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Welcome back.
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So I did this ahead of time, so
as to not waste your time
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drawing it.
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The question says, a merchant
sells three types of clocks
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that chime as indicated
by the check marks
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in the table above.
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What is the total number of
chimes of the inventory of
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clocks in the 90-minute
period?
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And we're talking about
7:15 to 8:45.
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So let's just make sure we
understand this chart.
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So we have clocks of
type a, b, and c.
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This is the number of
each of those clocks
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that the store has.
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Now these n times on the nth
hour, that means when it turns
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7 o'clock, it's going to
chime seven times.
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When it turns 8 o'clock, it's
going to chime eight times, et
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cetera, et cetera.
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This is once on the hour,
so right at the hour
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does just one chime.
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And then these do once
on the half hour.
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So let's see, we have
clock a times 10.
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And how many times is each of
the clock a's going to chime
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between this period?
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Well, it does n times
on the nth hour.
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So between 7:15 and 8:45,
there's only one hour that
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happens, which is 8 o'clock.
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And at 8 o'clock it's going
to chime n times.
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It's going to chime eight
chimes at 8 o'clock.
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And it also does one
on the half hour.
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So what half hours are there?
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Well there's 7:30 and there's
8:30 that pass up.
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So there are two half hours.
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It's going to chime at 7:30
and 8:30, each of these.
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So then plus 2, once at 7:30
and once at 8:30, times 10,
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because there's ten clocks.
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Let's see, b times 5 clocks,
n times on the nth hour.
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Well, once again that's eight
chimes at 8:00, and it doesn't
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do anything else.
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So times 5.
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And then finally c times
three clocks.
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It doesn't do this n
times the nth hour.
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It does once on the hour.
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It's going to do it
once at 8 o'clock.
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And then once on the half
hour, so plus 1 at
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7:30 plus 1 at 8:30.
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So that's 3 times
three clocks.
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So what's this?
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It's 8 plus 2.
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Eight chimes plus two chimes.
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So that's ten chimes per
clock times 10 is
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equal to a 100 chimes.
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Eight chimes per clock
times five clocks
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is equal to 40 chimes.
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And then three chimes per clock
times three clocks is
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equal to 9.
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You add all this up together,
and the whole store in this
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time period, if I haven't made
a mistake, will chime 149 or
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there'll be 149 chimes of the
inventory of clocks in this
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90-minute period.
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Next question.
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So they draw a bunch
of random things.
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I'll just replace them with
numbers because that's easier
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for me to think, or letters
a, b, c, d, and e.
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I mean those pictures
are useless.
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They say, if the five cards
shown above are placed in a
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row so that the shaded box, but
I'll call that c, so that
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c is never at either end, how
many different arrangements
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are possible?
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Well, this is how I
think about it.
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c is the most restricted.
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Let's say that we're placing
them in order.
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Let's say these are the spots.
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They're in a row.
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1, 2, 3, 4, 5.
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And when we come along,
we have c.
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We know that c can't be
placed here, and it
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can't be placed here.
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So it can only be placed in
one of these three spots.
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So there's three possible
situations
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where c can be placed.
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Let's say you place c in one
of these three spots.
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Now it's our turn to place a.
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How many spots are
left to place a?
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Well, one of these three is
going to be taken by c.
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But then a can be in any
of the other four.
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So then there's four
possibilities for a.
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And then once you place a, then
for b, well two of the
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spots are going to be
taken up in b, so
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there's three spots left.
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So there's three possibilities
for b.
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And then there's only
two openings for d.
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And then there's
only one for e.
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So if you multiply this out,
you get 3 times 4 is 12.
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12 times 3 is 36.
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36 times 2 is 72.
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So there are 72 possible
arrangements where the middle
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card or that grey card is never
placed at either end.
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That's how I always think about
these because you just
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think about placing them-- well
this first one can only
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go in three-- well
you get the idea.
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Hopefully you get the idea.
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Well, that's this section,
so I will see
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you in the next section.
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Have fun.
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