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Subtracting complex numbers

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    So we've plotted two complex numbers right over here on this
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    argand diagram. And what I think about is, what if we define a third
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    complex number c as being equal to the complex
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    number a minus the complex number b.
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    What is c going to look like if we were to write it as
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    just a sum of its real and imaginary parts? And what would it look like
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    on this argand diagram? So let's just first think about
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    this. So c is (let me do that in yellow colour) equal to
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    a which is the same thing as six plus two i minus b.
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    Now what is b?
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    b is two minus i.
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    So when we're subtracting anything, we can distribute this negative sign
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    and so this would be the same thing. This would be equivalent to
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    six plus two i
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    minus two and then
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    distributing the negative on a negative i, that's going to be a positive i,
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    plus i just like that. And now this is going to be equal to
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    (I'll do it right over here), this is going to be equal to, we can add
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    the real parts right over here. We have six minus two and so that's going to be four.
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    And then we can add, then we can add the two i
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    to the i, which is going to be three i
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    plus four plus three i,
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    and that is the complex number c.
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    Now let's see why that actually makes sense when we view,
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    when we visualise a and b as vectors.
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    So this is b, but we're essentially, when we do a minus b, that's essentially the same thing
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    as a plus negative b.
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    So what's negative b going to be equal to?
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    Negative b is going to be equal to
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    negative two plus i. I just multiplied all
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    the terms by negative one. So what does that look like? Let's see, negative two
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    plus i gets us right over there.
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    And we see, we've essentially just flipped
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    this vector over the origin. So this right over here
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    is negative b, that is negative b.
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    And we've already seen, if you're adding two things, we're going to add a to negative b.
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    So we've plotted a, so that its tail is at its origin
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    its head is right over here. And then we could take the tale of
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    negative b, put it right over here and then if you just shift it over,
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    it goes two to the left and one up.
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    It gets to that point right over here so that
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    this vector is another way to visualise
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    negative b as a vector. So where our new
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    head is once we put the tail of negative b here
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    is going to be the head of our vector c.
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    So c is going to be this vector right over here,
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    c is going to be this vector right over here if we visualize
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    this vector right over here. And we see that is
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    one, two, three, four. That is four plus
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    one, two, three i. We see that right over there.
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    So on one level it's kind of straight forward, manipulating expressions
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    and just recognizing that you can only add the imaginary parts to the imaginary parts
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    and the real parts to the real parts. And if you want to visualize it on an argand diagram
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    it really is analogous to... Subtracting b from a
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    is equivalent to adding the negative of b to a.
Title:
Subtracting complex numbers
Description:

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Video Language:
English
Duration:
03:51

English subtitles

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