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Welcome back.
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I'm on problem number 10.
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Phillip used 4 pieces of masking
tape, each 6 inches
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long, to put up each
of his posters.
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So this is per poster.
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Good enough.
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Phillip had a 300-foot roll of
masking tape when he started.
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So he starts at 300 feet.
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I can already tell you that
some unit conversion will
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happen, because they're talking
about 6 inches here
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and they're talking about
300 feet here.
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If no tape was wasted, which
of the following represents
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the number of feet--and they
underline it-- of masking tape
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that was left on the roll after
he put up the n posters?
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And they actually tell us that
12 inches are equal to a foot
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in case you aren't
from this planet.
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So how do we do this?
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So he's going to put
up n posters.
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So he's going to start
off-- well, how much
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tape will he use?
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So for each of those n posters,
how much will he use?
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He uses 4 pieces
times 6 inches.
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But we want to go into feet.
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We want to know how many
feet are left.
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So let's just convert
immediately to feet.
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6 inches is equal to
how many feet?
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Well, it's half a foot.
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6/12 inches.
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So it equals 1/2 foot.
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So he does 4 pieces for each
poster, and each of those
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pieces is 1/2 foot.
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And now we're immediately
in feet length.
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So this is how much he uses.
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So he will use-- so 4
times 1/2 is just 2.
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So he uses 2n feet.
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So if he starts with 300, the
amount that he has left is
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what he started with
minus what he used.
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He used 2n.
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So he starts with 300 feet minus
2n feet, so that's the
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expression.
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That's choice B.
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Next problem.
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Problem 11.
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I'll switch to magenta.
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In the x, y coordinate plane,
line m is the reflection of
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line l about the x-axis.
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If the slope of m-- so m slope--
is equal to minus 4/5,
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what is the slope of l?
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So you should hopefully be able
to do this on the real
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exam without having
to draw it.
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Or you could actually just draw
a really quick and dirty
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one, and that actually
probably would
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do the job for you.
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So minus 4/5.
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That means for every
5-- and it's a
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reflection about the x-axis.
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So let's draw a line m.
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Now let's just assume that
the origin's here.
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They don't tell us that,
but they don't
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tell us it's not that.
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So that's zero, one, two,
three, four, five.
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And this is one, two,
three, four.
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Let me do it here.
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One, two, three, four.
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I just want to draw it
so you understand.
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So 4, minus 4, this is 5.
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So we know line m.
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For every line m, for every
5 it goes to the right,
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it goes down 4.
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So this could be a legitimate
line m right here.
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It could be like this.
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Line m could look like that.
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So a reflection about the
x-axis, if I were to reflect
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it about the x-axis.
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This is the x-axis right here,
so I just want to take its
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mirror image, or flip
it over the x-axis.
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It would look like this.
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Oh, I thought I was using
the line tool.
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It would look like this.
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I'm still not using
the line tool.
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Now, I'm using the line tool.
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It would look like
that, right?
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So what's the slope here?
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Well, for every 5 I go to
the right, I move up 4.
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So change in y.
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Let me make sure this is
line m, this is line l.
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Change in y over change in
x for line l is equal to
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positive 4/5.
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It shouldn't take you
that long to do it.
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One thing that you could just
do as well, you could just
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draw a quick and dirty one.
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It's like, well, if I have
something with a negative
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slope-- let's say I have
a negative, really
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shallow slope like that.
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If I flip it, it's going to have
the same slope, but it's
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going to be a positive slope,
but it's still going to be
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shallow, so it's going to
be the same magnitude.
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You'll flip the sign.
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So the answer is B, 4/5.
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But I did this just to give
you the intuition.
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The next problem.
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Or to let you know why you got
it wrong, if you got it wrong.
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Anyway.
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Problem number 12.
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If n is equal to 3p, for what
value of p is n equal to p?
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This is kind of crazy.
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And at first, I was like,
what are they saying?
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And then I read one
of the choices.
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Because no matter what,
n is equal to 3p.
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There's no circumstance--
well, oh, sorry.
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I was incorrect.
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There is a circumstance in
which n is equal to 3p.
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Well, what's the circumstance?
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Well, you might initially say,
well, as long as p is not 0, n
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is going to be exactly
3 times p.
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But then in our statement, I
just told you the answer.
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They both can be 0.
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If p is 0, then 3
times 0 is 0.
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So there's no real
algebra there.
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It's just kind of to realize
that 0 is a choice.
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And if you looked at the
choices, you'd immediately see
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choice A is 0.
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Try it out.
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You say, oh, well, if p is
0, then n is also 0.
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So then n would equal p.
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So next problem.
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Problem 13.
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That was one of those problems
that in some ways are so easy
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that you waste time
on it, making sure
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you didn't miss something.
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Let's draw what they drew.
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So we have a line like that.
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I have a line like that.
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Then I have a line like that.
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And this is line l.
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This is y degrees.
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This is line m.
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This is x degrees, and this
is line n right here.
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In the figure above, if z--
oh, they tell us this is z
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right here.
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In the figure above, if z is
equal to 30, what is the value
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of x plus y?
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x plus y is what?
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Well, what can we figure out?
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What do we know about this
angle right here?
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It's supplementary
to y, right?
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So this is kind of the angle
game, but we're going to have
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a little bit more variables
than normal.
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It's supplementary to y, so this
is going to be 180 minus
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y because y plus this
angle are going to
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have to equal 180.
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And for the exact same reason,
this angle right here
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is 180 minus x.
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And what do we know?
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We know this angle plus this
angle plus z is equal to 180.
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So let's write that down.
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This angle, 180 minus y, plus
this angle, plus 180 minus x,
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plus z is equal to 180
because they're
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all in the same triangle.
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So let's try our best
to simplify this.
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Well, we could immediately get
rid of one of the 180's on
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that side, and that becomes 0.
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z is 30, right?
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So let's simplify it.
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We get minus y minus x, and
then you have 180 plus 30,
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plus 210, is equal to 0.
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Now let's add x and
y to both sides.
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I'm kind of skipping a step.
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You could add x to both sides
and then add y to both sides.
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But if you add x and y to both
sides, you get 210 is
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equal to x plus y.
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And that's the answer.
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They want to know what
x plus y is.
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And that is choice D.
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And so the trick here is really
saying, well, they
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only give us z.
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The only thing I know is that
z is in a triangle with this
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angle and this angle.
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And let me express those two
angles in terms of x and y,
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because they are supplementary
to x and y.
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See you in the next video.