1 00:00:00,090 --> 00:00:01,410 - [Lecturer] Let's solve a couple of problems 2 00:00:01,410 --> 00:00:02,910 on Newton's second law. 3 00:00:02,910 --> 00:00:03,780 Here's the first one. 4 00:00:03,780 --> 00:00:05,970 We have an elevator, which is moving up. 5 00:00:05,970 --> 00:00:07,350 And let's say the mass of the elevator, 6 00:00:07,350 --> 00:00:11,880 including the passenger inside, is 1,000 kilograms. 7 00:00:11,880 --> 00:00:14,940 Now the force, the tension force of the cable, 8 00:00:14,940 --> 00:00:17,400 let's say that's about 7,800 newtons, 9 00:00:17,400 --> 00:00:20,880 our goal is to figure out what the acceleration 10 00:00:20,880 --> 00:00:22,710 of this elevator is. 11 00:00:22,710 --> 00:00:26,070 We're also given that the gravitational force acting 12 00:00:26,070 --> 00:00:29,310 on that elevator, including the passenger over here, 13 00:00:29,310 --> 00:00:32,430 is about 9,800 newtons. 14 00:00:32,430 --> 00:00:33,990 So, how do we figure this out? 15 00:00:33,990 --> 00:00:35,617 Well, the first thing that comes to my mind is, 16 00:00:35,617 --> 00:00:37,830 "Hey, we have some forces 17 00:00:37,830 --> 00:00:40,860 and we have some motion variables like acceleration. 18 00:00:40,860 --> 00:00:43,440 What connects forces and motion variables? 19 00:00:43,440 --> 00:00:45,060 What connects forces and motion? 20 00:00:45,060 --> 00:00:47,490 Newton's second law. 21 00:00:47,490 --> 00:00:49,140 So, the first thing I try to do 22 00:00:49,140 --> 00:00:50,880 before applying Newton second law is I try 23 00:00:50,880 --> 00:00:53,520 to draw a free body diagram. 24 00:00:53,520 --> 00:00:55,080 So lemme do that. 25 00:00:55,080 --> 00:00:56,670 What's the way to draw a free body diagram? 26 00:00:56,670 --> 00:00:58,920 We try to get rid of unnecessary details. 27 00:00:58,920 --> 00:01:01,350 Use a box to represent your object of interest. 28 00:01:01,350 --> 00:01:02,910 Our object of interest is this elevator 29 00:01:02,910 --> 00:01:03,750 and the person over here. 30 00:01:03,750 --> 00:01:05,490 So, that's our box. 31 00:01:05,490 --> 00:01:07,020 It's mass is 1,000 kilograms 32 00:01:07,020 --> 00:01:08,880 and let's draw all the forces acting on it, 33 00:01:08,880 --> 00:01:09,990 which are the forces acting on it. 34 00:01:09,990 --> 00:01:12,330 Well, we have an upward force that's tension 35 00:01:12,330 --> 00:01:15,300 and we have a downward force that's the force of gravity 36 00:01:15,300 --> 00:01:18,480 and our goal is to calculate what the acceleration is. 37 00:01:18,480 --> 00:01:19,830 And how do we do that? 38 00:01:19,830 --> 00:01:20,950 Well, we use Newton second law, 39 00:01:20,950 --> 00:01:23,190 which says the acceleration 40 00:01:23,190 --> 00:01:26,310 should equal the net force acting on an object 41 00:01:26,310 --> 00:01:29,100 divided by its mass. 42 00:01:29,100 --> 00:01:31,860 And of course, since we're dealing with vectors, 43 00:01:31,860 --> 00:01:33,990 we can put arrow marks over here. 44 00:01:33,990 --> 00:01:35,820 The direction of the acceleration will be the same 45 00:01:35,820 --> 00:01:37,140 as the direction of the net force. 46 00:01:37,140 --> 00:01:40,350 Okay, now we can calculate the net force from this 47 00:01:40,350 --> 00:01:42,150 and we can calculate, we know the mass, 48 00:01:42,150 --> 00:01:43,800 so from that we can calculate the acceleration. 49 00:01:43,800 --> 00:01:45,240 So why don't you pause the video 50 00:01:45,240 --> 00:01:46,680 and see if you can plug in the numbers 51 00:01:46,680 --> 00:01:48,730 and find the acceleration yourself first. 52 00:01:49,980 --> 00:01:51,540 All right, let's try. 53 00:01:51,540 --> 00:01:54,300 So our acceleration would be the net force. 54 00:01:54,300 --> 00:01:55,890 How do I figure the net force out? 55 00:01:55,890 --> 00:01:57,000 Well, the total force, 56 00:01:57,000 --> 00:01:59,430 well they're since in the opposite direction, 57 00:01:59,430 --> 00:02:00,540 we'll subtract them. 58 00:02:00,540 --> 00:02:02,400 So, I'll just take the bigger number. 59 00:02:02,400 --> 00:02:06,000 So 9,800 newtons, which is acting downwards. 60 00:02:06,000 --> 00:02:08,010 We need to take care of the direction. 61 00:02:08,010 --> 00:02:10,650 From that, I'll subtract the smaller number, 62 00:02:10,650 --> 00:02:15,650 that is 7,800 newtons upwards divided by the mass, 63 00:02:16,350 --> 00:02:18,903 which is 1,000 kilograms. 64 00:02:20,610 --> 00:02:22,320 And if you simplify, 65 00:02:22,320 --> 00:02:26,880 we will get 9,800 minus 7,800 is 2,000. 66 00:02:26,880 --> 00:02:29,640 Nice numbers, 2000 newtons. 67 00:02:29,640 --> 00:02:31,380 But what direction is it? 68 00:02:31,380 --> 00:02:34,655 The downward one wins, right? It's bigger. 69 00:02:34,655 --> 00:02:36,750 So, the net force will be in the downward direction. 70 00:02:36,750 --> 00:02:41,750 It's divided by 1,000 kilograms and that gives us two. 71 00:02:42,840 --> 00:02:45,210 So, our acceleration becomes 72 00:02:45,210 --> 00:02:49,620 two meters per second square downwards. 73 00:02:49,620 --> 00:02:50,790 Okay, we found our answer, 74 00:02:50,790 --> 00:02:54,330 but one of the best ways to gain deeper insights is to try 75 00:02:54,330 --> 00:02:55,890 and see if this kind of makes sense. 76 00:02:55,890 --> 00:02:58,050 Can you get a feeling for what's going on over here? 77 00:02:58,050 --> 00:02:59,910 Okay, now the first question 78 00:02:59,910 --> 00:03:01,830 that we could be having over here is, look, 79 00:03:01,830 --> 00:03:03,720 the net force is downwards 80 00:03:03,720 --> 00:03:04,860 because gravity is winning, right? 81 00:03:04,860 --> 00:03:07,290 So the total force acting on this elevator is downwards 82 00:03:07,290 --> 00:03:10,080 and yet the elevator is moving up. 83 00:03:10,080 --> 00:03:11,880 Why is that? (chuckles) 84 00:03:11,880 --> 00:03:15,090 Well, remember, force does not dictate 85 00:03:15,090 --> 00:03:17,070 the direction of motion. 86 00:03:17,070 --> 00:03:20,940 Force tells you the direction of acceleration, okay? 87 00:03:20,940 --> 00:03:22,020 The elevator could be moving, 88 00:03:22,020 --> 00:03:24,240 objects can be moving whatever direction it wants. 89 00:03:24,240 --> 00:03:25,770 When you put a force on it, it tells you 90 00:03:25,770 --> 00:03:27,210 what direction it should accelerate. 91 00:03:27,210 --> 00:03:28,170 So that's the key thing. 92 00:03:28,170 --> 00:03:31,320 So, there is no problem that the force is acting downwards, 93 00:03:31,320 --> 00:03:32,910 but the elevator is moving upwards. 94 00:03:32,910 --> 00:03:34,530 Secondly, what does it mean 95 00:03:34,530 --> 00:03:36,210 that the acceleration is downwards? 96 00:03:36,210 --> 00:03:38,010 See, if the net force is downwards, 97 00:03:38,010 --> 00:03:39,060 the acceleration has to be downward. 98 00:03:39,060 --> 00:03:41,130 But what does it mean the elevator is moving up 99 00:03:41,130 --> 00:03:42,750 and the acceleration is downwards? 100 00:03:42,750 --> 00:03:46,560 Ooh, this means since the velocity 101 00:03:46,560 --> 00:03:48,720 and the acceleration is in the opposite direction, 102 00:03:48,720 --> 00:03:52,740 this means the elevator is slowing down. 103 00:03:52,740 --> 00:03:54,090 That's what it means for velocity 104 00:03:54,090 --> 00:03:55,560 and acceleration to be in the opposite direction. 105 00:03:55,560 --> 00:03:56,460 If they're in the same direction, 106 00:03:56,460 --> 00:03:57,780 it means they're speeding up. 107 00:03:57,780 --> 00:04:00,240 So, this means our elevator is going up, 108 00:04:00,240 --> 00:04:03,150 but it is slowing down, which probably means that, you know, 109 00:04:03,150 --> 00:04:04,860 it's probably about to stop. 110 00:04:04,860 --> 00:04:06,990 Maybe this person has probably reached 111 00:04:06,990 --> 00:04:08,670 his destination or something. 112 00:04:08,670 --> 00:04:10,560 All right, onto the next problem. 113 00:04:10,560 --> 00:04:15,120 This time we have a sledge at rest whose is 70 kilograms. 114 00:04:15,120 --> 00:04:16,620 Our goal is to push it 115 00:04:16,620 --> 00:04:18,810 and accelerate to six meters per second 116 00:04:18,810 --> 00:04:20,430 in about two seconds, let's say, 117 00:04:20,430 --> 00:04:22,110 so that, you know, it can nicely slide down 118 00:04:22,110 --> 00:04:23,760 and we can enjoy the ride. 119 00:04:23,760 --> 00:04:26,010 Now, there is going to be some frictional force. 120 00:04:26,010 --> 00:04:28,140 Even though we're on ice and everything, 121 00:04:28,140 --> 00:04:29,370 there'll be some frictional force. 122 00:04:29,370 --> 00:04:30,203 Let's say the friction 123 00:04:30,203 --> 00:04:32,853 that this ledge will experience is about 200 newtons. 124 00:04:33,690 --> 00:04:36,840 The question now is what is the force with which we have 125 00:04:36,840 --> 00:04:39,990 to push on it so as to achieve all of this? 126 00:04:39,990 --> 00:04:42,060 So how do we figure this out? 127 00:04:42,060 --> 00:04:43,980 Well, again, the first thing that comes to my mind is 128 00:04:43,980 --> 00:04:47,010 that look, we're dealing with forces and we have motion. 129 00:04:47,010 --> 00:04:50,490 What connects forces and motion? Newton's second law. 130 00:04:50,490 --> 00:04:52,320 So, the first thing I'll do is I'm gonna draw 131 00:04:52,320 --> 00:04:53,310 a free-body diagram. 132 00:04:53,310 --> 00:04:56,430 Again, I encourage you to pause the video now 133 00:04:56,430 --> 00:04:57,600 or anytime later on. 134 00:04:57,600 --> 00:04:58,710 Whenever you feel more comfortable, 135 00:04:58,710 --> 00:05:01,050 pause the video and see if you can complete it yourself. 136 00:05:01,050 --> 00:05:03,120 Okay, so anyways, let's first try 137 00:05:03,120 --> 00:05:04,230 to draw a free-body diagram. 138 00:05:04,230 --> 00:05:05,063 How do we do that? 139 00:05:05,063 --> 00:05:06,780 Well, again, we'll take the object of our interest. 140 00:05:06,780 --> 00:05:09,510 In this case, the object of our interest is this ledge 141 00:05:09,510 --> 00:05:12,930 whose mass is 70 kilograms and just make it a square 142 00:05:12,930 --> 00:05:14,370 and then draw all the forces acting on it. 143 00:05:14,370 --> 00:05:15,450 What are the forces acting on it? 144 00:05:15,450 --> 00:05:18,000 I know there's frictional force acting backwards 145 00:05:18,000 --> 00:05:21,660 of 200 newtons, but then I also have the applied force 146 00:05:21,660 --> 00:05:23,580 by this person, which I, we need to figure out. 147 00:05:23,580 --> 00:05:24,810 This is what we need to calculate. 148 00:05:24,810 --> 00:05:27,780 That is the applied force. What are other forces? 149 00:05:27,780 --> 00:05:30,600 Well, I know that there's also gravity acting on it 150 00:05:30,600 --> 00:05:33,150 and then there's a normal force acting on it upwards. 151 00:05:33,150 --> 00:05:35,220 But we know that these forces are balanced 152 00:05:35,220 --> 00:05:37,590 and so they're not going to be useful. 153 00:05:37,590 --> 00:05:41,190 They're not going to affect our situation over here. 154 00:05:41,190 --> 00:05:42,840 So, I'm just gonna draw them over here. 155 00:05:42,840 --> 00:05:44,954 They're there, of course, but they're completely balanced. 156 00:05:44,954 --> 00:05:46,740 They're in the verticals, they're not gonna affect it, 157 00:05:46,740 --> 00:05:48,150 so we'll not draw it. 158 00:05:48,150 --> 00:05:50,160 Okay, now that I have my free-body diagram, 159 00:05:50,160 --> 00:05:52,470 let's go ahead and write down on Newton second law. 160 00:05:52,470 --> 00:05:57,470 It says acceleration should always equal the net force, 161 00:05:57,930 --> 00:06:00,420 which let me draw using pink now. 162 00:06:00,420 --> 00:06:04,920 Net force divided by the mass. 163 00:06:04,920 --> 00:06:06,510 Divided by the mass. 164 00:06:06,510 --> 00:06:09,870 Okay, so what do we do next? 165 00:06:09,870 --> 00:06:12,630 I need to find this applied force. 166 00:06:12,630 --> 00:06:16,620 So this means if I can calculate the net force, 167 00:06:16,620 --> 00:06:19,650 then I can figure out what the applied force is, right? 168 00:06:19,650 --> 00:06:21,150 So, from Newton's second law, 169 00:06:21,150 --> 00:06:22,770 I just need to figure out what the net force is. 170 00:06:22,770 --> 00:06:25,470 For that, I ask myself, do I know m? 171 00:06:25,470 --> 00:06:27,960 I do. I know that m is 70 kilograms. 172 00:06:27,960 --> 00:06:29,940 Do I know the acceleration? 173 00:06:29,940 --> 00:06:31,140 Hmm, it's not given directly, 174 00:06:31,140 --> 00:06:34,740 but wait a second, I know the initial velocity, 175 00:06:34,740 --> 00:06:36,183 I know the final velocity and I know 176 00:06:36,183 --> 00:06:38,730 that the change in velocity should happen in two seconds. 177 00:06:38,730 --> 00:06:39,943 Whoo-hoo! 178 00:06:39,943 --> 00:06:43,860 That means I can calculate the acceleration from this data. 179 00:06:43,860 --> 00:06:46,140 I can plug in and from that I can figure out 180 00:06:46,140 --> 00:06:48,630 what the total force is going to be, 181 00:06:48,630 --> 00:06:50,070 the net force is going to be. 182 00:06:50,070 --> 00:06:52,590 And from that we can figure out 183 00:06:52,590 --> 00:06:54,330 what the applied force should be. 184 00:06:54,330 --> 00:06:56,280 Okay, so if you haven't done this before, 185 00:06:56,280 --> 00:06:57,690 why don't you now pause the video 186 00:06:57,690 --> 00:06:59,430 and see if you can put it all together 187 00:06:59,430 --> 00:07:01,560 and solve the problem? 188 00:07:01,560 --> 00:07:03,180 Okay, let's do this. 189 00:07:03,180 --> 00:07:05,130 So, let me first calculate the acceleration. 190 00:07:05,130 --> 00:07:06,240 So our acceleration is going 191 00:07:06,240 --> 00:07:07,620 to be, well how do we figure this out? 192 00:07:07,620 --> 00:07:11,670 This is the final velocity minus the initial velocity 193 00:07:11,670 --> 00:07:13,950 divided by the time taken. 194 00:07:13,950 --> 00:07:15,300 So, that's going to be, in our case, 195 00:07:15,300 --> 00:07:17,500 the final velocity is six meters per second 196 00:07:19,260 --> 00:07:21,810 to the right minus... 197 00:07:21,810 --> 00:07:23,040 What's the initial velocity? 198 00:07:23,040 --> 00:07:25,650 Well, it's zero, it's at rest. 199 00:07:25,650 --> 00:07:27,690 So there is no initial velocity divided 200 00:07:27,690 --> 00:07:30,360 by time is two, two seconds. 201 00:07:30,360 --> 00:07:31,590 That gives us what? 202 00:07:31,590 --> 00:07:36,590 That gives us six by two is three meters per second squared 203 00:07:37,560 --> 00:07:39,870 to the right. 204 00:07:39,870 --> 00:07:42,390 So I know my acceleration has to be 205 00:07:42,390 --> 00:07:44,610 to the right, which is good news. (chuckles) 206 00:07:44,610 --> 00:07:45,660 It has to be to the right. 207 00:07:45,660 --> 00:07:46,920 We want this ledge to move to the right. 208 00:07:46,920 --> 00:07:47,753 So, that makes sense. 209 00:07:47,753 --> 00:07:49,440 So, we are on the right track over here. 210 00:07:49,440 --> 00:07:50,730 Okay, now, I can plug in 211 00:07:50,730 --> 00:07:52,560 and figure out what the net force is going to be. 212 00:07:52,560 --> 00:07:56,100 So, if I just simplify that, so net force is going to be, 213 00:07:56,100 --> 00:07:58,770 if I rearrange this equation multiply by m on both sides. 214 00:07:58,770 --> 00:08:02,223 So I get net force to be mass times the acceleration. 215 00:08:03,240 --> 00:08:06,060 And so now I can plug in for mass and acceleration. 216 00:08:06,060 --> 00:08:09,150 What do I get? Well I get 70 kilograms. 217 00:08:09,150 --> 00:08:10,530 That's the mass, 218 00:08:10,530 --> 00:08:14,160 times the acceleration is three meters per second squared, 219 00:08:14,160 --> 00:08:15,620 70 times three, seven times these 21. 220 00:08:15,620 --> 00:08:18,090 So, this is 210. 221 00:08:18,090 --> 00:08:21,910 So, I get that my net force is 210 newtons 222 00:08:23,606 --> 00:08:25,230 to the right of this, 223 00:08:25,230 --> 00:08:27,210 this acceleration was to the right. 224 00:08:27,210 --> 00:08:30,660 So, this will also be to the right. 225 00:08:30,660 --> 00:08:34,740 So, now that I've found my net force, so my net force, 226 00:08:34,740 --> 00:08:37,860 the total force will be to the right 227 00:08:37,860 --> 00:08:40,020 and that is 210 newtons. 228 00:08:40,020 --> 00:08:44,070 From that, can I calculate the applied force? Yes. 229 00:08:44,070 --> 00:08:45,030 So now, first of all, 230 00:08:45,030 --> 00:08:47,550 I know my applied force should be bigger. 231 00:08:47,550 --> 00:08:48,660 It has to be bigger 232 00:08:48,660 --> 00:08:51,510 because my total force should be towards the right, 233 00:08:51,510 --> 00:08:54,030 which means if I subtract the two from this, 234 00:08:54,030 --> 00:08:57,030 if I subtract this number, I should get this number. 235 00:08:57,030 --> 00:08:58,530 That's the net force, all right? 236 00:08:58,530 --> 00:09:00,390 So now, now that I know all the directions 237 00:09:00,390 --> 00:09:02,070 and everything, I can just subtract the numbers. 238 00:09:02,070 --> 00:09:04,530 So I can now say, "Hey, my net force 239 00:09:04,530 --> 00:09:08,640 that is 210 newtons should equal this bigger number, 240 00:09:08,640 --> 00:09:13,443 the bigger force minus 200 newtons. 241 00:09:14,610 --> 00:09:17,850 Now, to get applied force, I just add 200 on both sides 242 00:09:17,850 --> 00:09:20,283 so that I can get rid of this. 243 00:09:22,050 --> 00:09:27,050 And look, the applied force becomes 210 plus 200. 244 00:09:27,150 --> 00:09:31,170 That is 410 newtons. 245 00:09:31,170 --> 00:09:32,880 And I already know it's to the right, 246 00:09:32,880 --> 00:09:34,440 so I know it's direction. 247 00:09:34,440 --> 00:09:37,110 So if I were to write down its direction, 248 00:09:37,110 --> 00:09:39,115 it's going to be, oops. (chuckles) 249 00:09:39,115 --> 00:09:39,990 Okay. Okay. 250 00:09:39,990 --> 00:09:42,990 I mean, okay, not the most organized board over here, 251 00:09:42,990 --> 00:09:45,420 but let me just write it down a little bit more neatly. 252 00:09:45,420 --> 00:09:49,410 So 410 newtons to the right. 253 00:09:49,410 --> 00:09:51,390 That's how much force we need to apply 254 00:09:51,390 --> 00:09:53,013 for all of this to happen.