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2003 AIME II Problem 5

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    "A cylindrical log has
    a diameter of 12 inches.
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    A wedge is cut from the log
    by making two planar cuts that
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    go entirely through the log.
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    The first is perpendicular
    to the axis of the cylinder,
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    and the plane of the second
    cut forms a 45 degree angle
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    with the plane of the first cut.
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    The intersection
    of these two planes
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    has exactly one point
    in common with the log.
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    The number of cubic
    inches in the wedge
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    can be expressed as n pi,
    where n is a positive integer.
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    Find n."
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    So let's think about it.
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    So let's just draw what
    they're describing.
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    So we have a
    cylindrical log that
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    has a diameter of 12 inches.
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    So let's draw that.
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    So let me draw it like this.
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    So that is a cross
    section of the log.
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    It has a diameter of 12 inches.
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    So this is 12 inches.
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    And it is a cylinder,
    so it looks like this.
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    That is our log.
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    That is the log in question.
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    A wedge is cut from the log
    by making two planar cuts that
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    go entirely through the log.
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    The first cut is perpendicular
    to the axis of the cylinder.
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    So it would go-- it'd
    really just cut it--
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    it would just cut it straight.
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    That's another way
    to think about it.
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    It's perpendicular to
    the axis of the cylinder.
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    The axis of the cylinder
    goes through the cylinder,
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    like that.
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    I don't want to do
    that; it'll make
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    the diagram a little confusing.
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    If the log was transparent,
    our cut would look like this.
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    This first cut would just go
    through the log like this.
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    It would really just form
    a cross section of the log.
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    So that's the first cut.
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    The first is perpendicular
    to the axis of the cylinder.
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    And the plane of the second
    cut forms a 45 degree angle
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    with the plane of the first cut.
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    So that thing is going to
    come in at a 45 degree angle.
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    So it's going to cut into
    our log something like that.
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    Something like that,
    right over there.
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    The intersection
    of these two planes
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    has exactly one point
    in common with the log.
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    That would be this
    point, right over here.
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    So we need to find the
    number of cubic inches
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    in the wedge, expressed
    as n pi, and then we
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    have to figure out n.
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    So let's draw this wedge, this
    wedge that we've cut out here.
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    So this right here is our wedge.
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    Let me take it out and
    kind of flip it around.
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    So the base of--
    I'll make the base
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    of the wedge the
    perpendicular cut.
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    This cut right over here.
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    So that is the
    base of the wedge.
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    That is our base.
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    And then you can do the top
    of our cut to be the magenta,
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    the 45 degree angle cut.
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    So maybe I'll draw it like this.
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    So it would look
    something like this.
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    I'm trying my best to draw it.
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    That's really the
    hard part, here.
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    So let me draw the
    45 degree angle cut.
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    It's going to look
    something like that, where
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    this angle right over
    here-- so if I were
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    to go-- the diameter of this
    top thing, it's actually,
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    it's not going to
    be a normal circle.
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    It's going to be
    more elliptical.
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    But the diameter
    of this top thing
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    versus the diameter
    of the base, which
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    is the diameter of a
    circle, this right here
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    is going to be a
    45 degree angle.
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    Now when I first
    looked at this problem,
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    there's all sorts
    of temptations here.
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    Maybe you use some calculus.
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    Maybe you use some-- you rotate
    something around some axis
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    to find the volume.
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    Maybe you can take some
    type of average, here.
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    And you probably could
    do something like that.
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    But the easiest
    thing here-- and this
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    is kind of-- whenever
    you see these kind
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    of competition-type
    math problems--
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    and this comes from
    the 2003 AIM exam--
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    is that there should be
    a quick way to do it.
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    And for this exam,
    particular, you
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    shouldn't have to use
    any type of calculus.
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    And so, if you find
    yourself doing something
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    tedious and hairy,
    you're probably not
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    seeing the easiest way
    to do this problem.
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    And this problem is actually
    ridiculously easy to do,
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    if you just see the trick here.
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    And the trick here is,
    instead of just directly
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    trying to solve for the volume
    of this figure, right here,
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    take another one of these guys,
    and flip it over, and put it
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    on top of him.
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    So let's say, if
    you did that, you
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    would have another thing on
    top of it, just like that.
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    So if I just took
    two of these wedges
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    and stacked them on top of each
    other-- flipped one of them
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    and stacked them on top of each
    other, it would look like that.
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    This is another
    wedge right here.
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    So I took their angled
    faces and put them
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    right on top of each other.
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    And so if you took two wedges
    together, flip one of them,
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    and put it on top of the
    other, what do you get?
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    So the equivalent-- I could
    draw the green wedge right over
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    here.
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    The green wedge
    would look like this,
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    where its base looks like this.
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    So what would two wedges put in
    this configuration look like?
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    Well, it's just a cylinder, now.
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    And it now is a cylinder.
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    So this is a cylinder
    with a diameter of 12.
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    So that diameter is 12.
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    But in order to figure out
    the volume of a cylinder,
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    you still need to figure out
    the height of the cylinder.
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    You still have to figure out
    this length, right over here.
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    You still have to figure out
    what the height is equal to.
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    You have to figure out what
    this length, right over here,
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    is equal to.
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    And that's where the
    45 degrees helps us.
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    Well, the 45 degrees
    already helped us,
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    because if you flipped the
    thing over and put it on top,
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    it forms a nice cylinder for us.
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    If it was another
    angle, it wouldn't
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    have been a nice, clean
    cylinder, like this.
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    But the 45 degrees also
    tells us what this height is.
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    And let's just think about
    it, here, for a second.
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    This triangle that I had
    drawn, in the beginning--
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    let me draw this in--
    well, I already used blue.
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    Let me draw it in yellow.
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    So if I were to
    take the diameter
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    of the angled surface-- and
    once again, it's not a circle,
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    but it's kind of a
    stretched-out circle--
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    and I took the
    diameter of the base,
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    they form a 45 degree angle.
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    So this is 45 degrees.
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    This right here is also
    going to be 45 degrees.
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    This length, over
    here, we know--
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    we know this length, right
    over here, is going to be 12.
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    Now, this right here
    is a 45-45-90 triangle.
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    Let me draw it like this.
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    I could draw it like this.
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    This right here is
    45-45-90 triangle.
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    And you might say, how
    did I know that's 45?
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    Well, this is going to be a
    right angle, right over here.
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    And the sum of the angles
    have to add up to 180.
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    And then, if you have
    45 and 90 already, then
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    this one has to be 45 degrees.
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    And in 45-45-90 triangle, this
    side is equal to that side.
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    It is an isosceles triangle.
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    The two base angles
    are the same,
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    so the two sides are
    going to be the same.
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    So if this side, right
    over here, is 12,
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    then this side, right
    over here-- this side,
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    right over here is 12.
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    So the height is going
    to be equal to 12.
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    So let's figure out the
    volume of this cylinder that's
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    essentially two
    wedges, and then we
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    can take half of that to
    find the volume of one wedge.
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    And to find the
    volume of a cylinder,
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    you just have to find the area
    of the top of the cylinder.
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    And to find that, it's going to
    be pi times the radius squared.
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    The radius here is 6, 1/2 of 12.
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    So the area is pi r squared.
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    So it's 36 pi--
    that's that area--
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    times the height-- times 12.
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    And so the whole
    volume, our volume
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    is going to be equal
    to-- what's that?
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    360 plus 70.
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    Let me just multiply it out.
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    I don't want to make
    a careless mistake.
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    36 times 12.
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    36 times 2 is 72.
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    1 times 36 is 36.
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    2, 13, 4.
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    So it's 432 pi.
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    Now we have to be very careful.
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    This is the volume
    of two wedges.
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    So this is the volume of
    two wedges, I could call it.
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    So the volume of one wedge,
    is going to be 1/2 of this.
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    Let me do this in
    a different color.
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    The volume of one wedge is going
    to be 1/2 of this, or 216 pi.
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    And so if we want to
    find n, because they say,
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    the number of cubic
    inches in the wedge
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    can be expressed as n pi.
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    It's 216 pi, where n
    is a positive integer.
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    Find n.
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    Well, we just figured
    that out. n is 216.
Title:
2003 AIME II Problem 5
Description:

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Video Language:
English
Team:
Khan Academy
Duration:
08:14

English subtitles

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