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Trigonometry word problems (part 2)

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    Welcome back.
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    I was just chugging through the
    hairy math of this problem,
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    which I think we're
    almost done.
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    But as I was saying, we're
    just simplifying this.
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    We have 25 times sine
    squared of 15 plus
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    cosine squared of 15.
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    I said well, that's
    an identity, right?
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    Remember, I
    undistributed this 25.
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    So sine squared plus cosine
    squared of the same angle is 1.
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    So I can simplify this to --
    and I will now change colors
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    just to be arbitrary.
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    So, 25 plus 100 minus 100
    cosine of 15 degrees, and this
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    is what m squared is equal to,
    and I used the variable m
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    because it stands for nothing
    relevant to this problem.
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    And that equals 125 minus
    100 cosine of 15 degrees.
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    Now I have to use a calculator
    if I want to get a real answer.
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    But the possibility for error
    is much lower now that I've
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    hopefully simplified it.
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    So I could use my calculator,
    and the cosine of 15 degrees --
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    I'll write that down here, you
    could just use a calculator or
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    table to figure that out --
    it is equal to 0.96593.
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    So this term would be 125
    minus 100 times this, right?
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    So what's 100 times this?
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    Well that's just minus 96.593,
    right, I just did 100 times
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    the cosine of 15 degrees.
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    And now let me use the
    trusty calculator to
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    figure out what that is.
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    So if I say 125 minus
    96.593, I get 28.407.
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    So I have m squared
    is equal to 28.407.
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    And so m is equal to the
    square root of that.
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    It's going to be 5 point
    something, right?
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    Square root.
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    5.3298.
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    So 5.33.
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    m is equal to 5.33.
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    And we're done.
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    The poor guy -- he's got to
    figure out the right direction
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    to go in and he probably has to
    think about the current in all
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    of that, but he hasn't asked us
    that question so we
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    won't answer it.
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    But all he has left
    to go is 5.33 miles.
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    So he only has to go an extra
    0.33 miles than he would have,
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    had he gone in the right
    direction from the get-go.
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    Hopefully that
    makes some sense.
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    If it doesn't, well, not much
    I can do, but maybe you
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    can re-watch this video.
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    Have fun.
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Title:
Trigonometry word problems (part 2)
Description:

The second part of the problem of the off-track ship captain

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Video Language:
English
Duration:
02:51

English subtitles

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