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- [Instructor] Function g can
be thought of as a translated
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or shifted version of f of
x is equal to x squared.
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Write the equation for g of x.
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Now, pause this video,
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and see if you can work
this out on your own.
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All right, so whenever I think
about shifting a function,
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and in this case, we're
shifting a parabola,
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I like to look for a distinctive point.
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And on a parabola, the vertex is going
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to be our most distinctive point.
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And if I focus on the vertex of f,
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it looks like if I shift that to the right
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by three,
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and then if I were to shift that down
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by four,
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at least our vertices would overlap.
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I would be able to shift the vertex
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to where the vertex of g is.
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And it does look,
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and we'll validate this, at
least visually, in a little bit,
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so I'm gonna go minus four
in the vertical direction,
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that not only would it
make the vertices overlap,
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but it would make the
entire curve overlap.
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So we're going to make,
we're gonna first shift to
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the right
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by three.
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And we're gonna think about how
would we change our equation
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so it shifts f to the right by three,
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and then we're gonna shift down by four.
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Shift down
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by four.
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Now, some of you might
already be familiar with this,
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and I go into the intuition
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in a lot more depth in other videos.
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But in general,
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when you shift to the right by some value,
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in this case, we're shifting
to the right by three,
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you would replace x with x minus three.
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So one way to think about this
would be y is equal to f of
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x minus three,
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or y is equal to, instead
of it being x squared,
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you would replace x with x minus three.
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So it'd be x minus three squared.
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Now, when I first learned this,
this was counterintuitive.
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I'm shifting to the right by three.
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The x-coordinate of my vertex
is increasing by three,
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but I'm replacing x with x minus three.
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Why does this make sense?
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Well, let's graph the shifted version,
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just to get a little
bit more intuition here.
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Once again, I go into much more
depth in other videos here.
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This is more of a worked example.
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So this is what the shifted
curve is gonna look like.
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Think about the behavior that we want,
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right over here, at x equals three.
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We want the same value
that we used to have
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when x equals zero.
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When x equals zero for the original f,
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zero squared was zero.
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Y equals zero.
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We still want y equals zero.
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Well, the way that we can do that is
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if we are squaring zero,
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and the way that we're gonna square zero
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is if we subtract three from x.
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And you can validate that at other points.
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Think about what happens
now, when x equals four.
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Four minus three is one squared.
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It does indeed equal one.
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The same behavior that you used to get
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at x is equal to one.
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So it does look like we have
indeed shifted to the right
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by three when we replace
x with x minus three.
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If you replaced x with x plus three,
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it would have had the opposite effect.
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You would have shifted
to the left by three,
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and I encourage to think about
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why that actually makes sense.
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So now that we've shifted
to the right by three,
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the next step is to shift down by four,
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and this one is little bit more intuitive.
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So let's start with our
shifted to the right.
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So that's y is equal to
x minus three squared.
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But now, whatever y value we were getting,
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we want to get four less than that.
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So when x equals three, instead
of getting y equals zero,
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we want to get y equals
four less, or negative four.
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When x equals four,
instead of getting one,
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we want to get y is
equal to negative three.
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So whatever y value we were getting,
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we want to now get four less than that.
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So the shifting in the vertical direction
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is a little bit more intuitive.
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If we shift down, we subtract that amount.
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If we shift up, we add that amount.
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So this, right over here,
is the equation for g of x.
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G of x is going to be equal
to x minus three squared
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minus four.
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And once again, just to review,
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replacing the x with x
minus three, on f of x,
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that's what shifted,
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shifted
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right
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by three,
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by three.
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And then, subtracting the four,
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that shifted us down by four,
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shifted
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down
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by four,
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to give us this next graph.
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And you can visualize, or
you can verify visually,
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that if you shift each of these
points exactly down by four,
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we are,
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we are indeed
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going to overlap on top of g of x.