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SAT Prep: Test 5 Section 9 Part 3

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    Welcome back.
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    I'm on problem number 10.
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    Phillip used 4 pieces of masking
    tape, each 6 inches
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    long, to put up each
    of his posters.
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    So this is per poster.
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    Good enough.
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    Phillip had a 300-foot roll of
    masking tape when he started.
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    So he starts at 300 feet.
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    I can already tell you that
    some unit conversion will
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    happen, because they're talking
    about 6 inches here
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    and they're talking about
    300 feet here.
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    If no tape was wasted, which
    of the following represents
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    the number of feet--and they
    underline it-- of masking tape
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    that was left on the roll after
    he put up the n posters?
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    And they actually tell us that
    12 inches are equal to a foot
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    in case you aren't
    from this planet.
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    So how do we do this?
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    So he's going to put
    up n posters.
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    So he's going to start
    off-- well, how much
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    tape will he use?
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    So for each of those n posters,
    how much will he use?
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    He uses 4 pieces
    times 6 inches.
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    But we want to go into feet.
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    We want to know how many
    feet are left.
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    So let's just convert
    immediately to feet.
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    6 inches is equal to
    how many feet?
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    Well, it's half a foot.
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    6/12 inches.
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    So it equals 1/2 foot.
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    So he does 4 pieces for each
    poster, and each of those
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    pieces is 1/2 foot.
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    And now we're immediately
    in feet length.
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    So this is how much he uses.
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    So he will use-- so 4
    times 1/2 is just 2.
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    So he uses 2n feet.
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    So if he starts with 300, the
    amount that he has left is
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    what he started with
    minus what he used.
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    He used 2n.
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    So he starts with 300 feet minus
    2n feet, so that's the
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    expression.
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    That's choice B.
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    Next problem.
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    Problem 11.
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    I'll switch to magenta.
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    In the x, y coordinate plane,
    line m is the reflection of
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    line l about the x-axis.
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    If the slope of m-- so m slope--
    is equal to minus 4/5,
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    what is the slope of l?
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    So you should hopefully be able
    to do this on the real
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    exam without having
    to draw it.
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    Or you could actually just draw
    a really quick and dirty
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    one, and that actually
    probably would
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    do the job for you.
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    So minus 4/5.
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    That means for every
    5-- and it's a
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    reflection about the x-axis.
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    So let's draw a line m.
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    Now let's just assume that
    the origin's here.
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    They don't tell us that,
    but they don't
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    tell us it's not that.
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    So that's zero, one, two,
    three, four, five.
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    And this is one, two,
    three, four.
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    Let me do it here.
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    One, two, three, four.
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    I just want to draw it
    so you understand.
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    So 4, minus 4, this is 5.
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    So we know line m.
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    For every line m, for every
    5 it goes to the right,
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    it goes down 4.
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    So this could be a legitimate
    line m right here.
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    It could be like this.
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    Line m could look like that.
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    So a reflection about the
    x-axis, if I were to reflect
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    it about the x-axis.
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    This is the x-axis right here,
    so I just want to take its
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    mirror image, or flip
    it over the x-axis.
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    It would look like this.
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    Oh, I thought I was using
    the line tool.
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    It would look like this.
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    I'm still not using
    the line tool.
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    Now, I'm using the line tool.
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    It would look like
    that, right?
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    So what's the slope here?
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    Well, for every 5 I go to
    the right, I move up 4.
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    So change in y.
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    Let me make sure this is
    line m, this is line l.
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    Change in y over change in
    x for line l is equal to
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    positive 4/5.
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    It shouldn't take you
    that long to do it.
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    One thing that you could just
    do as well, you could just
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    draw a quick and dirty one.
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    It's like, well, if I have
    something with a negative
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    slope-- let's say I have
    a negative, really
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    shallow slope like that.
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    If I flip it, it's going to have
    the same slope, but it's
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    going to be a positive slope,
    but it's still going to be
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    shallow, so it's going to
    be the same magnitude.
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    You'll flip the sign.
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    So the answer is B, 4/5.
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    But I did this just to give
    you the intuition.
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    The next problem.
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    Or to let you know why you got
    it wrong, if you got it wrong.
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    Anyway.
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    Problem number 12.
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    If n is equal to 3p, for what
    value of p is n equal to p?
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    This is kind of crazy.
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    And at first, I was like,
    what are they saying?
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    And then I read one
    of the choices.
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    Because no matter what,
    n is equal to 3p.
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    There's no circumstance--
    well, oh, sorry.
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    I was incorrect.
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    There is a circumstance in
    which n is equal to 3p.
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    Well, what's the circumstance?
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    Well, you might initially say,
    well, as long as p is not 0, n
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    is going to be exactly
    3 times p.
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    But then in our statement, I
    just told you the answer.
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    They both can be 0.
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    If p is 0, then 3
    times 0 is 0.
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    So there's no real
    algebra there.
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    It's just kind of to realize
    that 0 is a choice.
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    And if you looked at the
    choices, you'd immediately see
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    choice A is 0.
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    Try it out.
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    You say, oh, well, if p is
    0, then n is also 0.
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    So then n would equal p.
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    So next problem.
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    Problem 13.
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    That was one of those problems
    that in some ways are so easy
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    that you waste time
    on it, making sure
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    you didn't miss something.
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    Let's draw what they drew.
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    So we have a line like that.
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    I have a line like that.
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    Then I have a line like that.
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    And this is line l.
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    This is y degrees.
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    This is line m.
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    This is x degrees, and this
    is line n right here.
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    In the figure above, if z--
    oh, they tell us this is z
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    right here.
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    In the figure above, if z is
    equal to 30, what is the value
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    of x plus y?
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    x plus y is what?
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    Well, what can we figure out?
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    What do we know about this
    angle right here?
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    It's supplementary
    to y, right?
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    So this is kind of the angle
    game, but we're going to have
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    a little bit more variables
    than normal.
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    It's supplementary to y, so this
    is going to be 180 minus
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    y because y plus this
    angle are going to
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    have to equal 180.
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    And for the exact same reason,
    this angle right here
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    is 180 minus x.
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    And what do we know?
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    We know this angle plus this
    angle plus z is equal to 180.
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    So let's write that down.
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    This angle, 180 minus y, plus
    this angle, plus 180 minus x,
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    plus z is equal to 180
    because they're
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    all in the same triangle.
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    So let's try our best
    to simplify this.
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    Well, we could immediately get
    rid of one of the 180's on
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    that side, and that becomes 0.
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    z is 30, right?
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    So let's simplify it.
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    We get minus y minus x, and
    then you have 180 plus 30,
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    plus 210, is equal to 0.
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    Now let's add x and
    y to both sides.
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    I'm kind of skipping a step.
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    You could add x to both sides
    and then add y to both sides.
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    But if you add x and y to both
    sides, you get 210 is
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    equal to x plus y.
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    And that's the answer.
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    They want to know what
    x plus y is.
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    And that is choice D.
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    And so the trick here is really
    saying, well, they
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    only give us z.
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    The only thing I know is that
    z is in a triangle with this
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    angle and this angle.
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    And let me express those two
    angles in terms of x and y,
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    because they are supplementary
    to x and y.
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    See you in the next video.
Title:
SAT Prep: Test 5 Section 9 Part 3
Description:

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Video Language:
English
Team:
Khan Academy
Duration:
09:36

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