1
00:00:00,620 --> 00:00:02,590
Hərəkət edən hissəciyin mövqeyi

2
00:00:02,590 --> 00:00:04,730
s(t) ilə verilib, o, 3-də 2 t-nin kubu

3
00:00:04,730 --> 00:00:08,810
çıxılsın 6t-nin kvadratı, üstəgəl
10t,

4
00:00:08,810 --> 00:00:10,600
t 0-dan böyük bərabərdir və

5
00:00:10,600 --> 00:00:12,850
saniyə ilə ifadə edilib.

6
00:00:12,850 --> 00:00:16,340
Hissəcik ilk 6 saniyədə sola və
sağa hərəkət edir.

7
00:00:16,340 --> 00:00:19,640
t 0-dan böyük bərabər və 6-dan kiçik
bərabər olduqda

8
00:00:19,640 --> 00:00:23,042
hissəciyin getdiyi ümumi yol
nəyə bərabərdir?

9
00:00:23,042 --> 00:00:24,500
Gəlin ümumi yol dedikdə nəyi

10
00:00:24,500 --> 00:00:26,990
nəzərdə tutduğuna baxaq.

11
00:00:26,990 --> 00:00:29,280
Buradan başlasam,

12
00:00:29,280 --> 00:00:32,689
3 xana sağa və

13
00:00:32,689 --> 00:00:37,270
4 xana sola hərəkət etsəm,

14
00:00:37,270 --> 00:00:40,370
burada sola getdiyimizə görə
mənfi 4 olur,

15
00:00:40,370 --> 00:00:46,002
ümumi yol 7 olar.

16
00:00:46,002 --> 00:00:47,720
3 xana sağa və 4 xana sola.

17
00:00:47,720 --> 00:00:49,560
Hətta bu hissə

18
00:00:49,560 --> 00:00:51,075
mənfi 1 olur.

19
00:00:53,630 --> 00:00:56,240
Yəni yerdəyişməsi

20
00:00:56,240 --> 00:00:58,490
mənfi 1 olur.

21
00:00:58,490 --> 00:01:00,990
Başladığım yerdən 1 xana soldayam.

22
00:01:00,990 --> 00:01:03,030
Ümumi yol isə 7-dir.

23
00:01:03,030 --> 00:01:04,370
Bunu aydınlaşdırdıq.

24
00:01:04,370 --> 00:01:06,379
İndi videonu dayandırın və

25
00:01:06,379 --> 00:01:07,670
suala cavab verməyə
çalışın.

26
00:01:07,670 --> 00:01:09,260
İlk 6 saniyədə hissəciyin getdiyi

27
00:01:09,260 --> 00:01:13,930
ümumi yol nə qədərdir?

28
00:01:13,930 --> 00:01:16,244
Bunu həll etməyin

29
00:01:16,244 --> 00:01:17,660
ən asan yolu

30
00:01:17,660 --> 00:01:19,034
hissəciyin nə vaxt sağa və

31
00:01:19,034 --> 00:01:20,590
nə vaxt sola getdiyini
tapmaqdır.

32
00:01:20,590 --> 00:01:22,320
Vektorial sürət müsbət olanda

33
00:01:22,320 --> 00:01:24,020
sağa gedir, mənfi olduqda isə

34
00:01:24,020 --> 00:01:26,559
hissəcik sola doğru gedir.

35
00:01:26,559 --> 00:01:28,180
Beləliklə, sadəcə vektorial
sürətin

36
00:01:28,180 --> 00:01:30,515
nə vaxt müsbət və mənfi olduğuna
fikir verməliyik.

37
00:01:30,515 --> 00:01:31,890
Bunu tapmaq üçün gəlin

38
00:01:31,890 --> 00:01:34,996
vektorial sürətin funksiyasının
qrafikini çəkək.

39
00:01:34,996 --> 00:01:36,370
Burada funksiya müsbətdir.

40
00:01:36,370 --> 00:01:37,869
Vektorial sürət yerdəyişmənin

41
00:01:37,869 --> 00:01:41,510
zamana görə törəməsinə
bərabərdir.

42
00:01:41,510 --> 00:01:44,110
3-də 2 t-nin kubunun törəməsi

43
00:01:44,110 --> 00:01:48,100
2t kvadratına bərabər olacaq.

44
00:01:48,100 --> 00:01:54,100
Daha sonra çıxılsın 12t,
üstəgəl 10.

45
00:01:54,100 --> 00:01:57,580
Gəlin qrafiki çəkməyə çalışaq

46
00:01:57,580 --> 00:01:59,840
Bu, qolları yuxarı yönəlmiş
parabola olacaq.

47
00:01:59,840 --> 00:02:01,520
Funksiya kvadratikdir.

48
00:02:01,520 --> 00:02:04,720
2-ci yerdə duran, yəni
t kvadratının əmsalı

49
00:02:04,720 --> 00:02:06,510
müsbətdir, buna görə də

50
00:02:06,510 --> 00:02:08,698
qrafik qolları yuxarı yönəlmiş
parabola olacaq.

51
00:02:08,698 --> 00:02:10,630
Belə olacaq.

52
00:02:10,630 --> 00:02:12,636


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