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>> Okay. Now let's talk about what happens to voltage and current, 
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and we first turn on a voltage source let's say we first took up the battery, 
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it's going to start putting charges on top of this plate, 
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which is then going to force charges away from this plate and again this flow of current. 
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Current starts to flow immediately. 
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Its largest at the start and gradually as the charges fill up on his plate, 
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there'll be no current at the end when the plates are all full. 
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So, current begins to start immediately 
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and is largest at the beginning and then falls down to zero. 
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Meanwhile, the current starts 
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immediately but then when the plates are full it goes to zero. 
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So, what does that look like the current? 
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Here is a picture of an interesting circuit where we have a switch that's going to 
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take this 10-volt battery and turn it on to start charging this capacitor. 
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We know that the current is dq dt that that's also 
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equal to the capacitance times the change in voltage with respect to time. 
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So, as I turned this on, let's see what's going to happen. 
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When I first turn it on, 
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it's going to go up to its peak current and then it's 
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going to gradually go down to zero as the plates get full. 
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In fact, it's peak current is going to occur up 
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here when the capacitor is effectively a short circuit. 
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So, look right here when we first started, 
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all the current can go into that faster. 
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At the very beginning when we had a big change, 
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this capacitor acts like a short circuit. 
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So, what will the current be? 
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It will be this voltage divided by that resistance, 
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and in fact, right there, that's what it is. 
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Is simply what everything at time t equal to zero, 
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and then we have this exponential decay. 
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The speed of the decay depends on something that we call the time constant, 
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tau that is equal to R times C for a series resistor capacitor circuit. 
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If I have for example, 
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R is one kilo ohm, 
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C is one microfarad and this voltage, 
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this is exactly what my currents would look like, 
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starting out at VS over R and ending at zero. 
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The time constant tells us that as this exponential decreases, 
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it will reach 36 percent of its original value, 
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at the time constant tau equals RC. 
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Okay. Now what happens when we first turn on the voltage. 
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Well, originally there are no charges on the top plate, 
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there are no charges on the bottom plate, 
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and so the total voltage across here would start out as zero. 
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But as we gradually add up all of these charges, 
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then there's going to be a large voltage at the end. 
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So, the voltage is the integral of the current over time with the capacitance inverted. 
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So, right here's my case. 
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I'm going to be integrating the current over time. 
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This is what it looks like. 
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My voltage starts out at zero and it ends up that Vs. 
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The voltage is one over the capacitance times the integral of time, 
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and if you look at that, that's going to be Vs times 1 minus e to the minus t over tau. 
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Again, it's the same time constant. 
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So, the voltage reaches 66 percent of its value at the time constant RC. 
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So, here's the answer to what does a capacitor do to a voltage and current? 
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With the current plot we looked at and here's the voltage plot. 
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Steady state would be long time, 
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like after the switch has been closed for a long time, 
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and that would say there would be no current and that there would be a large voltage. 
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At time t equal to zero when there is a very big change, 
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the capacitor acts as a short circuit. 
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The time t equal to infinity when it's all charged up, 
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it acts like an open circuit. 
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Now what are the implications of that? 
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When we have something that we want to charge and discharge, 
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instead of being able to do a square wave like they might have liked, 
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we always end up with some stray capacitance and make 
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our square wave looks like this charging, discharging plot. 
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How do we use capacitors? 
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Here are two examples where we use them for energy storage. 
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This disposable camera for example has two batteries and a capacitor 
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inside in order to make the flash that you use when you take a picture. 
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The capacitance between the clouds and the earth 
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is what creates the ability for lightning to strike. 
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We can also use capacitors to stabilize power for example to the reduce ripple. 
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Here's a case where we've put in a power supply and let's suppose that 
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sometimes it was a little more than nine volts and sometimes it was a little less, 
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but that our circuit over here wants exactly nine volts. 
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In that case, this capacitor can take a little bit of that 
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away when it's too high and return a little bit back, when it is low. 
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The capacitor effectively storing the excess and release it when it is needed. 
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Now let's talk about low pass and high pass filters. 
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A low pass signal is going to allow 
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a constant value to go through but not the high frequency noise. 
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So, here's a series RC circuit, 
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where remember that if I have a change, 
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a fast changing thing that this thing acts like an open circuit. 
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So, it allows the low frequency to go through but not the high frequency. 
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Here's another example. 
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What does this look like without the capacitor? 
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Looks like an inverting amplifier. 
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Now let's suppose that we tried to send a DC value through. 
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Well, the DC value, 
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this capacitor still acts like an open circuit. 
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So, it just acts like an inverting amplifier that you've always seen before. 
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The low pass signal goes through, 
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but now what if I wanted to send a grasp changing a high frequency signal. 
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In that case, the capacitor would act like a short circuit. 
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I'll be shorting out my R2. 
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Remember what the amplification for inverting amplifiers, 
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remember that the gain is equal to minus RF divided by RS, 
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and then in this case the RF is R2, 
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but if I made RF equal to zero, 
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then my game would be zero. 
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So, the high frequency signal that will come out with the zero. 
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The capacitor allows the low frequency to go through this circuit, 
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goes through R2 that takes the high frequency through here and basically equals to zero. 
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This allows the capacitor to work as an integrator. 
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Notice here's the RC circuit right here. 
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It's taking this square wave and it's producing this output. 
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Remember what integration does? 
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It finds the area under the curve. 
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When I first made my step up the area is zero, 
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and gradually as I'm adding up, adding up, 
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adding up the area of the curve, 
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it builds up the maximum voltage. 
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When I take a negative value, 
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it starts subtracting off that value. 
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So, there's no charging discharging though. 
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I can literally use this capacitor circuit to integrate signals that are coming in. 
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Here's a high pass filter design or DC block. 
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In this case, notice I've just switched the location of my capacitor and my resistor. 
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If I were sending a DC signal through, 
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this capacitor it would look like an open circuit and my output voltage would be zero. 
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Nothing will come out, but if I had a high frequency signal from 
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this capacitor would act like a short circuit and the full voltage would come out. 
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Now here's my inverting amplifier again. 
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Remember, that the gain is equal to minus RF which is R2 in 
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this case divided by RS which is R1. 
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Well, if I have a DC signal my RS is infinity, 
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and so my full voltage comes out. 
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If I have an AC or very high frequency signal, I have a short circuit, 
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and that means that I get no frequency, no signal out. 
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So, high pass signals come through but low pass signals do not. 
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That allows me to do differentiation. 
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That means that I want to emphasize the changes. 
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Here's an up and here's a down. 
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If I did the derivative, 
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I would see this and I will see that for this is what my capacitor does, 
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it seems a little but there's my first step and here's my second step. 
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This is the differentiation of the square length. 
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So, basically we have covered these four topics. 
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What is capacitance? 
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How does it relate to current and charges? 
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How do the various parameters of 
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the capacitor matter and what does it do to a voltage and a current? 
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Thank you very much for your attention.