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Introduction to Torque

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    Welcome to the presentation
    on torque.
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    So, if you watched the
    presentation on the center of
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    mass, which you should have, you
    might have gotten a little
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    bit of a glancing view
    of what torque is.
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    And now we'll do some
    more in detail.
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    So in general, from the center
    of mass video, we learned, if
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    this is a ruler and this is the
    ruler's center of mass.
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    And if I were to apply force at
    the center of mass, I would
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    accelerate the whole ruler in
    the direction of the force.
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    If I have the force applying at
    the center of mass there,
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    the whole ruler would accelerate
    in that direction.
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    And we'd figure it out by
    taking the force we're
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    applying to it and dividing
    by the mass of the ruler.
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    And in that center of mass
    video, I imply-- well, what
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    happens if the force
    is applied here?
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    Away from the center of mass?
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    Well, in this situation, the
    object, assuming it's a free
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    floating object on the Space
    Shuttle or something, it will
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    rotate around the
    center of mass.
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    And that's also true, if we
    didn't use the center of mass,
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    but instead we fixed
    the point.
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    Let's say we had
    another ruler.
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    Although it has less height
    than the previous one.
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    Instead of worrying about its
    center of mass, let's say that
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    it's just fixed at
    a point here.
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    Let's say it's fixed here.
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    So if this could be the hand
    of a clock, and it's nailed
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    down to the back of the
    clock right there.
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    So if we were trying to rotate
    it, it would always rotate
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    around this point.
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    And the same thing
    would happen.
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    If I were to apply a force at
    this point, maybe I could
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    break the nail off the back of
    the clock, or something, but I
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    won't rotate this needle or
    this ruler, or whatever you
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    want to call it.
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    But if I would apply a force
    here, I would rotate the ruler
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    around the pivot point.
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    And this force that's applied a
    distance away from the pivot
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    point, or we could say from the
    axis of rotation, or the
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    center of mass.
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    That's called torque.
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    And torque, the letter for
    torque is this Greek, I think
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    that's tau, it's a curvy T.
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    And torque is defined as
    force times distance.
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    And what force and what
    distance is it?
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    It's the force that's
    perpendicular to the object.
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    I guess you could say to
    the distance vector.
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    If this is the distance vector--
    let me do it in a
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    different color.
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    If this is the distance vector,
    the component of the
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    force is perpendicular to
    this distance vector.
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    And this is torque.
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    And so what are its units?
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    Well, force is newtons, and
    distance is meters, so this is
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    newton meters.
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    And you're saying, hey Sal,
    newtons times meters, force
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    times distance, that looks
    an awful lot like work.
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    And it's very important to
    realize that this isn't work,
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    and that's why we won't
    call this joules.
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    Because in work, what
    are we doing?
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    We are translating an object.
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    If this is an object, and I'm
    applying a force, I'm taking
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    the force over the distance
    in the same
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    direction as the force.
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    Here the distance and
    the force are
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    parallel to each other.
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    You could say the distance
    vector and the force vector
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    are in the same direction.
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    Of course, that's
    translational.
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    The whole object
    is just moving.
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    It's not rotating or anything.
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    In the situation of torque,
    let me switch colors.
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    The distance vector, this is the
    distance from the fulcrum
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    or the pivot point of the center
    of mass, to where I'm
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    applying the force.
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    This distance vector is
    perpendicular to the force
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    that's being applied.
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    So torque and work are
    fundamentally two different
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    things, even though their
    units are the same.
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    And this is a little
    bit of notational.
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    This distance is often called
    the moment arm distance.
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    And I don't know where
    that came from.
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    Maybe one of you all can write
    me a message saying where it
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    did come from.
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    And often in some of your
    physics classes they'll often
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    call torque as a moment.
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    But we'll deal with
    the term torque.
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    And that's more fun, because
    eventually we can understand
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    concepts like torque
    horsepower in cars.
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    So let's do a little bit of
    math, hopefully I've given you
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    a little bit of intuition.
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    So let's say I had this ruler.
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    And let's say that this is its
    pivot point right here.
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    So it would rotate around
    that point.
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    It's nailed to the wall
    or something.
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    And let's say that I apply a
    force-- Let's say the moment
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    arm distance.
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    So let's say this distance,
    let me do it
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    in different color.
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    Let's say that this distance
    right here is 10 meters.
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    And I were to apply a force of 5
    newtons perpendicular to the
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    distance vector, or to dimension
    of the moment arm,
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    you could view it either way.
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    So torque is pretty easy
    in this situation.
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    Torque is going to be equal to
    the force, 5 newtons, times
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    the distance, 10.
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    So it would be 50
    newton meters.
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    And you're probably saying,
    well, Sal, how do I know if
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    this torque is going to be
    positive or negative?
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    And this is where there's just a
    general arbitrary convention
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    in physics.
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    And it's good to know.
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    If you're rotating clockwise
    torque is negative.
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    Let me go the other way.
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    If you were rotating
    counterclockwise, like we were
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    in this example, rotating
    counterclockwise, the opposite
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    direction of which a clock
    would move in.
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    Torque is positive.
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    And if you rotate clockwise
    the other
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    way, torque is negative.
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    So clockwise is negative.
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    And I'm not going to go into
    the whole cross product and
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    the linear algebra of torque
    right now, because I think
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    that's a little bit
    beyond the scope.
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    But we'll do that
    once we do more
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    mathematically intensive physics.
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    But, so, good enough.
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    There's a torque of
    50 newton meters.
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    And that's all of the torque
    that is acting
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    on this object .
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    So it's going to rotate
    in this direction.
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    And we don't have the tools yet
    to figure out how quickly
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    it will rotate.
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    But we know it will rotate.
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    And that's vaguely useful.
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    But what if I said that the
    object is not rotating?
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    And that I have another
    force acting here?
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    And let's say that that force
    is-- I don't know, let me make
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    up something, that's 5
    meters to the left
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    of the pivot point.
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    If I were tell you that this
    object does not rotate.
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    So if I tell you that the object
    is not rotating, that
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    means the net torque on this
    ruler must be 0, because it's
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    not-- its rate of change of
    rotation is not changing.
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    I should be a little exact.
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    If I'm applying some force here,
    and still not rotating,
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    then we know that the net torque
    on this object is 0.
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    So what is the force
    being applied here?
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    Well, what is the net torque?
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    Well, it's this torque, which
    we already figured out.
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    It's going in the clockwise
    direction.
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    So it's 5-- Let me do it
    in a brighter color.
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    5 times 10.
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    And then the net torque.
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    The sum of all the torques
    have to be equal to 0.
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    So what's this torque?
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    So let's call this f.
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    This is the force.
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    So, plus-- Well, this force is
    acting in what direction?
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    Clockwise or counterclockwise?
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    Well, it's acting in the
    clockwise direction.
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    This force wants to make the
    ruler rotate this way.
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    So this is actually going
    to be a negative torque.
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    So let's say, put a negative
    number here times f, times its
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    moment arm distance, times
    5, and all of this
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    has to equal 0.
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    The net torque is 0, because the
    object's rate of change of
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    rotation isn't changing, or if
    it started off not rotating,
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    it's still not rotating.
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    So here we get 50 minus
    5 f is equal to 0.
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    That's 50 is equal to 5 f.
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    f is equal to 10.
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    If we follow the units all the
    way through, we would get that
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    f is equal to 10 newtons.
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    So that's interesting.
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    I applied double the force
    at half the distance.
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    And it offsetted half the force
    at twice the distance.
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    And that should all connect, or
    start to connect, with what
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    we talked about with mechanical
    advantage.
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    You could view it
    the other way.
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    Let's say these are people
    applying these forces.
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    Say this guy over here is
    applying 10 newtons.
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    He's much stronger.
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    He's twice as strong as
    this guy over here.
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    But because this guy is twice
    as far away from the pivot
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    point, he balances
    the other guy.
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    So you can kind of view it
    as this guy having some
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    mechanical advantage or having
    a mechanical advantage of 2.
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    And watch the mechanical
    advantage videos if that
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    confuses you a little bit.
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    But this is where to
    torque is useful.
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    Because if an object's rate of
    rotation is not changing, you
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    know that the net torque
    on that object is 0.
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    And you can solve for the
    forces or the distances.
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    I'm about to run out of
    time, so I will see
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    you in the next video.
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Title:
Introduction to Torque
Description:

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Video Language:
English
Duration:
09:24

English subtitles

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