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Structural (constitutional) isomers

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    - [Voiceover] Let's
    say we're asked to draw
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    all the structural isomers that have the
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    molecular formula C5H12.
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    The word "isomer" means same parts.
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    And so we're talking about
    the same number of atoms.
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    All of our structural
    isomers are gonna have
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    five carbons and 12 hydrogens.
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    Our isomers are gonna differ
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    in how those atoms are
    connected to each other.
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    So they differ in terms
    of their structure.
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    And that's why we call
    them structural isomers.
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    We can also call them
    constitutional isomers.
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    So we need five carbons.
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    So for our first isomer we could just draw
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    five carbons in a chain.
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    So here are my five carbons in a chain.
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    And you should have already seen the video
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    on bond line structures
    before you watch this one.
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    So let's draw those five carbons
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    and let's double check and make sure
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    we have the correct number of hydrogens.
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    The carbon on the far
    left has three hydrogens,
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    so here we have our three hydrogens.
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    Next carbon has two,
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    same with the next carbons,
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    so two for this one,
    two for the next carbon,
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    and finally three hydrogens
    for the last carbon.
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    So let's count up everything
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    and make sure we have to
    correct molecular formulas.
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    We have one, two, three,
    four, five carbons.
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    So that's C5.
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    And then we should have 12 hydrogens.
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    Here's three plus two gives us five,
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    plus two gives us seven,
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    plus two gives us nine,
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    and then we have three
    more for a total of 12.
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    So, C5H12 is the molecular
    formula for this compound.
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    Let's draw another structural isomer
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    that has the same molecular formula.
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    So instead of drawing
    five carbons in a chain
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    now we have to draw four.
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    So let's start by drawing four carbons.
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    We need a total of five carbons
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    so we need to show the fifth carbon
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    branching off of our chain.
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    So we could show the fifth carbon
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    branching off of our chain here.
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    Let's draw in those five carbons.
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    So here we have our five carbons.
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    Let's count up hydrogens.
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    Carbon on the left has three,
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    so three hydrogens here.
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    Three hydrogens on this top carbon.
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    There's only one hydrogen on this carbon,
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    two hydrogens on this one,
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    and finally three
    hydrogens on this carbon.
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    So let's count up our atoms.
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    So let's use red for this one.
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    We have one, two, three
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    four, five carbons.
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    So that's C5.
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    And then for hydrogens we have three here
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    plus three gives us six,
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    plus one gives us seven,
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    plus two gives us nine.
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    And three more for a total of 12.
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    So C5H12 is the molecular
    formula for this compound.
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    So these two drawings represent
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    two different molecules.
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    Both these molecules have
    the molecular formula C5H12.
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    But they differ in terms of
    how those atoms are connected.
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    They differ in terms of their structure.
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    So we call them structural
    isomers of each other.
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    All right, to draw
    another structural isomer,
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    some students might say,
    "We could start with
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    "four carbons in our chain again."
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    And this time,
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    instead of showing a
    branch off of this carbon,
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    we could show a branch off of this carbon.
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    And so a student might draw this structure
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    and say, "Okay, there's a
    different structural isomer."
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    But actually these are
    just two different ways
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    to represent the same molecule.
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    If you analyze that second
    structure that we just drew
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    the connections are the same.
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    We have a CH right here
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    bonded to a CH3, bonded to a CH3,
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    and bonded to a CH2.
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    And the CH2 is bonded to a CH3.
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    That's the same structure as
    what we drew out over here.
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    So it looks like it's
    a different structure.
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    It's a different drawing
    than the one up here,
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    but actually this is
    just two different ways
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    to represent the same molecule.
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    So we have two structural isomers so far.
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    Let's think about one more.
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    So we can no longer do
    four carbons in our chain
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    so we go down to three carbons.
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    So we start with three
    carbons in our chain.
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    We know we need a total of five carbons.
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    So we need to show two more
    carbons added to our chain.
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    And these would have to
    add those two carbons
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    to our central carbon like that.
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    Let's draw out all of our carbons here.
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    And let's add in our hydrogen.
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    So this carbon would have three hydrogens
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    same with this carbon.
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    And the same with this one,
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    and finally the same for this carbon.
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    The carbon in the center, this
    carbon in the center here,
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    already has four bonds.
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    So it doesn't have any hydrogens on it.
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    Let's count up everything.
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    Let's count our carbons first,
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    one, two, three, four,
    five carbons, so C5.
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    And then we have three hydrogens
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    plus three is six plus three is nine
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    plus three is 12.
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    So C5H12 is the molecular formula
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    for this compound.
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    And this is another structural isomer.
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    So it's a different
    molecule from the other two.
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    So we have a total of
    three structural isomers
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    that have the molecular formula C5H12.
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    Now let's draw all of
    the structural isomers
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    that have the molecular formula C3H8O.
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    And we'll start with the molecule
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    we talked about in the
    bond line structure video,
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    so that molecule look like this.
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    We have three carbons
    and then we have an OH
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    coming off of the central carbon.
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    Let's expand that out and make sure
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    that this has the correct
    molecular formula.
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    We have our three carbons.
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    And on the middle carbon we have an OH.
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    So an oxygen bonded to a hydrogen.
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    I'll go ahead and put lone pairs of
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    electrons on this oxygen.
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    How many hydrogens do we need to add
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    to the carbon on the left?
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    Well, we need to add three hydrogen.
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    So we go ahead and draw
    in those three hydrogens.
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    The carbon in the center
    already has three bonds
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    so it needs one more
    so we add one hydrogen
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    to that carbon.
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    And the carbon on the right
    needs three hydrogens.
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    So let's count everything up now.
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    So we'll start with our carbons.
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    We have one, two, three carbons.
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    So that's C3.
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    We have three hydrogens
    here and three here,
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    so that's six plus one is seven,
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    and don't forget about the
    hydrogen on the oxygen for eight.
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    So we have eight hydrogens.
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    And obviously we have one oxygen here.
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    So I went ahead and
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    put in lone pairs of
    electrons on that oxygen.
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    So the molecular formula for this molecule
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    is C3H8O.
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    And if I number this, if
    I said this was carbon 1
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    and this was carbon 2,
    and this was carbon 3,
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    that helps us to draw the
    next structural isomer
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    because we could think about
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    instead of that OH group
    coming off of carbon 2,
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    what if that OH group
    came off of carbon 1?
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    And so let's draw out
    our three carbons here.
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    And now we put our OH group
    coming off of carbon 1.
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    And let's expand this out
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    and draw the Lewis dot structure
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    and make sure that this has
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    the correct molecular formula.
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    So we have three carbons, again, in a row.
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    And then the carbon on the left
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    is bonded to the oxygen.
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    The oxygen is bonded to a hydrogen.
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    I'll put in lone pairs of
    electrons on the oxygen.
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    Now we need to add in
    carbon hydrogen bonds.
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    So this carbon needs two.
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    The next carbon also needs two.
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    And the carbon on the
    end would need three.
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    So that's one, two, and three.
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    When we add everything up
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    let's use blue for that,
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    that's one, two, three carbons.
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    We have C3.
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    We have three hydrogens
    here, plus two is five,
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    plus two is seven, and one here is eight.
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    So C3H8.
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    And then, of course, our oxygen.
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    So C3H8O is the molecular formula.
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    Next.
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    Some students might think, "Okay, well,
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    "we put an OH coming off of carbon 1
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    "but what if I put an
    OH on the other side?"
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    So, over here on the other side.
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    So let's see what would that give us.
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    If I put an OH coming off of that carbon,
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    hopefully it's obvious that these two
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    represent the same molecule.
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    There's no difference in terms of
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    how those two are connected structurally.
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    So this is the same molecule,
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    so two different ways
    to draw the same one.
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    So this is not a new structural isomer.
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    Just a new way of
    looking at this molecule.
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    Now let's draw one more.
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    So we can't put the OH
    on the other carbon.
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    So now we have to figure out
    something else that we can do.
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    Well, we could, this time,
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    put two carbons in a row and
    put an oxygen in between,
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    so putting an oxygen to
    break up our carbon chain.
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    So now this would be
    carbon bonded to carbon
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    bonded to oxygen, bonded to carbon.
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    And then we fill in our hydrogen,
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    so there would be three on this carbon.
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    There would be two on this carbon.
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    There would be three on this carbon.
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    And I could put in lone pairs of electrons
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    on the oxygen like that,
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    and can everything up.
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    So we have one, two, three carbons,
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    so that's C3.
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    We have three hydrogens plus two is five,
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    plus three is eight.
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    So we have the H8.
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    And then, of course, the one oxygen.
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    So this is another structural isomer.
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    Again, some students might say,
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    "Well, we could go like this,"
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    and this would be yet another
    structural isomer like that.
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    But really this is just another
    way to draw this molecule.
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    So it's not a new structural isomer.
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    It has the same connections.
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    So we have a total of
    three structural isomers
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    that have the molecular formula C3H8O.
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    And as you go further in organic chemistry
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    you'll learn that the first
    two isomers we talked about,
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    so this one and this one,
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    the ones that have an OH on it,
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    those are called alcohols.
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    And the last structural
    isomer is called an ether.
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    So we'll worry about that
    more later in other videos.
Title:
Structural (constitutional) isomers
Description:

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Video Language:
English
Duration:
09:52

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