0.098.
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    And then we have x is equal to 0.098 divided by 22.4.
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    And this, of course, is in moles.
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    So 0.098 divided by 22.4 is equal to 0.004375 moles.
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    And they're telling us that this amount has a mass of 0.081 grams.
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    So let me get the number.
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    So how many grams are there per mole?
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    So we take 0.081 grams and we just did the math
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    to figure out that we're dealing with 0.004375 moles.
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    So how many grams do we have per mole?
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    Let's take the calculator out.
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    So we have 0.081 divided by 0.004375 is equal to 18.51.
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    So it's equals 18.5 grams per mole.
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    So now this is an interesting question.
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    So we figured out the molar mass of our mystery substance
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    that took up 98 milliliters and had a mass of 0.081 grams
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    at standard temperature and pressure, and we figured out
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    its molar mass, or its mass per mole, is 18.5 grams.
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    So any guess as to what molecule we're dealing with?
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    And probably it's not going to be exact,
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    but at least in my brain, water seems to be a good candidate.
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    Water is H20.
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    Maybe I should do it in blue because it's water. H2O.
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    The mass of each hydrogen is 1.
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    Remember, hydrogen, at least in its most standard form,
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    doesn't have a neutron, so it's really just a proton
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    and an electron, so it has an atomic mass of 1
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    or a molar mass of 1 gram.
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    And oxygen has a molar mass of 16 grams.
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    So you have two hydrogens, so it's 2 plus 16 is equal to 18.
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    So it looks like our mystery substance is water.
Title:
Ideal Gas Example 4
Description:

Figuring out the molar mass of a mystery molecule at STP.

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Video Language:
English
Duration:
05:03
oliviagao8971 added a translation

English, British subtitles

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