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- [Instructor] We are told
that a van drives around
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a circular curve of radius
r with linear speed v.
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On a second curve of the same radius,
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the van has linear speed 1/3 v.
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And you could view linear
speed as the magnitude
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of your linear velocity.
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How does the magnitude of the
van's centripetal acceleration
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change after the linear speed decreases?
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So pause this video and see
if you can figure it out
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on your own, and I'll give
you a little bit of a hint.
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We know that the magnitude
of centripetal acceleration
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in general is equal to
linear speed squared
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divided by radius.
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The radius of the curve.
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Alright, now let's work
through this together.
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So let's first think
about the first curve.
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So the first curve the
magnitude of our centripetal
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acceleration for curve one,
I have another subscript
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one here, this is around the first curve.
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They tell us that our linear speed is v.
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So we have v squared over and
the radius of that curve is r.
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This is going to be a
straight up v squared over r
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for that first curve.
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The magnitude of our
centripetal acceleration.
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Now what about the second curve?
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So the magnitude of our
centripetal acceleration
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around second curve,
that's what that two is,
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is going to be equal to,
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they tell us we now have
a linear speed of 1/3 v.
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So in our numerator
we're gonna square that,
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1/3 v squared all of that over
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the curve of the same radius.
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So our radius is still r.
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So let's just do a little
algebraic simplification.
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1/3 v times 1/3 v is just going to be
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1/9 v squared.
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So it's going to be 1/9 v squared over r.
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All I did is square this numerator here.
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Or I could write this as
1/9 times v squared over r.
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The reason why I wrote
this in green is because
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this is the exact same thing as this.
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And so this is going to be equal to,
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this is equal to 1/9
times, instead of writing
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v squared over r, I could say hey that's r
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the magnitude of our
centripetal acceleration
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around the first curve.
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The magnitude of our
centripetal acceleration
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around the first curve.
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So how does the magnitude
of the van's centripetal
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acceleration change after
the linear speed decreases?
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Well around the second curve,
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we have 1/9 the magnitude
of centripetal acceleration.
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So we could say the magnitude,
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or I could just say, they already asked us
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how does the magnitude change
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so we could say decreases,
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decreases by a factor
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factor of nine.
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And I wrote it in this language.
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You could say it got
multiplied by a factor of 1/9
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or you could say decreases
by a factor of nine
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because on the Khan Academy exercises
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that deal with this, they
use language like that.
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Let's do another example.
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Here we are told a
father spins his daughter
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in a circle of radius r
at angular speed omega.
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Then the father extends
his arms and spins her
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in a circle of radius two r
with the same angular speed.
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How does the magnitude of
the child's centripetal
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acceleration change when
the father extends his arms?
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Once again pause this
video and see if you can
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figure it out.
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Well the key realization
here and we derived this
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at a previous video, is to
realize that the magnitude
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of centripetal acceleration
is equal to r times
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our angular speed squared.
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And so initially so the
magnitude of our centripetal
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acceleration initially,
I'll do that with a sub i.
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That is going to be equal
to, well they're using
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the same notation.
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We have omega as our angular speed.
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And our radius is r.
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So it's just going to be r omega squared.
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And then when we think about the father,
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he extends his arms.
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So then you have the
magnitude of your centripetal
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acceleration, I could
say final or extended or
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I'll just say final sub f.
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What does that going to be equal to?
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Well now our radius, the
radius of our circle is two r.
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So it's going to be two r
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and they say the same angular speed.
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So our angular speed is still omega.
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Two r omega squared.
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Well this part right over
here r omega squared,
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that was just the magnitude of our initial
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centripetal acceleration.
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That was the magnitude of our initial
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centripetal acceleration.
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And so you see that the magnitude of our
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centripetal acceleration, has
increased by a factor of two.
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Increased, increased by a factor
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of two.
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And we are done.