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CA Algebra I: Rational Expressions

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    We're on problem 66.
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    And it says what is x squared
    minus 4x plus 4, divided by x
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    squared minus 3x plus 2, reduced
    to lowest terms?
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    So they probably want us
    to factor each of these
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    quadratics and see if any of
    these terms cancel out.
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    So let's try to do that.
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    So the numerator, this seems
    pretty easy to factor.
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    What two numbers when I
    multiply them equal 4?
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    And when I add them
    equal minus 4?
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    Well it's minus 2, right?
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    Minus 2 and minus
    2 is minus 4.
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    Minus 2 squared is plus 4.
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    So this is x minus 2
    times x minus 2.
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    And you could test it if
    you don't believe it.
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    Multiply that out.
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    Divided by, let's see,
    what two numbers?
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    This looks factorable.
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    They both have to be the same
    sign because when you multiply
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    them you get a positive.
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    And they're both going to be
    negative, because when you add
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    them you get a negative 3.
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    So let's see, minus
    2 and minus 1.
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    Minus 2 times minus
    1 is positive 2.
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    Minus 2 plus minus
    1 is minus 3.
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    So x minus 2, times x minus 1.
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    And if we assume that x is never
    equal to 2, because that
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    would make this expression
    undefined, we cancel that out.
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    You'll learn later that would
    cause a hole in the graph,
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    because the function
    is undefined there.
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    And you're left with minus
    2 over minus 1.
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    And that is choice A.
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    Problem 67.
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    This is good practice.
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    They give a bunch of it.
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    They say what is-- I'll just
    write it-- 12a cubed minus 20a
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    squared over 16a squared
    plus 8a.
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    Reduce to lowest terms. So let's
    just try to factor out
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    things on the top and the bottom
    and see what happens.
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    So in the top, in the
    numerator-- let me switch
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    colors-- both terms are
    divisible by 4 and a squared.
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    So let's fact out
    a 4a squared.
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    So we get 4a squared.
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    12 divided by 4 is a 3.
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    And a cubed divided by
    a squared is an a.
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    So 12a cubed divided by
    4a squared is 3a.
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    Minus 20-- I could say
    plus minus 20--
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    but you get the idea.
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    20 divided by 4 is 5.
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    And a squared divided by
    a squared is just a.
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    And if you don't believe
    this, multiply it out.
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    4a squared times 3a
    is 12a cubed.
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    And 4a squared times minus
    5 is minus 20a squared.
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    So it works out.
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    You do the denominator.
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    Let's see, both of these are
    divisible by 8a, so let's
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    factor that out.
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    16 divided by 8 is 2.
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    a squared divided by a is a.
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    So 16a squared divided
    by 8s is 2a.
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    And if you go the other
    way, 8a times 2a
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    squared is 16a squared.
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    So it all works out.
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    Plus 1.
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    8a times 1 is 8a.
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    So let's see what we
    could do here.
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    This is becomes a 1.
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    This becomes a 2.
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    And a squared divided by a, this
    becomes a 1 and this just
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    becomes just an a.
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    And we're left with a times
    3a minus 5, over 2
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    times 2a plus 1.
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    And let's see.
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    That is choice D.
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    I thought maybe they'd want us
    to re-multiply this out again.
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    But that is choice D.
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    Problem 68.
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    Oh this is a good one.
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    I'll just write it.
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    They want us to multiply
    something.
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    So they say 7z squared plus
    7z-- all of that--
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    over 4z plus 8.
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    Times z squared minus 4-- all of
    that-- over z to the third
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    plus 2z squared plus z equals.
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    So you must be like oh my god,
    I have to multiply all of
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    these things and I have
    to divide them.
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    But the best thing, I'm
    guessing, is to just factor
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    these out and all sorts of
    things will start canceling
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    out with each other.
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    And it will turn into a
    pretty simple problem.
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    Let's see, both of these terms
    are divisible by 7z.
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    So le'ts factor that out.
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    So that top part becomes, 7z
    squared divided by 7z, you
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    just have a z left.
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    If multiply these, you
    get 7z squared.
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    Plus 1.
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    If you multiply this out, you
    get 7z squared plus 7z.
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    When you multiply fractions,
    it's just the numerator times
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    the numerator, over the
    denominator times the
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    denominator.
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    So this is times
    the numerator.
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    Z squared minus 4, that's a
    squared minus b squared.
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    So that's z plus 2, a plus b,
    times z minus 2, a minus b.
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    That's just the pattern when I
    say all those a's and b's.
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    So that's z plus 2 times z minus
    2, hopefully you can
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    recognize that at this point.
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    And then all of that over--
    let's see, we can definitely
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    factor out a 4 here, so that's
    4 times z plus 2.
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    8 divided by 4 is 2 times-- so
    we can definitely factor out a
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    z here, so we get z times z
    squared plus 2z plus 1.
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    I think we're almost done.
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    Now we have to factor this.
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    Let me just rewrite
    everything.
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    So this is equal to 7z times
    z plus 1, times z plus 2,
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    times z minus 6.
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    All of that over 4 times
    z plus 2, times z.
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    And what's this?
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    This is z plus 1 squared.
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    Z plus 1 times z plus
    1, 1 times 1 is 1,
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    and 1 plus 1 is 2.
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    So times z plus 1,
    times z plus 1.
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    And now is fun part.
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    This is a 1 here, that's
    parentheses.
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    Now we can start
    canceling out.
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    And we assume that the
    denominator would never equal
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    0 and all that.
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    Let's see, this z plus
    2 cancels out
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    with this z plus 2.
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    This z plus 1 cancels out with
    one of these z plus 1's.
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    I'll do the one that's
    written messier.
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    And let's see, this z cancels
    out with this z.
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    And what are we left with?
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    Everything simplified to 7
    times z minus 6 over 4
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    times z plus 1.
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    I wrote a z minus b here.
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    It's z plus 2 times z minus 2.
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    All that pattern matching,
    I made a mistake.
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    Z squared minus 4 is z plus
    2 times z minus 2.
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    Not z minus b, and I though
    that was a 6.
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    So this is z minus 2.
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    So this is z minus 2.
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    And so that is choice A.
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    Sorry about that error.
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    Brain malfunctions
    all the time.
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    All right, now they want
    us to do it again.
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    They want us to find the product
    of x plus 5, over 3x
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    plus 2, times 2x minus
    3, over x minus 5.
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    Frankly, there's not a lot of
    simplification we can do, we
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    just have to multiply it out.
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    So this is going to be equal to
    x plus 5 times 2x minus 3.
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    All of that over 3x--
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    I'm just multiplying the
    numerator and then multiplying
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    the denominators-- 3x plus
    2 times x minus 5.
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    And now we just multiply
    both binomials, x
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    times 2x, 2x squared.
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    X times minus 3, minus 3x.
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    5 times 2x, plus 10x.
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    5 times minus 3, minus 15.
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    Fair enough.
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    Now you do the denominator.
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    3x times x is 3x squared.
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    3x times minus 5, minus 15x.
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    2 times x, plus 2x.
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    2 times minus 5, minus 10.
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    And now let's see if
    we can simplify.
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    We have the numerator is
    equal to 2x squared
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    minus 3x plus 10x.
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    So that's plus 7x minus 15.
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    All of that over 3x squared.
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    And minus 15x plus 2x.
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    That's minus 13x minus 10.
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    And that is choice D.
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    Next problem.
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    Problem 70.
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    Boy, they they want us
    to keep this up.
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    This is good practice.
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    So they write, x squared plus
    8x plus 16, over x plus 3,
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    divided by 2x plus 8, over
    x squared minus 9.
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    So the first thing you do, when
    you divide by a fraction,
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    it's the same thing is
    multiplying by its inverse.
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    So this is equal to x squared
    plus 8x plus 16, over x plus 3
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    times the inverse of this,
    x squared minus 9,
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    over 2x plus 8.
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    Fair enough.
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    Now let's see if we can simplify
    these a little bit.
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    I'll do that in yellow.
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    So this is, 4 plus 4 is
    8, 4 times 4 is 16.
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    So this we can rewrite as
    x plus 4 times x plus 4.
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    x squared minus 9, that's a
    squared minus b squared.
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    So this we can rewrite as x
    plus 3 times x minus 3.
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    It's going with the pattern.
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    We can factor out a 2 here, so
    we can rewrite this as 2
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    times x plus 4.
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    We have an x plus 3 there.
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    And of course, when we multiply
    fractions, we're just
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    multiplying all the numerators
    over all the denominators.
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    So it's almost like you
    make this one line.
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    So the numerator is x plus 4
    times x plus 4 times x plus 3
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    times x minus 3.
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    All of that over x plus 3
    times 2 times x plus 4.
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    So now let's do some
    cancellation.
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    This is the fun part.
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    So we have an x plus 4 and and
    x plus 4, cancel them out.
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    We have an x plus 3 and an x
    plus 3, cancel them out.
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    And what are we left with?
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    We are left with an x plus
    4 times an x minus 3.
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    All of that over 2.
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    And that is choice C.
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    And I will see you in
    the next video.
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Title:
CA Algebra I: Rational Expressions
Description:

66-70, more simplifying of rational expressions

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Video Language:
English
Duration:
11:28

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