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Change in centripetal acceleration from change in linear velocity and radius: Worked examples

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    - [Instructor] We are told
    that a van drives around
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    a circular curve of radius
    r with linear speed v.
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    On a second curve of the same radius,
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    the van has linear speed 1/3 v.
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    And you could view linear
    speed as the magnitude
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    of your linear velocity.
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    How does the magnitude of the
    van's centripetal acceleration
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    change after the linear speed decreases?
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    So pause this video and see
    if you can figure it out
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    on your own, and I'll give
    you a little bit of a hint.
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    We know that the magnitude
    of centripetal acceleration
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    in general is equal to
    linear speed squared
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    divided by radius.
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    The radius of the curve.
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    Alright, now let's work
    through this together.
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    So let's first think
    about the first curve.
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    So the first curve the
    magnitude of our centripetal
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    acceleration for curve one,
    I have another subscript
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    one here, this is around the first curve.
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    They tell us that our linear speed is v.
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    So we have v squared over and
    the radius of that curve is r.
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    This is going to be a
    straight up v squared over r
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    for that first curve.
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    The magnitude of our
    centripetal acceleration.
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    Now what about the second curve?
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    So the magnitude of our
    centripetal acceleration
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    around second curve,
    that's what that two is,
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    is going to be equal to,
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    they tell us we now have
    a linear speed of 1/3 v.
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    So in our numerator
    we're gonna square that,
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    1/3 v squared all of that over
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    the curve of the same radius.
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    So our radius is still r.
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    So let's just do a little
    algebraic simplification.
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    1/3 v times 1/3 v is just going to be
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    1/9 v squared.
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    So it's going to be 1/9 v squared over r.
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    All I did is square this numerator here.
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    Or I could write this as
    1/9 times v squared over r.
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    The reason why I wrote
    this in green is because
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    this is the exact same thing as this.
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    And so this is going to be equal to,
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    this is equal to 1/9
    times, instead of writing
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    v squared over r, I could say hey that's r
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    the magnitude of our
    centripetal acceleration
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    around the first curve.
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    The magnitude of our
    centripetal acceleration
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    around the first curve.
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    So how does the magnitude
    of the van's centripetal
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    acceleration change after
    the linear speed decreases?
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    Well around the second curve,
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    we have 1/9 the magnitude
    of centripetal acceleration.
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    So we could say the magnitude,
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    or I could just say, they already asked us
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    how does the magnitude change
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    so we could say decreases,
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    decreases by a factor
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    factor of nine.
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    And I wrote it in this language.
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    You could say it got
    multiplied by a factor of 1/9
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    or you could say decreases
    by a factor of nine
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    because on the Khan Academy exercises
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    that deal with this, they
    use language like that.
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    Let's do another example.
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    Here we are told a
    father spins his daughter
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    in a circle of radius r
    at angular speed omega.
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    Then the father extends
    his arms and spins her
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    in a circle of radius two r
    with the same angular speed.
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    How does the magnitude of
    the child's centripetal
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    acceleration change when
    the father extends his arms?
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    Once again pause this
    video and see if you can
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    figure it out.
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    Well the key realization
    here and we derived this
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    at a previous video, is to
    realize that the magnitude
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    of centripetal acceleration
    is equal to r times
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    our angular speed squared.
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    And so initially so the
    magnitude of our centripetal
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    acceleration initially,
    I'll do that with a sub i.
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    That is going to be equal
    to, well they're using
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    the same notation.
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    We have omega as our angular speed.
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    And our radius is r.
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    So it's just going to be r omega squared.
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    And then when we think about the father,
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    he extends his arms.
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    So then you have the
    magnitude of your centripetal
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    acceleration, I could
    say final or extended or
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    I'll just say final sub f.
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    What does that going to be equal to?
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    Well now our radius, the
    radius of our circle is two r.
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    So it's going to be two r
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    and they say the same angular speed.
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    So our angular speed is still omega.
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    Two r omega squared.
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    Well this part right over
    here r omega squared,
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    that was just the magnitude of our initial
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    centripetal acceleration.
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    That was the magnitude of our initial
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    centripetal acceleration.
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    And so you see that the magnitude of our
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    centripetal acceleration, has
    increased by a factor of two.
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    Increased, increased by a factor
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    of two.
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    And we are done.
Title:
Change in centripetal acceleration from change in linear velocity and radius: Worked examples
Description:

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Video Language:
Czech
Duration:
04:57

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