< Return to Video

Quadratic Inequalities (Visual Explanation)

  • 0:02 - 0:06
    Welcome to the presentation
    on quadratic inequalities.
  • 0:06 - 0:10
    Before we get to quadratic
    inequalities, let's just start
  • 0:10 - 0:12
    graphing some functions and
    interpret them and then we'll
  • 0:12 - 0:14
    slowly move to the
    inequalities.
  • 0:14 - 0:26
    Let's say I had f of x is equal
    to x squared plus x minus 6.
  • 0:26 - 0:29
    Well, if we wanted to figure
    out where this function
  • 0:29 - 0:33
    intersects the x-axis or the
    roots of it, we learned in our
  • 0:33 - 0:35
    factoring quadratics that we
    could just set f of x
  • 0:35 - 0:37
    is equal to 0, right?
  • 0:37 - 0:39
    Because f of x equals 0 when
    you're intersecting the x-axis.
  • 0:39 - 0:47
    So you would say x squared
    plus x minus 6 is equal to 0.
  • 0:47 - 0:49
    And you just factor
    this quadratic.
  • 0:49 - 0:57
    x plus 3 times x
    minus 2 equals 0.
  • 0:57 - 1:03
    And you would learn that the
    roots of this quadratic
  • 1:03 - 1:12
    function are x is equal to
    minus 3, and x is equal to 2.
  • 1:12 - 1:14
    How would we visualize this?
  • 1:14 - 1:17
    Well let's draw this
    quadratic function.
  • 1:21 - 1:25
    Those are my very uneven lines.
  • 1:25 - 1:27
    So the roots are x is
    equal to negative 3.
  • 1:27 - 1:33
    So this is, right here, x is at
    minus 3y0 -- by definition one
  • 1:33 - 1:37
    of the roots is where
    f of x is equal to 0.
  • 1:37 - 1:41
    So the y, or the f of
    x axis here is 0.
  • 1:41 - 1:43
    The coordinate is 0.
  • 1:43 - 1:47
    And this point here
    is 2 comma 0.
  • 1:47 - 1:53
    Once again, this is the x-axis,
    and this is the f of x-axis.
  • 1:53 - 1:56
    We also know that the y
    intercept is minus 6.
  • 1:56 - 1:58
    This isn't the vertex,
    this is the y intercept.
  • 1:58 - 2:04
    And that the graph is going to
    look something like this -- not
  • 2:04 - 2:06
    as bumpy as what I'm drawing,
    which I think you get the
  • 2:06 - 2:10
    general idea if you've ever
    seen a clean parabola.
  • 2:10 - 2:16
    It looks like that with x minus
    3 here, and x is 2 here.
  • 2:16 - 2:17
    Pretty straightforward.
  • 2:17 - 2:19
    We figured out the roots, we
    figured out what it looks like.
  • 2:19 - 2:22
    Now what if we, instead of
    wanting to know where f of x is
  • 2:22 - 2:25
    equal to 0, which is these two
    points, what if we wanted
  • 2:25 - 2:29
    to know where f of x
    is greater than 0?
  • 2:29 - 2:33
    What x values make f
    of x greater than 0?
  • 2:33 - 2:36
    Or another way of saying
    it, what values make
  • 2:36 - 2:37
    the statement true?
  • 2:37 - 2:43
    x squared plus x minus 6
    is greater than 0, Right,
  • 2:43 - 2:45
    this is just f of x.
  • 2:45 - 2:49
    Well if we look at the graph,
    when is f of x greater than 0?
  • 2:49 - 2:52
    Well this is the f of x
    axis, and when are we
  • 2:52 - 2:53
    in positive territory?
  • 2:53 - 2:55
    Well f of x is greater than
    0 here -- let me draw that
  • 2:55 - 3:01
    another color -- is greater
    than 0 here, right?
  • 3:01 - 3:05
    Because it's above the x-axis.
  • 3:05 - 3:07
    And f of x is greater
    than 0 here.
  • 3:12 - 3:17
    So just visually looking at it,
    what x values make this true?
  • 3:17 - 3:24
    Well, this is true whenever x
    is less than minus 3, right, or
  • 3:24 - 3:26
    whenever x is greater than 2.
  • 3:26 - 3:32
    Because when x is greater than
    2, f of x is greater than 0,
  • 3:32 - 3:36
    and when x is less than
    negative 3, f of x
  • 3:36 - 3:37
    is greater than 0.
  • 3:37 - 3:41
    So we would say the solution to
    this quadratic inequality, and
  • 3:41 - 3:47
    we pretty much solved this
    visually, is x is less than
  • 3:47 - 3:53
    minus 3, or x is
    greater than 2.
  • 3:53 - 3:54
    And you could test it out.
  • 3:54 - 3:57
    You could try out the number
    minus 4, and you should get f
  • 3:57 - 3:59
    of x being greater than 0.
  • 3:59 - 4:01
    You could try it out here.
  • 4:01 - 4:04
    Or you could try the number 3
    and make sure that this works.
  • 4:04 - 4:07
    And you can just make sure
    that, you could, for example,
  • 4:07 - 4:10
    try out the number 0 and make
    sure that 0 doesn't work,
  • 4:10 - 4:13
    right, because 0 is
    between the two roots.
  • 4:13 - 4:15
    It actually turns out that
    when x is equal to 0, f
  • 4:15 - 4:19
    of x is minus 6, which is
    definitely less than 0.
  • 4:19 - 4:22
    So I think this will give you a
    visual intuition of what this
  • 4:22 - 4:24
    quadratic inequality means.
  • 4:24 - 4:27
    Now with that visual intuition
    in the back of your mind, let's
  • 4:27 - 4:29
    do some more problems and maybe
    we won't have to go through the
  • 4:29 - 4:33
    exercise of drawing it, but
    maybe I will draw it just to
  • 4:33 - 4:35
    make sure that the
    point hits home.
  • 4:35 - 4:37
    Let me give you a slightly
    trickier problem.
  • 4:37 - 4:49
    Let's say I had minus x squared
    minus 3x plus 28, let me
  • 4:49 - 4:52
    say, is greater than 0.
  • 4:52 - 4:54
    Well I want to get rid of
    this negative sign in
  • 4:54 - 4:54
    front of the x squared.
  • 4:54 - 4:56
    I just don't like it there
    because it makes it look
  • 4:56 - 4:58
    more confusing to factor.
  • 4:58 - 5:00
    I'm going to multiply
    everything by negative 1.
  • 5:00 - 5:01
    Both sides.
  • 5:01 - 5:08
    I get x squared plus 3x minus
    28, and when you multiply or
  • 5:08 - 5:10
    divide by a negative, with any
    inequality you have
  • 5:10 - 5:11
    to swap the sign.
  • 5:11 - 5:17
    So this is now going
    to be less than 0.
  • 5:17 - 5:25
    And if we were to factor this,
    we get x plus 7 times x
  • 5:25 - 5:30
    minus 4 is less than 0.
  • 5:30 - 5:32
    So if this was equal to 0, we
    would know that the two roots
  • 5:32 - 5:37
    of this function -- let's
    define the function f of x --
  • 5:37 - 5:41
    let's define the function as f
    of x is equal to -- well we can
  • 5:41 - 5:43
    define it as this or this
    because they're the same thing.
  • 5:43 - 5:47
    But for simplicity let's define
    it as x plus 7 times x minus 4.
  • 5:47 - 5:49
    That's f of x, right?
  • 5:49 - 5:53
    Well, after factoring it, we
    know that the roots of this,
  • 5:53 - 6:06
    the roots are x is equal to
    minus 7, and x is equal to 4.
  • 6:06 - 6:08
    Now what we want to know
    is what x values make
  • 6:08 - 6:10
    this inequality true?
  • 6:10 - 6:12
    If this was any
    equality we'd be done.
  • 6:12 - 6:15
    But we want to know what
    makes this inequality true.
  • 6:15 - 6:18
    I'll give you a little bit of a
    trick, it's always going to be
  • 6:18 - 6:21
    the numbers in between the
    two roots or outside
  • 6:21 - 6:23
    of the two roots.
  • 6:23 - 6:26
    So what I do whenever I'm doing
    this on a test or something, I
  • 6:26 - 6:29
    just test numbers that are
    either between the roots or
  • 6:29 - 6:31
    outside of the two roots.
  • 6:31 - 6:35
    So let's pick a number that's
    between x equals minus
  • 6:35 - 6:36
    7 and x equals 4.
  • 6:36 - 6:42
    Well let's try x equals 0.
  • 6:42 - 6:47
    Well, f of 0 is equal to -- we
    could do it right here -- f of
  • 6:47 - 6:57
    0 is 0 plus 7 times 0 minus 4
    is just 7 times minus
  • 6:57 - 7:00
    4, which is minus 28.
  • 7:00 - 7:04
    So f of 0 is minus 28.
  • 7:04 - 7:09
    Now is this -- this is the
    function we're working with
  • 7:09 - 7:12
    -- is this less than 0?
  • 7:12 - 7:13
    Well yeah, it is.
  • 7:13 - 7:16
    So it actually turns that a
    number, an x value between
  • 7:16 - 7:17
    the two roots works.
  • 7:17 - 7:20
    So actually I immediately
    know that the answer here
  • 7:20 - 7:23
    is all of the x's that are
    between the two roots.
  • 7:23 - 7:29
    So we could say that the
    solution to this is
  • 7:29 - 7:35
    minus 7 is less than x
    which is less than 4.
  • 7:35 - 7:35
    Because now the other way.
  • 7:35 - 7:38
    You could have tried a number
    that's outside of the roots,
  • 7:38 - 7:41
    either less than minus 7 or
    greater than 4 and
  • 7:41 - 7:43
    have tried it out.
  • 7:43 - 7:46
    Let's say if you
    had tried out 5.
  • 7:46 - 7:48
    Try x equals 5.
  • 7:48 - 7:56
    Well then f of 5 would
    be 12 times 1, right,
  • 7:56 - 7:59
    which is equal to 12.
  • 7:59 - 8:00
    f of 5 is 12.
  • 8:00 - 8:02
    Is that less than 0?
  • 8:02 - 8:03
    No.
  • 8:03 - 8:04
    So that wouldn't have worked.
  • 8:04 - 8:06
    So once again, that gives
    us a confidence that we
  • 8:06 - 8:07
    got the right interval.
  • 8:07 - 8:12
    And if we wanted to think about
    this visually, because we got
  • 8:12 - 8:15
    this answer, when you do it
    visually it actually makes, I
  • 8:15 - 8:19
    think, a lot of sense,
    but maybe I'm biased.
  • 8:26 - 8:29
    If you look at it visually
    it looks like this.
  • 8:35 - 8:41
    If you draw it visually and this
    is the parabola, this is f of
  • 8:41 - 8:53
    x, the roots here are minus 7,
    0 and 4, 0, we're saying that
  • 8:53 - 8:56
    for all x values between these
    two numbers, f of
  • 8:56 - 8:57
    x is less than 0.
  • 8:57 - 9:00
    And that makes sense, because
    when is f of x less than 0?
  • 9:00 - 9:02
    Well this is the
    graph of f of x.
  • 9:06 - 9:08
    And when is f of x less than 0?
  • 9:08 - 9:08
    Right here.
  • 9:08 - 9:11
    So what x values give us that?
  • 9:11 - 9:14
    Well the x values that give
    us that are right here.
  • 9:14 - 9:15
    I hope I'm not confusing
    you too much with
  • 9:15 - 9:17
    these visual graphs.
  • 9:17 - 9:19
    And you're probably saying,
    well how do I know
  • 9:19 - 9:20
    I don't include 0?
  • 9:20 - 9:23
    Well you could try it out, but
    if you -- oh, well how come
  • 9:23 - 9:25
    I don't include the roots?
  • 9:25 - 9:28
    Well at the roots, f
    of x is equal to 0.
  • 9:28 - 9:32
    So if this was this, if this
    was less than or equal to 0,
  • 9:32 - 9:36
    then the answer would be
    negative 7 is less than
  • 9:36 - 9:39
    or equal to x is less
    than or equal to 4.
  • 9:39 - 9:41
    I hope that gives you a sense.
  • 9:41 - 9:42
    You pretty much just have to
    try number in between the
  • 9:42 - 9:45
    roots, and try number outside
    of the roots, and that tells
  • 9:45 - 9:49
    you what interval will
    make the inequality true.
  • 9:49 - 9:52
    I'll see you in the
    next presentation.
Title:
Quadratic Inequalities (Visual Explanation)
Description:

How to solve a quadratic inequality. Visual intuition of what a quadratic inequality means.

more » « less
Video Language:
English
Duration:
09:51

English subtitles

Revisions