0:00:00.570,0:00:04.680 So I have got this block of wood here that has a mass of 5 kilograms 0:00:04.680,0:00:08.830 and it is sitting on some dirt and we are near the surface of the earth 0:00:08.830,0:00:16.720 and the coefficient of static friction between this type of wood and this type of dirt is 0.60 0:00:16.720,0:00:23.030 and the coefficient of kinetic friction between this type of wood and this type of dirt is 0.55 0:00:23.030,0:00:25.630 This was measured by someone else long ago 0:00:25.630,0:00:28.060 or you found it in some type of a book someplace 0:00:28.060,0:00:32.300 And let's say we push on this side of the block with a force of a 100 N 0:00:32.300,0:00:34.440 What is going to happen? 0:00:34.440,0:00:37.250 So the first thing you might realize is if there is no friction 0:00:37.250,0:00:39.310 if this was a completely frictionless boundary and there is 0:00:39.310,0:00:42.640 no air resistance, we are assuming that there is no air resistance in this example 0:00:42.640,0:00:45.320 That in this dimension, in the horizontal dimension 0:00:45.320,0:00:48.220 there would only be one force here, this 100 N force 0:00:48.220,0:00:51.810 It would be completely unbalanced and that would be the net force 0:00:51.810,0:00:56.350 and so you would have a force going in that direction of a 100 N on a mass of 5 kilograms 0:00:56.350,0:00:59.540 Force = Mass times acceleration 0:00:59.540,0:01:01.580 acceleration and force are vector quantities 0:01:01.580,0:01:04.110 So you would have the force divided by the mass 0:01:04.110,0:01:08.640 would give you 20 meters per second of acceleration in the rightward direction 0:01:08.640,0:01:10.950 That is if there were no friction 0:01:10.950,0:01:13.040 but there is friction in this situation 0:01:13.040,0:01:15.160 So let's think about how we'll deal with it 0:01:15.160,0:01:17.950 So the coefficient of friction tells us 0:01:17.950,0:01:22.740 So this right here is the ratio between the magnitude of the force 0:01:22.740,0:01:24.460 that I have called the budging force 0:01:24.460,0:01:28.820 The amount of force you need to apply to get this thing to budge 0:01:28.820,0:01:32.670 to get this thing to start moving. So we can start using the coefficient of kinetic friction 0:01:32.670,0:01:38.200 It's the ratio between that and the magnitude of the force of contact 0:01:38.200,0:01:41.100 between this block and the floor or ground here 0:01:41.100,0:01:44.040 And the magnitude of that force of contact is the same thing 0:01:44.040,0:01:48.410 as the normal force that the ground is applying on the block 0:01:48.410,0:01:52.810 the magnitude of the normal force the ground is applying on the block 0:01:52.810,0:01:54.150 Then once its moving 0:01:54.150,0:01:58.650 then we can say that this is going to be--this will then be equal to 0:01:58.650,0:02:01.710 this over here will be equal to the force of friction 0:02:01.710,0:02:05.140 So this is the force that really overcome friction 0:02:05.140,0:02:08.360 and this over here will be equal to the force of friction 0:02:08.360,0:02:13.280 The magnitude of the force of friction over the force of contact 0:02:13.280,0:02:16.720 the contact force between those two, so over the normal force 0:02:16.720,0:02:18.140 and it makes sense 0:02:18.140,0:02:21.030 that the larger the contact force 0:02:21.030,0:02:23.050 the more that these are being pressed together 0:02:23.050,0:02:26.210 the little at the atomic level, they kind of really get into each others grooves 0:02:26.210,0:02:28.430 the more budging force you would need 0:02:28.430,0:02:31.620 or the more friction force would go against your motion 0:02:31.620,0:02:33.650 And in either situation 0:02:33.650,0:02:35.920 the force of friction is going against your motion 0:02:35.920,0:02:37.320 So even if you push it in that way 0:02:37.320,0:02:40.420 sounds like force of friction is all of a sudden going to help you 0:02:40.420,0:02:44.160 So let's think about what the necessary force will we need 0:02:44.160,0:02:47.500 to overcome the force of friction right here in the static situation 0:02:47.500,0:02:51.960 So the force of gravity on this block 0:02:51.960,0:02:57.760 is going to be the gravitational field which is 9.8 m/s^2 times 5 kilograms 0:02:57.760,0:03:05.550 9.8 m/s times 5 kilograms gives 49 kilogram meters per second or 49 newtons down 0:03:05.550,0:03:08.390 This is the force, the magnitude of the force due to gravity 0:03:08.390,0:03:11.540 the direction is straight down towards the center of the earth 0:03:11.540,0:03:17.140 The normal force, and that force is there because this block is not accelerating downwards 0:03:17.140,0:03:21.390 So there must be some force that completely balances off the force of gravity 0:03:21.390,0:03:26.030 And in this example, it is the normal force 0:03:26.030,0:03:30.100 So it is acting 49 newtons upward 0:03:30.100,0:03:35.060 and so these net out. And that's why this block does not accelerate upwards or downwards 0:03:35.060,0:03:36.970 So what we have is the budge the 0:03:36.970,0:03:41.050 magnitude of the budging force, needs to be equal to, over the magnitude of the normal force 0:03:41.050,0:03:43.620 well this thing right over here is going to be 49 newtons 0:03:43.620,0:03:46.810 Is equal to 0.60 0:03:46.810,0:03:52.370 Or we could say that the magnitude of the budging force 0:03:52.370,0:03:56.700 is equal to 49 newtons times the coefficient of static fiction 0:03:56.700,0:04:06.710 Or that's 49 newtons times 0.60 0:04:06.710,0:04:09.910 And remember coefficient of friction are unitless 0:04:09.910,0:04:13.040 So the units here are still going to be in newtons 0:04:13.040,0:04:22.580 So this 49 times .6 gives us 29.4 newtons 0:04:22.580,0:04:30.550 This is equal to 29.4 newtons 0:04:30.550,0:04:34.520 So that's the force that's started to overcome static friction 0:04:34.520,0:04:36.790 which we are applying more than enough of 0:04:36.790,0:04:39.920 so with a 100 newtons, we would just start to budge it 0:04:39.920,0:04:42.100 and right when we are in just in that moment 0:04:42.100,0:04:44.190 where that thing is just starting to move 0:04:44.190,0:04:45.580 the net force-- 0:04:45.580,0:04:47.670 so we have a 100 newtons going in that direction 0:04:47.670,0:04:51.090 and the force of static friction is going to go in this direction-- 0:04:51.090,0:04:53.580 maybe I could draw it down here to show it's coming from right over here 0:04:53.580,0:04:57.970 The force of static friction is going to be 29.4 newtons that way 0:04:57.970,0:05:00.650 and so right when I am just starting to budge this 0:05:00.650,0:05:03.030 just when that little movement-- 0:05:03.070,0:05:04.930 because once I do that, then all of a sudden it's moving 0:05:05.030,0:05:09.180 and then kinetic friction starts to matter, but just for that moment 0:05:09.650,0:05:15.930 just for that moment I'll have a net force of 100 - 29.4 0:05:16.360,0:05:28.660 to the right, so I have a net force of 70.6 N 0:05:28.660,0:05:32.820 for just a moment while I budge it 0:05:32.820,0:05:35.250 So just exactly while I'm budging it 0:05:35.250,0:05:42.380 While we're overcoming the static friction, we have a 70.6 N net force in the right direction 0:05:42.690,0:05:47.980 And so just for that moment, you divide it by 5 kg mass 0:05:48.000,0:05:52.430 So just for that moment, it will be accelerating at 14.12 m/s^2 0:05:53.050,0:06:00.280 So you'll have an acceleration of 14.1 m/s^2 to the right 0:06:00.300,0:06:04.250 but that will just be for that absolute moment, because once I budge it 0:06:04.360,0:06:07.420 all of a sudden the block will start to be moving 0:06:07.440,0:06:10.880 And once it's moving, the coefficient of kinetic friction starts to matter 0:06:10.880,0:06:12.880 We've got the things out of their little grooves 0:06:12.900,0:06:17.160 and so they're kind of gliding past each other on the top, although there still is resistant 0:06:17.200,0:06:20.550 So once we budge it, we'll have that acceleration for just a moment 0:06:20.560,0:06:23.550 Now all of a sudden, the coefficient of kinetic friction comes to play 0:06:23.930,0:06:27.080 And the force of friction, assuming we're moving 0:06:27.410,0:06:31.120 the magnitude of the force of friction will always go against our movement 0:06:31.550,0:06:35.460 is going to be--remember, our normal force is 49 N 0:06:35.700,0:06:38.850 So we can multiply both sides of this times 49 0:06:39.000,0:06:57.780 We get 49 N times 0.55 which is equal to 26.95 N 0:06:57.800,0:07:00.400 This is the force of friction; this is the magnitude 0:07:00.520,0:07:02.400 and it's going to go against our motions 0:07:02.410,0:07:05.690 So as soon as we start to move in that direction, the force of friction 0:07:05.890,0:07:09.480 is going to be going in that direction 0:07:09.740,0:07:15.050 So once we start moving, assuming that I'm continuing to apply this 100 newtons of force 0:07:15.130,0:07:18.280 what is the net force? So I have 100 N going that way 0:07:18.380,0:07:23.180 and I have 26.95 going that way 0:07:23.200,0:07:25.080 Remember, with vectors, I don't have to draw them here 0:07:25.080,0:07:28.890 I can draw all of their tails start at the center of mass of the 0:07:28.890,0:07:32.810 object. I can draw them whatever, but remember this is acting on the object 0:07:32.810,0:07:37.140 If we want to be precise, we can show it on the center of mass because 0:07:37.140,0:07:39.940 we can view all of these atoms as one collective object 0:07:39.950,0:07:42.150 But anyway, what is the net force now? 0:07:42.160,0:07:46.420 We have 100 N to the right; we have 26.95 to the left 0:07:47.080,0:07:51.750 100 minus 26.95 0:07:51.750,0:07:53.600 100 N that I'm applying to the right 0:07:53.600,0:07:59.260 - 26.95 N which is the force of friction to the left always acting against us 0:07:59.410,0:08:03.410 means that there's a net force to the right of 73.05 0:08:03.430,0:08:10.840 So once we're moving, we have a net force to the right of 73.05 N 0:08:10.840,0:08:18.070 This is the net force and it's acting to the right 0:08:18.260,0:08:22.850 Right after we budge it, how quickly will this accelerate? 0:08:22.850,0:08:32.700 Well, 73.05 divided by the mass, divided by 5 kg, gives us 14.61 0:08:33.220,0:08:40.430 So the acceleration once we're moving is going to be 14.61 m/s squared 0:08:40.630,0:08:44.450 to the right 0:08:44.490,0:08:47.190 So I really want to make sure you understand what's happening here 0:08:47.220,0:08:51.270 We always have enough force to start budging it 0:08:51.560,0:08:53.510 but right when we budged it 0:08:53.510,0:08:56.430 we overcome the static friction for just a moment 0:08:56.430,0:08:59.810 our acceleration was slower 0:08:59.820,0:09:01.900 because we're overcoming that static friction 0:09:01.900,0:09:04.900 but once we budged it and once it's moving 0:09:04.920,0:09:08.600 and assuming that we're continuing to apply a constant force over here 0:09:08.790,0:09:10.480 then all of a sudden, the force of friction since 0:09:10.480,0:09:14.400 we're kind of bump it along the top now and not stuck in their grooves 0:09:14.920,0:09:17.570 we're now using the coefficient of kinetic friction 0:09:17.590,0:09:22.780 And so once it's moving, the net force becomes greater in the rightward direction because 0:09:22.930,0:09:27.590 you can kind of view that force of friction will become less once it starts moving 0:09:27.790,0:09:31.820 And so now the force of friction went down a little bit to 26.95 N 0:09:31.870,0:09:38.630 And so now we're accelerating to right at a slightly faster rate 14.61 m/s^2 0:09:38.640,0:09:41.860 So right when you budge it, it accelerates at 14.1 m/s^2 0:09:41.860,0:09:44.870 but just for a moment, almost unnoticeable moment once it starts moving 0:09:44.920,0:09:48.780 Then you're going to be going to the right with this constant acceleration