- [Voiceover] The figure above shows the graph of f prime,
the derivative of a twice-differentiable function f,
on the interval, that's a closed interval,
from negative three to four.
The graph of f prime has horizontal tangents
at x equals negative one, x equals one,
and x equals three.
So you have a horizontal tangent right over,
a horizontal tangent right over there.
And let me draw that a little bit neater,
right over there,
a horizontal tangent right over there,
and a horizontal tangent right over there.
Alright.
The areas of the regions bounded
by the x-axis and the graph of f prime
on the intervals negative two to one,
closed intervals from negative two to one,
so this region right over here,
and the region from one to four,
so this region right over there,
they tell us have,
have the areas are 9 and 12, respectively.
So that area's 9 and that area is 12.
So Part A,
Find all x coordinates at which f has a relative maximum.
Give a reason for your answer.
All x-coordinates at which f
has a relative maximum.
So you might say,
"Oh wait, wait this looks like a relative maximum
over here, but this isn't f.
This is the graph of f prime."
So let's think about when we used to
we don't have a graph of f in front of us.
So let's think about what it needs to be true
for f to have a relative maximum at a point.
We are probably familiar with
what relative maximum will look like.
It'd look like a little lump, like that.
It could also actually look like that
but since this is differentiable function
over the interval, we're probably not dealing
with a relative maximum that looks like that.
And so what do we know about a relative maximum point?
So let's say that's our relative maximum.
As we approach our relative maximum
from values, as we have x values that are approaching
the x value of our relative maximum point,
as we approach it from values below that x value,
we see that we have a positive slope.
Our function needs to be increasing.
So over here.
Over here we see f is increasing,
going into the relative maximum point,
f is increasing,
which means that the derivative of f
the derivative of f must be greater than zero.
And then after we past that maximum point,
after we past that maximum point,
we see that our function needs to be decreasing.
Do this in another color.
We see that our funciton is decreasing
right over here, so f decreasing,
decreasing, which means
that f prime of x needs to be less than zero.
So our relative maximum point
should happen at an x value.
It should happen at an x value
where our first derivative transitions
from being greater than zero
to being less than zero.
So what x value,
so let me say this,
so we have
f has relative, let me just write it shorthand,
relative maximum at x values
where
f prime transitions,
transitions,
transitions from
from positive, positive,
to negative, to, let me write this a little bit neater,
to negative.
And where do we see f prime transitioning
from positive to negative?
Well over here we only see that happening once.
We see right here f prime is positive, positive, positive,
and then it goes negative, negative, negative.
So we see,
we see f prime is positive over here,
And then, right when we hit x equals negative two,
f prime becomes negative.
F prime becomes negative.
So we know that the function itself,
not f prime,
f must be increasing here
because f prime is positive,
and then our function at f
is decreasing here
because f prime is negative.
And so this happens at x equals two.
So let me write that down.
This happens at x equals two.
This happens,
happens at x equals two.
And we're done.