WEBVTT 00:00:01.888 --> 00:00:09.539 In this video we will look at a couple of examples to practice thinking about conjectures and counter examples. 00:00:09.677 --> 00:00:17.844 Example A says: here's an algebraic equation and a table of values for n with the results for t. 00:00:18.044 --> 00:00:20.449 Notice that we started out with this equation: 00:00:25.557 --> 00:00:28.717 And what we have here is really just a table, 00:00:30.317 --> 00:00:39.352 that's divided in three parts, we have our values for n, all sort of calculations in the middle, and our answer fot t. 00:00:39.352 --> 00:00:43.383 And after looking at the table, Pablo makes this conjecture: 00:00:43.383 --> 00:00:53.391 the value of (n-1)(n-2)(n-3), in other words, the answer for t is zero for any hole number value of n. 00:00:53.391 --> 00:00:58.938 So, he is basically saying, that no matter what number I plug in over on the left from n, 00:00:58.938 --> 00:01:02.002 my answer is always going to end up being zero 00:01:02.002 --> 00:01:05.269 because that's what happen in the first three times. So maybe it will always happen. 00:01:05.269 --> 00:01:09.902 The question that we have is: is this a valid, or true, conjecture? 00:01:09.902 --> 00:01:14.809 So, if it's true, it means that it would be true for any number that you plug in for n. 00:01:14.809 --> 00:01:19.133 So you can plug in 100, and the answer should still be zero for t. 00:01:19.133 --> 00:01:25.501 So let's just test it out. Let's just try 100. Let's say n=100. 00:01:25.501 --> 00:01:31.078 We are trying to see if t will actually be equal zero. So let's plug it in. 00:01:31.324 --> 00:01:39.119 We would have (100-1)(100-2)(100-3). 00:01:39.442 --> 00:01:41.283 100-1 is 99.. 00:01:41.683 --> 00:01:43.660 Then we've got times 98, 00:01:43.937 --> 00:01:45.579 and times 97. 00:01:45.949 --> 00:01:49.191 Now I know that the answer to that is not zero, 00:01:49.191 --> 00:01:55.234 because to have an answer zero you have to multiply some of the one of the line by zero. 00:01:55.234 --> 00:02:01.534 So, this number is not equal zero. It's just gonna be a big number, definetly not equal to zero. NOTE Paragraph 00:02:01.711 --> 00:02:06.371 So that means actually that his conjecture is not valid. 00:02:07.140 --> 00:02:15.396 It's not true and what I just did over here: n equals 100, that's a counter example. 00:02:15.642 --> 00:02:21.014 Because it's a specific example that shows that his conjecture is wrong. 00:02:21.014 --> 00:02:28.504 I can plug in, for example, 100 into that expression for t and my answer is not zero. Therefore, he is wrong. 00:02:28.504 --> 00:02:33.195 So a counter example is just one example to prove someone is wrong. 00:02:33.195 --> 00:02:38.808 That counter prefix means like going against the clean. 00:02:39.023 --> 00:02:42.072 Alright, let's look at example B: 00:02:43.241 --> 00:02:49.121 *Arthur is making figures for a graphic art project. He drew polygons and some of their diagonals.* 00:02:49.275 --> 00:02:55.714 And here we have four examples, based on these examples, Arthur made this conjecture: 00:02:55.714 --> 00:03:04.977 *if a convex polygon has n sides, then there are n-2 triangles drawn from any given vertex of the polygon.* 00:03:04.977 --> 00:03:10.522 So let's just think about what that means. He is saying that, if the shape has n sides, 00:03:10.522 --> 00:03:15.395 for example, this would be n equals 3, three sides, 00:03:15.765 --> 00:03:17.307 four sides, 00:03:17.768 --> 00:03:19.631 five sides, 00:03:20.462 --> 00:03:21.702 six sides. 00:03:21.778 --> 00:03:26.387 He is saying that there are always n minus 2 triangles. 00:03:26.387 --> 00:03:36.625 So, for example, if n is five, 5-2 is 3, he is saying, in this example, there are 3 triangles: one, two, three. 00:03:36.625 --> 00:03:42.909 And in the next one that are four triangles, which is 6-2. 00:03:42.909 --> 00:03:49.726 So, the question is: is Arthur's conjecture correct? Can you find a counter example to his conjecture? 00:03:49.726 --> 00:03:55.910 Well, his conjecture certainly appears to be correct based on the four examples that he has done. 00:03:55.910 --> 00:04:02.510 And we could do more examples and it would actually turn out that any example you'll try, it will be true, 00:04:02.510 --> 00:04:08.061 but you still haven't proven it, if you've just looked at examples, because it is still possible 00:04:08.061 --> 00:04:14.227 that that's another example out of there that you haven't thought out. That would be a counter example to his conjecture. 00:04:14.227 --> 00:04:15.973 So what we should say is: 00:04:15.973 --> 00:04:19.765 his conjecture appears to be true, 00:04:22.411 --> 00:04:24.496 but it still needs to be proven. 00:04:26.694 --> 00:04:35.403 Because just looking at examples isn't an official really proof for sure that it will always be true.