0:00:00.780,0:00:02.220
Nou sou pwoblem senkant twa.

0:00:02.220,0:00:04.820
Li di Toni ap rezoud ekwasyon sa a pa ranpli a

0:00:04.820,0:00:08.430
kare. "ax" kare plis "bx" plis "c" se egal a "0", kote yon "a"

0:00:08.430,0:00:09.325
pi gran pase "0."

0:00:09.325,0:00:11.525
Sa se yon kwadratik tradisyonèl

0:00:11.525,0:00:13.550
Ann nou wè sa yo te fe la

0:00:13.550,0:00:17.660
Premye, li soustrè "c" sou toude bò ak li resevwa "ax."

0:00:17.660,0:00:20.950
kare plis "bx" ki egal a soustrè "c."