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Absolute value inequalities

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    We're told to graph all possible
    values for h on the
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    number line.
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    And this is a especially
    interesting inequality because
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    we also have an absolute
    value here.
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    So the way we're going to do it,
    we're going to solve this
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    inequality in terms of the
    absolute value of h, and from
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    there we can solve it for h.
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    So let's just get the absolute
    value of h on
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    one side of the equation.
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    So the easiest way to do this
    is to add 19 and 1/2 to both
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    sides of this equation.
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    I often like putting that as an
    improper fraction, but 1/2
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    is pretty easy to deal with,
    so let's add 19 and 1/2 to
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    both sides of this inequality.
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    Did I just say equation?
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    It's an inequality, not an
    equation, it's an inequality
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    sign, not an equal sign.
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    So plus 19 and 1/2.
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    On the left-hand side, these
    guys obviously cancel out,
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    that was the whole point, and we
    are left with the absolute
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    value of h on the left-hand
    side is less than.
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    And then if we have 19 and 1/2,
    essentially minus 12, 19
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    minus 12 is 7, so it's going
    to be 7 and 1/2.
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    So now we have that the absolute
    value of h is less
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    than 7 and 1/2.
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    So what does this tell us?
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    This means that the distance,
    another way to interpret
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    this-- remember, absolute value
    is the same thing as
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    distance from 0-- so another
    way to interpret this
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    statement is that the distance
    from h to 0 has to be less
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    than 7 and 1/2.
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    So what values of h are going
    to have less than a distance
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    from 7 and 1/2?
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    Well, it could be less than 7
    and 1/2 and greater than 0, or
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    equal to 0.
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    So let me put it this way.
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    So h could be less
    than 7 and 1/2.
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    But if it gets too far negative,
    if it goes to
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    negative 3, we're cool, negative
    4, negative 5,
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    negative 6, negative 7, we're
    still cool, but then at
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    negative 8, all of a sudden the
    absolute value isn't going
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    to be less than this.
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    So it also has to be greater
    than negative 7 and 1/2.
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    If you give me any number in
    this interval, its absolute
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    value is going to be less than 7
    and 1/2 because all of these
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    numbers are less than 7
    and 1/2 away from 0.
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    Let me draw it on the number
    line, which they
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    want us to do anyway.
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    So if this is the number line
    right there, that is 0, and we
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    draw some points, let's say
    that this is 7, that is 8,
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    that is negative 7, that
    is negative 8.
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    What numbers are less than
    7 and 1/2 away from 0?
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    Well, you have everything all
    the way up to-- 7 and 1/2 is
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    exactly 7 and 1/2 away, so you
    can't count that, so 7 and
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    1/2, you'll put a circle
    around it.
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    Same thing true for negative 7
    and 1/2, the absolute value,
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    it's exactly 7 and 1/2 away.
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    We have to be less than 7 and
    1/2 away, so neither of those
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    points are going to be included,
    positive 7 and 1/2
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    or negative 7 and 1/2.
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    Now, everything in between is
    less than 7 and 1/2 away from
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    0, so everything else counts.
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    Everything outside of it is
    clearly more than 7 and 1/2
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    away from 0.
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    And we're done.
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Title:
Absolute value inequalities
Description:

U05_L1_T2_we1 : Absolute value inequalities

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Video Language:
English
Duration:
03:27

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