1 00:00:00,890 --> 00:00:04,865 >> This configuration is known as a summing amplifier. 2 00:00:04,865 --> 00:00:07,050 We are going to find that it takes 3 00:00:07,050 --> 00:00:09,495 its name from the fact that the output voltage is going to 4 00:00:09,495 --> 00:00:15,030 equal a scaled version of the sum of V_1 and V_2. 5 00:00:15,030 --> 00:00:18,465 To analyze this, we're going to do as we always have and that is write 6 00:00:18,465 --> 00:00:22,305 a node equation at the inverting terminal. 7 00:00:22,305 --> 00:00:24,810 Once again, we have the virtual short here 8 00:00:24,810 --> 00:00:26,880 that tells us that V sub n is equal to V sub p, 9 00:00:26,880 --> 00:00:30,795 and again in this case, the non-inverting terminal is tied to ground. 10 00:00:30,795 --> 00:00:34,690 So, V sub n is going to equal zero. 11 00:00:35,060 --> 00:00:40,520 But again, we'll leave V sub n in there to see what's happening, 12 00:00:40,520 --> 00:00:43,685 and then as we move along we'll replace V sub n with zero. 13 00:00:43,685 --> 00:00:48,095 So, let's sum the currents here at this terminal. 14 00:00:48,095 --> 00:00:51,870 Notice that we now have three branches one, two, 15 00:00:51,870 --> 00:00:54,610 three branches connected to the node in 16 00:00:54,610 --> 00:00:57,290 addition to this branch here coming to the inverting terminal, 17 00:00:57,290 --> 00:01:00,200 which is still once again going to have no current going in there. 18 00:01:00,200 --> 00:01:02,870 So, let's write the equations here, 19 00:01:02,870 --> 00:01:04,670 or the equation here. 20 00:01:04,670 --> 00:01:10,370 The current leaving V sub n going in this path is going to 21 00:01:10,370 --> 00:01:16,750 be V sub n minus V_1 divided by R_1, 22 00:01:16,750 --> 00:01:20,180 plus the current leaving this node going in 23 00:01:20,180 --> 00:01:26,615 this direction is going to be V sub n minus V_2, 24 00:01:26,615 --> 00:01:31,760 divided by R_2, plus the current in the feedback loop, 25 00:01:31,760 --> 00:01:39,210 which is going to be V sub n minus V-out divided by R sub f. As already mentioned, 26 00:01:39,210 --> 00:01:42,225 there is no current going into the amplifier itself, 27 00:01:42,225 --> 00:01:46,650 therefore the sum of those three terms equals zero. 28 00:01:46,870 --> 00:01:52,950 Again, noting that V sub n equals zero in each of these, 29 00:01:52,950 --> 00:02:01,710 we have then negative V_1 over R_1 plus negative V_2 30 00:02:01,710 --> 00:02:11,950 over R_2 equals V-out over R sub f. Now, 31 00:02:11,950 --> 00:02:16,250 if we multiply both sides of the equation by R sub f and factor out, 32 00:02:16,250 --> 00:02:20,615 this minus sign is there, 33 00:02:20,615 --> 00:02:26,299 we're going to have them that V-out is equal to 34 00:02:26,299 --> 00:02:33,635 negative R sub f over R_1 times V_1. 35 00:02:33,635 --> 00:02:35,735 Let's put a bracket around here, 36 00:02:35,735 --> 00:02:38,645 plus R sub f, 37 00:02:38,645 --> 00:02:44,070 over R_2 times V_2. 38 00:02:44,170 --> 00:02:48,255 That's supposed to be a plus sign there. 39 00:02:48,255 --> 00:02:52,460 As advertised, the output then is the sum of 40 00:02:52,460 --> 00:02:58,160 the two input voltages scaled by the ratios of the feedback resistance to either R_1, 41 00:02:58,160 --> 00:03:02,320 in the case of V_1, or the feedback resistor divided by R_2 42 00:03:02,320 --> 00:03:09,030 for the second input voltage. 43 00:03:09,030 --> 00:03:13,985 Now, it'll be pretty obvious that if we want the scaling factor to be the same, 44 00:03:13,985 --> 00:03:17,305 we simply make R_1 equal R_2. 45 00:03:17,305 --> 00:03:26,770 Under those circumstances, the output voltage then would be negative R sub f over, 46 00:03:26,770 --> 00:03:30,000 call it R_1 or call it R_2, I guess so. 47 00:03:30,000 --> 00:03:35,845 Let's just be specific and let's say R_1 equals R_2, 48 00:03:35,845 --> 00:03:39,800 equals R sub s. So, 49 00:03:39,800 --> 00:03:49,215 our gain term then would be R sub f over R sub s times V_1 plus V_2. 50 00:03:49,215 --> 00:03:51,710 So, we have a minus sign again that is 51 00:03:51,710 --> 00:03:53,810 an inverted output due to the fact that 52 00:03:53,810 --> 00:03:56,825 these two sources are connected to the inverting terminal. 53 00:03:56,825 --> 00:03:58,850 With R_1 equaling R_2, 54 00:03:58,850 --> 00:04:01,264 both are amplified by the same amount, 55 00:04:01,264 --> 00:04:05,285 and we end up with a scaled version of the sum of those two. 56 00:04:05,285 --> 00:04:07,460 If we don't want any gain out of it, 57 00:04:07,460 --> 00:04:10,760 we simply make R sub f equal R_1 equal to R_2, 58 00:04:10,760 --> 00:04:17,430 and then the output voltage would be just V_1 plus V_2.