1 00:00:00,346 --> 00:00:04,009 欢迎观看第四级减法 2 00:00:04,009 --> 00:00:06,206 我们从一些问题开始吧~ 3 00:00:06,206 --> 00:00:21,804 第一个问题是用33,220减去399 4 00:00:21,804 --> 00:00:25,119 我相信我们可以处理它 5 00:00:25,119 --> 00:00:28,455 就用我们在上一次讲解中说过的“借位法” 6 00:00:28,455 --> 00:00:31,322 我们必须从上层的数字开始处理 7 00:00:31,322 --> 00:00:35,406 确保最右边的数字比 8 00:00:35,406 --> 00:00:37,623 它下面数的最右边的数大 9 00:00:37,623 --> 00:00:41,953 因为你只能从一个较大的数中 10 00:00:41,953 --> 00:00:42,970 减去一个较小的数 11 00:00:42,970 --> 00:00:44,616 至少到目前为止我们还没有学习“负数”时 12 00:00:44,616 --> 00:00:45,793 你只能这样处理它 13 00:00:45,793 --> 00:00:46,928 让我们查看一下这两个数 14 00:00:46,928 --> 00:00:48,899 用来确保所有上面的数字都是较大的 15 00:00:48,899 --> 00:00:50,465 好的,现在我们可以看到这里没有满足条件 16 00:00:50,465 --> 00:00:52,812 这里的0小于9 17 00:00:52,812 --> 00:00:56,077 所以我们必须向前借一位来使0更大 18 00:00:56,077 --> 00:00:59,544 我们所需要做的是向十位数借1 19 00:00:59,544 --> 00:01:01,229 像有些人说的我们“借位”了 20 00:01:01,229 --> 00:01:04,161 我的意思是有些人认为 21 00:01:04,161 --> 00:01:05,694 向十位数借1好像是借了10一样 22 00:01:05,694 --> 00:01:09,890 所以为了简化表达我们只说我们“借位” 23 00:01:09,890 --> 00:01:13,994 当你向十位数的“2”借1时 24 00:01:13,994 --> 00:01:18,282 个位上的“0”就变成了10 25 00:01:18,282 --> 00:01:21,796 同时十位数的2由于被“借位”,也会变成1 26 00:01:21,796 --> 00:01:26,183 再来回顾一遍——我们从十位的“2”借走1给个位上的“0”使之变成10 27 00:01:26,183 --> 00:01:29,282 事实上我们从“2”拿走的是10 28 00:01:29,282 --> 00:01:30,649 因为这个“2”在十位上 29 00:01:30,649 --> 00:01:31,816 我希望你们不会我的话迷惑了 30 00:01:31,816 --> 00:01:35,584 这个运算过程只是从“2”拿走1 31 00:01:35,584 --> 00:01:38,283 然后将它放在“0”前使之变成10 32 00:01:38,283 --> 00:01:40,583 现在让我们接着这样做下去 33 00:01:40,583 --> 00:01:42,267 在十位上我们只有“1”, 34 00:01:42,267 --> 00:01:45,616 因为“1”比下面的“9”小,所以我们需要继续“借位” 35 00:01:45,616 --> 00:01:49,950 我们从百位上的“2”借走1 36 00:01:49,950 --> 00:01:52,182 这个“2”就变成了“1” 37 00:01:52,182 --> 00:01:56,300 同时十位上的“1”变成了11 38 00:01:56,300 --> 00:01:59,600 这时候,我们在个位上有“10”,比下面的“9”大 39 00:01:59,600 --> 00:02:01,866 十位上的“11”也比下面的“9”要大 40 00:02:01,866 --> 00:02:05,982 但在百位上“1”比下面的“3”小,因此我们继续运用“借位”的方法 41 00:02:05,982 --> 00:02:07,867 只是一个很典型的例题 42 00:02:07,867 --> 00:02:10,726 也许在这里我该给你一点注意事项了 43 00:02:10,726 --> 00:02:11,844 它和“借位”法有很大的联系 44 00:02:11,844 --> 00:02:14,128 就像例题中展示的一样,为了“借位”我们重复同样的步骤 45 00:02:14,128 --> 00:02:16,878 让十位上的“1”变成“11” 46 00:02:16,878 --> 00:02:20,344 然后接着从千位上的"3"借走1让它变成2 47 00:02:20,344 --> 00:02:22,511 我想我们已经做到了 48 00:02:22,511 --> 00:02:26,580 个位上10大于9 49 00:02:26,580 --> 00:02:27,912 十位上11大于9,百位上11大于3 50 00:02:27,912 --> 00:02:29,111 千位的2和万位上的3下面没有数字 51 00:02:29,111 --> 00:02:31,111 现在,我们为减法做好了准备 52 00:02:31,111 --> 00:02:32,579 剩下部分的就十分简单了 53 00:02:32,579 --> 00:02:34,495 10减去9是1 54 00:02:34,495 --> 00:02:38,245 11减去9是2 55 00:02:38,245 --> 00:02:44,462 11减去3是8 56 00:02:44,462 --> 00:02:47,996 2减去0是2 57 00:02:47,996 --> 00:02:50,344 3减去0是3 58 00:02:50,344 --> 00:02:54,694 因此我们就得到了结果——32,821 59 00:02:54,694 --> 00:03:00,029 这道例题比一般的减法难在 60 00:03:00,029 --> 00:03:01,402 你需要知道如何“借位” 61 00:03:01,402 --> 00:03:03,621 在这里我所用的“借位”法可能和你们在学校习得的 62 00:03:03,621 --> 00:03:05,306 有所区别,不过我相信这种方法更为简单 63 00:03:05,306 --> 00:03:08,253 因为你一次做完了所有的“借位”工作,而不是 64 00:03:08,253 --> 00:03:11,103 在来回使用“借位”和“减法”的步骤 65 00:03:11,103 --> 00:03:13,880 看看我们已经完成的工作:个位上的0小于9 66 00:03:13,880 --> 00:03:15,097 于是便向十位借1 67 00:03:15,097 --> 00:03:18,097 把十位上的1放在个位前使得个位上的0变成了10 68 00:03:18,097 --> 00:03:22,256 我们又从百位上的2借走1,百位上的2变成1 69 00:03:22,256 --> 00:03:25,003 我相信如果我们再做一些练习 70 00:03:25,003 --> 00:03:26,486 你可以更加熟悉这种规律 71 00:03:26,486 --> 00:03:28,020 那么我们就再来解决一些题目吧 72 00:03:28,020 --> 00:03:46,937 这里我用25,633减去578 73 00:03:46,937 --> 00:03:49,151 这是练习题 74 00:03:49,151 --> 00:03:52,569 从上方的数的最右端开始 75 00:03:52,569 --> 00:03:55,387 确保上面的每个数都大于它下面的数 76 00:03:55,387 --> 00:04:00,016 现在我们看到个位的“3”小于下面的“8”于是我们“借位” 77 00:04:00,016 --> 00:04:02,790 使这个“3”变成“13” 78 00:04:02,790 --> 00:04:09,072 接着我们从这个3借位,使它变成2 79 00:04:09,072 --> 00:04:13,482 因为十位上的“3”被借走“1”,它变成“2” 80 00:04:13,482 --> 00:04:15,025 同时它减少的“1”被加在了个位这里 81 00:04:15,025 --> 00:04:19,955 个位上有“13”大于“8”,但十位上的“2”小于下面的“7” 82 00:04:19,955 --> 00:04:21,025 于是我们继续“借位” 83 00:04:21,025 --> 00:04:23,107 让十位的“2”变成“12” 84 00:04:23,107 --> 00:04:27,307 百位上的“6”变成“5” 85 00:04:27,307 --> 00:04:31,874 个位上“13”大于“8”,十位上“12”大于“7” 86 00:04:31,874 --> 00:04:36,056 百位上上下都是“5”,因此我们可以开始做减法了 87 00:04:36,056 --> 00:04:38,839 百位上的5减去5等于0 88 00:04:38,839 --> 00:04:41,333 记住我们做减法的前提是“只要上方的数字不小于 89 00:04:41,333 --> 00:04:42,495 它下面的数字” 90 00:04:42,495 --> 00:04:44,459 很明显千位上的5比下面的0要大 91 00:04:44,459 --> 00:04:46,436 万位上的2也大于下面的0 92 00:04:46,436 --> 00:04:48,336 我们的确是做好了进行减法的准备 93 00:04:48,336 --> 00:04:52,943 个位上:13-8=5 94 00:04:52,943 --> 00:04:57,444 十位上:12-8=5 95 00:04:57,444 --> 00:05:00,559 百位上:5-5=0 96 00:05:00,559 --> 00:05:03,161 千位上:5-0=5 97 00:05:03,161 --> 00:05:05,861 万位上的2也可以直接写下来 98 00:05:05,861 --> 00:05:12,194 因此结果是25,055 99 00:05:12,194 --> 00:05:17,326 让我们再来做一道题目 100 00:05:17,326 --> 00:05:20,127 因为这里的“借位”可能不是那么简单也许你会感到有些迷惑 101 00:05:20,127 --> 00:05:21,994 你需要掌握多重“借位” 102 00:05:21,994 --> 00:05:38,176 让我用37,002减去155 103 00:05:38,176 --> 00:05:41,327 这同样是练习题 104 00:05:41,327 --> 00:05:45,093 个位上2小于5,因此我们需要“借位” 105 00:05:45,093 --> 00:05:47,861 这个“2”就变成了“12” 106 00:05:47,861 --> 00:05:51,661 但是这里的十位上是0,你不能向0“借位“ 107 00:05:51,661 --> 00:05:53,577 有些人也许会教你可以向0“借位” 108 00:05:53,577 --> 00:05:55,210 但我认为那是不可理解的,因为你不能 109 00:05:55,210 --> 00:05:57,277 向0“借位”,0这里什么都没有 110 00:05:57,277 --> 00:05:59,961 为了避免想十位的“0”借位,我们继续向百位“借位” 111 00:05:59,961 --> 00:06:01,227 但百位上也是“0” 112 00:06:01,227 --> 00:06:03,694 于是我们只好继续向前借位,千位上有个“7” 113 00:06:03,694 --> 00:06:07,612 在这里我们所做的是为了避免向“0”借“1” 114 00:06:07,612 --> 00:06:14,177 历经重重我们成功从千位上的“700”借走了“1” 115 00:06:14,177 --> 00:06:17,361 那么这个“700”减去“1”之后又剩下什么呢 116 00:06:17,361 --> 00:06:20,211 是的,还有699 117 00:06:20,211 --> 00:06:25,177 因此从千位到十位的“700” 118 00:06:25,177 --> 00:06:28,527 让我把这三个数都划掉把这些都划掉 119 00:06:28,527 --> 00:06:31,328 现在,我们再来检查一下这两行数 120 00:06:31,328 --> 00:06:37,329 个位“12”比下面的“5”大,十位“9”比“下面的5” 121 00:06:37,329 --> 00:06:40,579 百位“9”比下面的“1”大,千位的“6”和万位“3”下面都大于下面的0 122 00:06:40,579 --> 00:06:41,912 很好,我们准备好进行减法了 123 00:06:41,912 --> 00:06:44,894 个位:12-5=7 124 00:06:44,894 --> 00:06:47,777 十位:9-5=4 125 00:06:47,777 --> 00:06:50,644 百位:9-1=8 126 00:06:50,644 --> 00:06:53,645 千位:6-0=6 127 00:06:53,645 --> 00:06:56,028 万位:3-0=3 128 00:06:56,028 --> 00:06:57,345 到这里我们就做完了 129 00:06:57,345 --> 00:07:01,761 答案是36,847 130 00:07:01,761 --> 00:07:04,662 我觉得我们还有时间多做一道题 131 00:07:04,662 --> 00:07:20,094 这里,用3201减去502 132 00:07:20,094 --> 00:07:22,611 还是练习题 133 00:07:22,611 --> 00:07:25,578 个位上“1”比下面的“2”小,让我们用“借位”法 134 00:07:25,578 --> 00:07:28,227 让它变成“11” 135 00:07:28,227 --> 00:07:30,569 但你不能向“0”借位 136 00:07:30,569 --> 00:07:31,969 于是不得不再向前移一位,从整个“20”中借位 137 00:07:31,969 --> 00:07:34,520 好的,那这个“20”减去“1”是? 138 00:07:34,520 --> 00:07:37,004 很好,就是“19” 139 00:07:37,004 --> 00:07:38,897 这里变成“19” 140 00:07:38,897 --> 00:07:41,599 让我们再检查一遍 141 00:07:41,599 --> 00:07:43,207 个位“11”大于下面的“2” 142 00:07:43,207 --> 00:07:44,130 很好 143 00:07:44,157 --> 00:07:45,794 十位上“9”也比下面的“0”要大 144 00:07:45,794 --> 00:07:46,573 很好 145 00:07:46,573 --> 00:07:47,393 啊—— 146 00:07:47,393 --> 00:07:49,598 百位上的“1”小于下面的“5” 147 00:07:49,598 --> 00:07:50,748 我们只好接着借位 148 00:07:50,748 --> 00:07:52,483 让这个“1”变成“11” 149 00:07:52,483 --> 00:07:54,482 我们从“3”借走了1于是它变成了“2” 150 00:07:54,482 --> 00:08:01,287 现在个位“11”大于“2”,十位“9”大于“0” 151 00:08:01,287 --> 00:08:04,136 百位“11”大于“5”,千位“2”显然比下面的“0”大 152 00:08:04,136 --> 00:08:05,436 我们再次做好准备开始减法 153 00:08:05,436 --> 00:08:08,588 个位:11-2=9 154 00:08:08,588 --> 00:08:11,469 十位:9-0=9 155 00:08:11,469 --> 00:08:14,320 百位:11-5=6 156 00:08:14,320 --> 00:08:16,903 千位:2-0=0 157 00:08:16,903 --> 00:08:25,904 因此3,201-502=2699 158 00:08:25,904 --> 00:08:27,737 我想你现在也许跃跃欲试想要亲自运用本次课 159 00:08:27,737 --> 00:08:29,453 的方法解决一些减法题了吧 160 00:08:29,453 --> 00:08:30,686 你只需要记住 161 00:08:30,686 --> 00:08:32,638 先做“借位” 162 00:08:32,638 --> 00:08:35,638 保证上面的每个数都大于它下面对应的数字 163 00:08:35,638 --> 00:08:38,438 至少要和下面的一样大 164 00:08:38,438 --> 00:08:40,171 然后你就可以进行减法运算了 165 00:08:40,171 --> 00:08:41,838 像一个正常的减法一样 166 00:08:41,838 --> 00:08:43,985 我希望你可以从中得到些许乐趣 167 00:08:43,985 --> 00:08:45,320 我们下次课再见~