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How to find equivalent expressions by combining like terms and using the distributive property

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    - Which expressions are equivalent
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    to x plus two-y plus x plus two?
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    Select all that apply. Alright.
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    Let's see if I can manipulate
    this thing a little bit.
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    Let me just rewrite it so I have x plus...
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    x plus two-y plus x plus two.
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    So, the first thing that jumps out at me,
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    before I even look at these choices,
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    here I have an x over here,
    I have an x over there.
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    Well, if I have one x, and
    then I can add it to another x
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    that would be two-x so
    I could rewrite this...
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    let me do this in a different color.
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    I could rewrite this x and this x,
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    if I add them together
    that's going to be two-x.
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    So, this is...actually, I
    don't want to skip any steps.
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    So, that's x plus x plus two-y...
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    now I'm just switching
    the order...plus two.
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    And then these two x's right over here,
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    I can just rewrite that as two-x.
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    So, I have two-x plus two-y...
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    plus two-y plus two.
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    Now, let's see, out of all my choices...
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    so, this one,
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    this is two-x plus four-y plus four.
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    So, that's not right, I have
    two-x plus two-y plus 2,
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    so I can rule this one out.
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    Now, this one's interesting, it looks like
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    they have factored out a two.
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    Let's see if we factor out
    a two here, what happens?
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    So, we do see that two
    is a factor of that term,
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    it's a factor of that term,
    and it's a factor of that term.
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    So, let's see if we can factor it out.
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    So, this is going to be two times x,
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    I'll do the x in that same
    magenta color, two times x plus,
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    we have just a y left when
    you factor out the two.
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    And then if you factor out a two here,
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    you're just going to have a one left.
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    So, two times x plus y plus one.
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    Which is exactly what they have over here.
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    And since I was able to find a choice,
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    I will not pick "None of the above".
Title:
How to find equivalent expressions by combining like terms and using the distributive property
Description:

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Video Language:
English
Team:
Khan Academy
Duration:
01:58

English subtitles

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