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www.mathcentre.ac.uk/.../5.9Trigonometric%20Functions.mp4

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    This video is going to look at
    three knew trig functions. Cosec
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    Zack and caught.
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    However, they're not entirely
    knew, because they are derived
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    from the three that we know
    about already sign calls and
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    tan. So let's have a look.
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    The first one that we want to
    have a look at is cosec that is
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    defined to be one over sine. So
    one over sine Theta is equal to.
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    Now to give it its full name it
    is the cosecant.
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    Home theater But we
    shorten that till cosec theater.
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    Second one. Follows the
    same line one over 'cause
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    Theater and it's full name is
    the secant of Theta. But again,
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    we shorten that to set theater
    and the final one, one over
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    10 theater. Equals and it's
    full name is the cotangent of
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    Theta, and again we shorten that
    to caught theater.
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    Now, why do we need these? Well,
    first of all, they will help us
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    to solve trig equations.
    Secondly, there involved in
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    identity's and 3rd they come up
    when we do calculus,
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    particularly when we do
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    integration. Let's just have a
    look at one example of where
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    they might occur in terms of
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    basic identity's. So the basic
    trig identity that we've got,
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    the sine squared Theta Plus Cost
    Square theater, equals 1.
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    And if I choose to divide
    everything on both sides of this
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    identity by Cos squared, then
    I'll have sine squared Theta
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    over cost Square theater plus
    cost Square theater over Cos
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    squared Theta equals one over
    cost squared Theta.
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    And so this one is sign over
    cause all squared. So that gives
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    us stand square theater plus
    cost squared into Cos squared is
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    one equals and then one over
    cost squared is one over cause
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    all squared. So that is set
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    squared Theta. So there's one
    of our new trick functions
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    popping up in an identity this
    time, and there is a similar
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    one that we can get if we
    divide throughout by sine
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    squared, and if we do that, we
    end up with one plus cot
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    squared Theta is equal to
    cosec squared Theta, so there
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    the other two trig functions
    that we've just introduced
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    again pop up.
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    Let's have a look at what might
    happen when we reached the later
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    stages of solving a trig
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    equation. So let's take
    cot squared Theta equals
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    3 four theater between
    360 and 0 degrees.
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    Well, we begin to solve this by
    taking the square root. So
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    caught theater equals Route 3 or
    minus Route 3. Remember, we take
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    a square root, it has to be plus
    or minus. Now we might think,
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    well, let's just look this up in
    some tables or let's take our
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    Calculator, but do we really
    need to? We know what caught
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    theater is. It's one over Tan
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    Theta. And that's Route 3 or
    minus Route 3.
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    Now we can turn this one upside
    down to give us Tan Theta equals
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    and we can think of each of
    these as being root 3 over one
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    or minus Route 3 over one, and
    so we can turn these upside down
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    to get one over Route 3 or minus
    one over Route 3.
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    And now it's in terms of Tan
    Theater and this is now one of
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    those special values of our trig
    functions. In fact, one over
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    Route 3 is the tangent of 30
    degrees, so we know that this
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    has one solution that is 30
    degrees. But what about the
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    other solutions? Well, let's
    have a look at those.
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    Sketch of the graph.
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    Tan Theta 0 up to
    90 from 90 up through
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    180 up towards 270.
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    Stopping there at
    360, so that's not.
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    9180, two, 70
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    and 360. And
    the tangent of 30 is one over
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    Route 3. So somewhere here is
    one over Route 3 coming down to
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    30. So of course the next one is
    across there and the symmetry
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    tells us if this is 30 on from
    zero. This is 30 on from 180, so
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    the next one is 210 degrees
    minus one over Route 3. Well,
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    that's going to be somewhere
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    along here. And again, the
    symmetry tells us if this is 30
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    on this way, then this one is 30
    back this way. So that gives us
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    150 degrees and we've got
    another value here which is
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    going to be 30 back from there,
    which is going to be 330
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    degrees. So solving equations
    that involve things like caught,
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    encek and Cosec is no different
    to solving equations to do with
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    sign causing tan because we just
    turn them into sign calls and
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    tab to conclude this, we're just
    going to have a look at the
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    graphs of these three knew trig
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    functions. And in order to do
    that, we will begin each one by
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    looking at the graph of the
    related trig function. So to
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    look at Cosec, we're going to
    look at sign first. So what does
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    the graph of sign?
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    Look like. Will take one
    complete cycle between North and
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    360. So 0.
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    180, three, 160 and the
    peak and trough are in
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    between 1970 and that goes
    from one down 2 -
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    1 and what we're going
    to graph now is cosec
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    theater, which of course is
    one over sine Theta. So
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    let's set up similar axes.
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    So mark them off, there's 90.
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    180 270
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    360 Now
    here at 90
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    the value of
    sign is warm.
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    So at 90 the value of cosec must
    also be one, so I'm going to
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    market their one here at 270.
    The value of sign is minus one.
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    And so at 270, the value of
    cosec must be one over minus
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    one, which again is just minus
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    one. So there are two points.
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    What about this point?
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    Here at zero the sign of
    0 is 0.
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    So the value of Cosec would be
    one over 0.
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    But we're not allowed to divide
    by zero, but we can divide by
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    something a little bit away.
    What we can see is that would be
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    a very very tiny positive number
    that we were dividing by. So if
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    we divide 1 by a very tiny
    positive number, the answer has
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    to be very big, but still
    positive. So with a bit of curve
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    there, let's have a look at 180.
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    Well, at 180 sign of Theta is
    again 0 so cosec is one over
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    0 at this 180 degrees. Let's go
    a little bit this side here of
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    180 and the value of sign is
    really very small. It's very
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    close to 0.
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    So again, 1 divided by something
    very small and positive.
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    Is again something very large
    and positive, so let me put in
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    an asymptotes. And we've got a
    piece of curve there.
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    Now this curve goes like that.
    What we're seeing is that this
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    curve is going to come down and
    up like that, and it's going to
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    do the same here, except because
    what we're dividing by are
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    negative numbers, it's going to
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    be like. That
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    So there's our graph of cosec
    derived from the graph of sign.
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    Let's take now calls feta.
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    Do the same.
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    Will take the graph of
    costita between North and 360.
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    At the extreme, values will
    be minus one plus one
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    9180 two 7360. Just make
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    that clearer. And so let's have
    a look here.
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    Mark off the same
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    points. And we're
    graphing SEK this
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    time sex theater,
    which is one
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    over 'cause theater.
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    So again, let's Mark some
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    points. Here when theater is 0.
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    Costita is one Soucek
    Theater is one over one
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    which is one. So will mark
    the one there here at 180.
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    Cost theater is minus one.
    Soucek Theater is 1 divided
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    by minus one and so will
    mark minus one here.
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    Here at 90 we got exactly the
    same problems we have before the
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    value of Cos theater at 90 zero.
    So 1 / 0 is a very big number.
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    Well, in fact we're not allowed
    to do it, so we have to go a
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    little bit away from 90 to get a
    value of Cos Theta which is very
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    small, close to 0 but positive.
    And if we divide 1 by that small
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    positive number, the answer that
    we get is very big and.
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    Positive so we have a bit of
    curve going up like that. What
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    about this side of 90? Well this
    side of 90 where dividing by
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    something which the value of Cos
    Theta is very small but
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    definitely negative. So the
    answer is going to be very big
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    in size when we divide it into
    one but negative. So a bit of
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    the curve here coming down to
    their same problem again at 270
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    so we can see the curve is going
    to go round.
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    And back like that. And then
    here again at 360, we're going
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    to be able to mark that point.
    We're going to have that one
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    coming down at that.
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    So there we've managed to get
    the graph of SEK.
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    Out of the graph, of course.
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    Let's now have a look at the
    graph of Tan Theater.
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    These
    off
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    9180,
    two,
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    70
    and
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    360.
    And now we'll have a look at
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    caught theater, which is one
    over Tan Theater.
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    So we'll take the same graph and
    I'll do the same as I've done
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    before. Mark these off.
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    So we're using the same
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    scale. OK, let's have a look
    what's happening here. This bit
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    of curve between North and 90.
    We begin with something for tan
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    that is very small but positive.
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    Just above 0 and then it gets
    bigger and bigger and bigger as
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    it rises. The value of Tan Theta
    rises towards Infinity.
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    Well down here divide the value
    of theater is very near to zero
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    and so tan Theta is very small
    but positive. So when we divide
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    into one we're going to get
    something very big and positive
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    self. But if curve there.
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    Up here, the value of Tan
    Theater is enormous. It's huge.
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    So if we divide something huge
    into one, the answer is going to
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    be very nearly zero. And the
    closer we get to 90, the closer
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    it would be to 0.
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    So now if we look here, we can
    see we've got something very,
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    very big, but negative. So the
    answer is going to be very, very
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    small, but also negative. This
    is going to be coming out of
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    that point there. Here 180.
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    Got a problem at 180. Tan
    Theater is 0 one over 10 theater
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    is there for something very very
    big so we can put in an acid
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    tote and we can see we've got
    exactly the same problem here at
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    360. So if I join up what I've
    got in the direction of what's
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    happening, we're getting a very
    similar curve and repeat it over
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    here, 'cause the curves are
    repeated. We're getting a very
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    similar curve, except the other
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    way around. So we've seen again
    how we can derive the graph of
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    coffee to directly from the
    graph of Tan.
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    So remember these three
    new functions.
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    Co sack sack and caught.
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    Respectively, they are one
    over sign, one over cosine
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    and one over Tangent.
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    We can use them to solve
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    equations. But each time we
    can get back to using sign
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    cause and tab to help us
    workout the angles.
Title:
www.mathcentre.ac.uk/.../5.9Trigonometric%20Functions.mp4
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