9:59:59.000,9:59:59.000
1[br]00:00:00,000 --> 00:00:00,700[br].

9:59:59.000,9:59:59.000
2[br]00:00:00,700 --> 00:00:06,250[br]မ်ဥ္းတစ္ေၾကာင္းက (-3,6) ႏွင့္ (6,0) ဆိုုတဲ့ အမွတ္ေတြကိုုၿဖတ္သြားတယ္.

9:59:59.000,9:59:59.000
3[br]00:00:06,250 --> 00:00:09,390[br]အဲ့ဒီမ်ဥ္းအတြက္ equation ကိုု point slope form, slope intercept form,[br][br]4[br]00:00:09,390 --> 00:00:11,860[br] ႏွင့္ standard form ပံုုစံတိုု႔ျဖင့္ရွာေပးပါ.

9:59:59.000,9:59:59.000
5[br]00:00:11,860 --> 00:00:13,970[br]ဒါကေတာ့

9:59:59.000,9:59:59.000
6[br]00:00:13,970 --> 00:00:16,030[br]equation တစ္ေၾကာင္းထဲကိုု 3 မ်ိုဳးေရးတာနဲ႔ တူတူပါပဲ.

9:59:59.000,9:59:59.000
7[br]00:00:16,030 --> 00:00:18,220[br]ဒီ 3 မ်ိဳးထဲက 1 မ်ိုဳး ကိုုရရင္, က်န္တဲ့ 2 မ်ိဳးကိုု

9:59:59.000,9:59:59.000
8[br]00:00:18,220 --> 00:00:19,230[br]ျပန္ေၿပာင္းေရးႏိုုင္ပါၿပီ.

9:59:59.000,9:59:59.000
9[br]00:00:19,230 --> 00:00:23,890[br]ဒါေပမယ့္ အဲဒါေတြက ဘာေတြလဲဆိုုရင္, point slope form ဆိုုတာ

9:59:59.000,9:59:59.000
10[br]00:00:23,890 --> 00:00:28,500[br]x1 ႏွင့္ y1 က မ်ဥ္းတစ္ေၾကာင္းေပၚက

9:59:59.000,9:59:59.000
11[br]00:00:28,500 --> 00:00:30,160[br]အမွတ္ေတြဆိုုပါေတာ့[br][br]12[br]00:00:30,160 --> 00:00:32,900[br]ဒီစာလံုုးေတြေအာက္နားက ခပ္ေသးေသးေရးထားတာကေတာ့

9:59:59.000,9:59:59.000
13[br]00:00:32,900 --> 00:00:34,750[br]တကယ္လိုု႔ x တစ္လုုံးပဲေရးထားရင္ေတာ့, ကြ်န္ေတာ္တုုိ႔က

9:59:59.000,9:59:59.000
14[br]00:00:34,750 --> 00:00:36,690[br]ဘယ္တန္ဖိုုးမဆိုုၿဖစ္ႏိုုင္တဲ့ ကိန္းရွင္တစ္ခုုကိုုေၿပာေနတာၿဖစ္ပါတယ္.

9:59:59.000,9:59:59.000
15[br]00:00:36,690 --> 00:00:39,770[br]တကယ္လိုု႔ x ႏွင့္ y ေအာက္နားေတြမွာ 1 ခပ္ေသးေသးေလးေတြေရးထားတယ္ ဆိုုရင္ေတာ့

9:59:59.000,9:59:59.000
16[br]00:00:39,770 --> 00:00:45,150[br]ဒါဟာ သီးသန္႔တန္ဖိုုးရွိတဲ့ x သိုု႔မဟုုတ္ y, ဒါမွမဟုုတ္

9:59:59.000,9:59:59.000
17[br]00:00:45,150 --> 00:00:48,450[br]coordinate တန္ဖိုုးတစ္ခုုကိုုဆိုုလုုိတာ ျဖစ္ပါတယ္.

9:59:59.000,9:59:59.000
18[br]00:00:48,450 --> 00:00:50,030[br]ကြ်န္ေတာ္တိုု႔ ဥပမာတြက္ရင္ ျမင္ရပါလိမ့္မယ္.

9:59:59.000,9:59:59.000
19[br]00:00:50,030 --> 00:00:52,480[br]ဒါေပမယ့္ point slope form ဆိုုတာက

9:59:59.000,9:59:59.000
20[br]00:00:52,480 --> 00:00:56,020[br]အမွတ္တစ္ခုု နဲ႔ မ်ဥ္းေၾကာင္းရဲ႕ slope ကိုုသိတယ္ ဆိုုပါေတာ့

9:59:59.000,9:59:59.000
21[br]00:00:56,020 --> 00:00:58,750[br]ဒါဆိုု အဲဒီ မ်ဥ္းကိုု point slope form နဲ႔ ေရးရရင္

9:59:59.000,9:59:59.000
22[br]00:00:58,750 --> 00:01:05,209[br]y-y1 = m*(x-x1)

9:59:59.000,9:59:59.000
23[br]00:01:05,209 --> 00:01:08,830[br]ဥပမာအားၿဖင့္

9:59:59.000,9:59:59.000
24[br]00:01:08,830 --> 00:01:13,170[br](-3,6)ဆိုုတဲ့ အမွတ္က မ်ဥ္းေပၚမွာဆုုိရင္ [br][br]25[br]00:01:13,170 --> 00:01:19,510[br]y-6= m(x-(-3)) လိုု႔ေၿပာလိုု႔ရပါတယ္

9:59:59.000,9:59:59.000
26[br]00:01:19,510 --> 00:01:21,120[br]ဒါဆိုု (x+3) ျဖစ္သြားပါမယ္.

9:59:59.000,9:59:59.000
27[br]00:01:21,120 --> 00:01:23,115[br]ဒါဟာ သီးသန္႔တန္ဖိုုးရွိတဲ့ x နဲ႔ y ပါ။

9:59:59.000,9:59:59.000
28[br]00:01:23,115 --> 00:01:25,130[br]ဒီေနရာမွာေတာ့ -3 နဲ႔ 6 ပါ။

9:59:59.000,9:59:59.000
29[br]00:01:25,130 --> 00:01:26,870[br]ဒါကေတာ့ point slope form ေပါ့။

9:59:59.000,9:59:59.000
30[br]00:01:26,870 --> 00:01:32,790[br]Slope intercept form ကေတာ့ y=mx+b

9:59:59.000,9:59:59.000
31[br]00:01:32,790 --> 00:01:36,810[br]ဒီမွာလည္း m က slope, b က 5y-၀င္ရိုုးကိုုၿဖတ္တဲ့အမွတ္

9:59:59.000,9:59:59.000
32[br]00:01:36,810 --> 00:01:40,180[br]တစ္နည္းအားၿဖင့္ x ကသုုညၿဖစ္တဲ့အခ်ိန္မွာရွိေနတဲ့

9:59:59.000,9:59:59.000
33[br]00:01:40,180 --> 00:01:41,680[br]y ရဲ႕တန္ဖိုုးပါ။

9:59:59.000,9:59:59.000
34[br]00:01:41,680 --> 00:01:47,680[br]Standard form ကေတာ့ ax+by=c,

9:59:59.000,9:59:59.000
35[br]00:01:47,680 --> 00:01:50,810[br]ဒါေတြက အေျခခံအားျဖင့္ ကိန္းဂဏန္း ၂ခုုပါပဲ။

9:59:59.000,9:59:59.000
36[br]00:01:50,810 --> 00:01:52,960[br]သုူတိုု႔က graph ေပၚမွာ

9:59:59.000,9:59:59.000
37[br]00:01:52,960 --> 00:01:54,430[br]တိုုက္ရိုုက္ပတ္သတ္မွဳမ်ိုဳးမရွိပါဘူး[br][br]38[br]00:01:54,430 --> 00:01:57,710[br]ကဲ ဒီ forms ေတြကိုု အေၿဖရွာၾကည့္ၾကပါစိုု႔

9:59:59.000,9:59:59.000
39[br]00:01:57,710 --> 00:01:59,900[br]ပထမဆံုုး slope ကိုုအရင္ရွာပါမယ္။

9:59:59.000,9:59:59.000
40[br]00:01:59,900 --> 00:02:02,610[br]Slope ကိုုသိၿပီဆိုုရင္ point slope form က

9:59:59.000,9:59:59.000
41[br]00:02:02,610 --> 00:02:05,820[br]တြက္ရတာ တကယ္ကိုု အရမ္းလြယ္သြားပါျပီ

9:59:59.000,9:59:59.000
42[br]00:02:05,820 --> 00:02:12,120[br]slope ျဖစ္တဲ့

9:59:59.000,9:59:59.000
43[br]00:02:12,120 --> 00:02:17,110[br]m  က y ေျပာင္းလဲမွဳကိုု x ေၿပာင္းလဲမွဳနဲ႔ စားတာပါ။[br][br]44[br]00:02:17,110 --> 00:02:18,480

9:59:59.000,9:59:59.000
45[br]00:02:18,480 --> 00:02:19,940[br]ဒါဆိုု y ေၿပာင္းလဲမွဳဆိုုတာ ဘာလဲ?

9:59:59.000,9:59:59.000
46[br]00:02:19,940 --> 00:02:23,610[br]ဒါကိုု ကြ်န္ေတာ္တိုု႔ရဲ႕အဆံုုးမွတ္လိုု႔သေဘာထားရင္

9:59:59.000,9:59:59.000
47[br]00:02:23,610 --> 00:02:26,190[br]ကြ်န္ေတာ္တိုု႔က ဒီကေနအဲဒီအမွတ္ကိုုသြားတယ္ဆိုုရင္

9:59:59.000,9:59:59.000
48[br]00:02:26,190 --> 00:02:27,460[br]y ေျပာင္းလဲမွဳကဘာလဲ?

9:59:59.000,9:59:59.000
49[br]00:02:27,460 --> 00:02:30,860[br]ကြ်န္ေတာ္တိုု႔မွာ 0 ဆိုုတဲ့အဆံုုးမွတ္တစ္ခုုရွိမယ္။ y က 6 ကစၿပီး

9:59:59.000,9:59:59.000
50[br]00:02:30,860 --> 00:02:33,300[br]0 မွာဆံုုးတယ္။

9:59:59.000,9:59:59.000
51[br]00:02:33,300 --> 00:02:38,650[br]ဒါဆိုု y ရဲ႕ ဆံုုးမွတ္က 0 ျဖစ္ၿပီး၊ စမွတ္က 6 ျဖစ္တယ္။

9:59:59.000,9:59:59.000
52[br]00:02:38,650 --> 00:02:41,870[br]ကြ်န္ေတာ္တိုု႔ xရဲ႕ ဆံုုးမွတ္ ဒါမွမဟုုတ္ x-coordinate ကဘာလဲ?

9:59:59.000,9:59:59.000
53[br]00:02:41,870 --> 00:02:44,810[br]x-coordinate က 6 ပါ။

9:59:59.000,9:59:59.000
54[br]00:02:44,810 --> 00:02:46,690[br]ကြ်န္ေတာ္ရွင္းေအာင္ၿပန္ေၿပာၿပပါမယ္။

9:59:59.000,9:59:59.000
55[br]00:02:46,690 --> 00:02:53,720[br]ဒါဆိုု ဒီ 0,

9:59:59.000,9:59:59.000
56[br]00:02:53,720 --> 00:02:59,330[br]ေနာက္ၿပီး ကြ်န္ေတာ္တိုု႔မွာ y ရဲ႕ စမွတ္ 6 ရွိတယ္။

9:59:59.000,9:59:59.000
57[br]00:02:59,330 --> 00:03:01,580[br]ေဟာဟိုုက 6 ပါ။

9:59:59.000,9:59:59.000
58[br]00:03:01,580 --> 00:03:06,000[br]ေနာက္ ကြ်န္ေတာ္တိုု႔က xရဲ႕ ဆံုုးမွတ္ကိုု လိုုခ်င္တယ္။ အဲဒါက ေဟာဒီက 6

9:59:59.000,9:59:59.000
59[br]00:03:06,000 --> 00:03:10,050[br]ဒါမွမဟုုတ္ ဒီ 6။ ေနာက္ၿပီး ကြ်န္ေတာ္တိုု႔က

9:59:59.000,9:59:59.000
60[br]00:03:10,050 --> 00:03:14,080[br]အဲဒါကိုု xရဲ႕ စမွတ္ကေန ႏွဳတ္ခ်င္တာပါ။

9:59:59.000,9:59:59.000
61[br]00:03:14,080 --> 00:03:16,800[br]xရဲ႕ စမွတ္က ေဟာဟိုုမွာပါ

9:59:59.000,9:59:59.000
62[br]00:03:16,800 --> 00:03:19,910[br]-3 ပဲျဖစ္ပါတယ္။

9:59:59.000,9:59:59.000
63[br]00:03:19,910 --> 00:03:21,880[br]ေသခ်ာေအာင္ျပန္ေျပာရရင္

9:59:59.000,9:59:59.000
64[br]00:03:21,880 --> 00:03:25,440[br]ဒီ -3 က ေဟာဟိုုက -3 ပါပဲ။[br][br]65[br]00:03:25,440 --> 00:03:29,500[br]ကြ်န္ေတာ္ေျပာတာက ဒီအမွတ္ကေနဒီအမွတ္ကိုုသြားရင္

9:59:59.000,9:59:59.000
66[br]00:03:29,500 --> 00:03:31,640[br]y က 6 မွတ္ေလ်ာ့သြားတယ္

9:59:59.000,9:59:59.000
67[br]00:03:31,640 --> 00:03:32,960[br]ကြ်န္ေတာ္တိုု႔ 6 ကေန 0 ကိုုေရာက္သြားတယ္။

9:59:59.000,9:59:59.000
68[br]00:03:32,960 --> 00:03:37,650[br]ကြ်န္ေတာ္တိုု႔ရဲ႕ y က 6 မွတ္ေလ်ာ့သြားပါတယ္။

9:59:59.000,9:59:59.000
69[br]00:03:37,650 --> 00:03:40,420[br]ဒါေၾကာင့္ 0-6 ဆိုုေတာ့ -6 ရပါတယ္။

9:59:59.000,9:59:59.000
70[br]00:03:40,420 --> 00:03:41,070[br].[br][br]71[br]00:03:41,070 --> 00:03:43,150[br]y က 6 မွတ္ေလ်ာ့သြားတယ္[br][br]72[br]00:03:43,150 --> 00:03:45,180[br]ကြ်န္ေတာ္တိုု႔ ဒီအမွတ္ကေန ဒီအမွတ္ကိုုသြားရင္[br][br]73[br]00:03:45,180 --> 00:03:46,060[br]x ကဘာၿဖစ္မလဲ?

9:59:59.000,9:59:59.000
74[br]00:03:46,060 --> 00:03:49,560[br]-3 ကေန 6 ကိုုသြားတယ္ဆိုုေတာ့ x က 9 မွတ္တိုုးလာသင့္တာေပါ့

9:59:59.000,9:59:59.000
75[br]00:03:49,560 --> 00:03:54,870[br]အဲဒါကိုုတြက္မယ္ဆိုုရင္ -3 ကိုုယူၿပီး 6 ထဲကႏွုဳတ္ရင္[br][br]76[br]00:03:54,870 --> 00:03:58,550[br]6 ကိုု 3 ေပါင္းတာနဲ႔ တုူတူပဲေပါ့ 9 ရပါတယ္

9:59:59.000,9:59:59.000
77[br]00:03:58,550 --> 00:04:00,120[br]ေနာက္ၿပီး -6 ကိုု 9 နဲ႔စားရင္ ဘယ္ေလာက္ရလဲ

9:59:59.000,9:59:59.000
78[br]00:04:00,120 --> 00:04:04,060[br]အဲဒါကိုုရွင္းလိုုက္ရင္ -2/3 က်န္ပါတယ္

9:59:59.000,9:59:59.000
79[br]00:04:04,060 --> 00:04:06,950[br]ပိုုင္းေဝေရာ ပိုုင္းေၿခကိုုပါ 3 နဲ႔စားလိုုက္တာပါ

9:59:59.000,9:59:59.000
80[br]00:04:06,950 --> 00:04:09,860[br]ဒါဆိုု ဒါဟာကြ်န္ေတာ္တိုု႔ရဲ႕ slope ျဖစ္တဲ့ -2/3 ပါ

9:59:59.000,9:59:59.000
81[br]00:04:09,860 --> 00:04:12,800[br]အခုုဆိုု ကြ်န္ေတာ္တိုု႔က point slope form ကိုုအသံုုးၿပဳလိုု႔ရပါၿပီ[br][br]82[br]00:04:12,800 --> 00:04:15,760[br]ကြ်န္ေတာ္တိုု႔မွာ အမွတ္တစ္မွတ္ရွိပါတယ္။ ဘယ္အမွတ္မဆိုု သံုုးလိုု႔ရပါတယ္။

9:59:59.000,9:59:59.000
83[br]00:04:15,760 --> 00:04:18,149[br]ကြ်န္ေတာ္ကေတာ့ (-3,6) ကိုုပဲသံုုးလိုုက္ပါမယ္

9:59:59.000,9:59:59.000
84[br]00:04:18,149 --> 00:04:19,269[br]ကြ်န္ေတာ္တိုု႔မွာ slope လည္းရွိပါတယ္

9:59:59.000,9:59:59.000
85[br]00:04:19,269 --> 00:04:20,910[br]point slope form နဲ႔ေရးၾကည့္ရေအာင္

9:59:59.000,9:59:59.000
86[br]00:04:20,910 --> 00:04:29,050[br].

9:59:59.000,9:59:59.000
87[br]00:04:29,050 --> 00:04:32,910[br]y ထဲကႏွဳတ္ဖိုု႔ ကြ်န္ေတာ္တိုု႔

9:59:59.000,9:59:59.000
88[br]00:04:32,910 --> 00:04:35,030[br]ဒီအမွတ္၂ခုုထဲက ၾကိဳက္တဲ့တစ္ခုုယုူလိုု႔ရပါတယ္. ကြ်န္ေတာ္ကဒီတစ္ခုုယူပါမယ္။

9:59:59.000,9:59:59.000
89[br]00:04:35,030 --> 00:04:42,990[br]y minus ေဟာဒီက y ရဲ႕ တန္ဖိုုး, ဒါဆိုု y-6=

9:59:59.000,9:59:59.000
90[br]00:04:42,990 --> 00:04:51,480[br]slope တန္ဖိုုးျဖစ္တဲ့ (-2/3) အေၿမွာက္ x minus [br][br]91[br]00:04:51,480 --> 00:04:51,930[br]x-coordinate.[br][br]92[br]00:04:51,930 --> 00:04:55,490[br]x-coordinate က -3[br][br]93[br]00:04:55,490 --> 00:05:00,370[br]ဆိုုေတာ့ x minus (-3) ဆိုုရင္ရပါၿပီ။

9:59:59.000,9:59:59.000
94[br]00:05:00,370 --> 00:05:01,570[br]ဒါကိုုနဲနဲထပ္ရွင္းလိုု႔ရပါေသးတယ္

9:59:59.000,9:59:59.000
95[br]00:05:01,570 --> 00:05:08,650[br]y-6 = -2/3 အေၿမွာက္ x.

9:59:59.000,9:59:59.000
96[br]00:05:08,650 --> 00:05:12,610[br]x minus -3 က x +3 နဲ႔တူတူပါပဲ

9:59:59.000,9:59:59.000
97[br]00:05:12,610 --> 00:05:15,760[br]ဒါကေတာ့ ကြ်န္ေတာ္တိုု႔ရဲ႕ point slope form ပါ။

9:59:59.000,9:59:59.000
98[br]00:05:15,760 --> 00:05:19,270[br]အခုု ကြ်န္ေတာ္တိုု႔က ဒီဟာ ကိုုပဲ [br][br]99[br]00:05:19,270 --> 00:05:23,500[br]slope intercept form ကိုု ေျပာင္းလဲလိုုက္လိုု႔ရပါတယ္

9:59:59.000,9:59:59.000
100[br]00:05:23,500 --> 00:05:24,130[br]ကဲ လုုပ္ၾကည့္ရေအာင္

9:59:59.000,9:59:59.000
101[br]00:05:24,130 --> 00:05:27,560[br]slope intercept ကိုု လိေမာ္ေရာင္နဲ႔ လုုပ္ၾကမယ္ေနာ္

9:59:59.000,9:59:59.000
102[br]00:05:27,560 --> 00:05:30,960[br]ကြ်န္ေတာ္တိုု႔မွာ slope intercept ရွိပါတယ္

9:59:59.000,9:59:59.000
103[br]00:05:30,960 --> 00:05:35,200[br].

9:59:59.000,9:59:59.000
104[br]00:05:35,200 --> 00:05:37,040[br]ဒီဟာကိုုဘယ္လိုုရွင္းၾကမလဲဆိုုေတာ့

9:59:59.000,9:59:59.000
105[br]00:05:37,040 --> 00:05:41,510[br]ကြ်န္ေတာ္တိုု႔က -2/3 ကိုုေၿမွာက္လိုုက္လိုု႔ရပါတယ္။

9:59:59.000,9:59:59.000
106[br]00:05:41,510 --> 00:05:44,150[br]ကြ်န္ေတာ္က -2/3 ကိုု အထဲဝင္ေျမွာက္မွာပါ။ y-6=

9:59:59.000,9:59:59.000
107[br]00:05:44,150 --> 00:05:48,950[br]-2/3 အေျမွာက္ x က -2/3x ပါ

9:59:59.000,9:59:59.000
108[br]00:05:48,950 --> 00:05:53,890[br]-2/3 အေျမွာက္ 3 က -2 ရပါတယ္

9:59:59.000,9:59:59.000
109[br]00:05:53,890 --> 00:05:56,150[br]အခုု slope intercept form အေနနဲ႔ရဖိုု႔

9:59:59.000,9:59:59.000
110[br]00:05:56,150 --> 00:05:59,270[br]6 ကိုု ၂ဖက္စလုုံးမွာ ေပါင္းလုုိက္မယ္ဆိုု ဘယ္ဖက္အျခမ္းက 6 ကိုု

9:59:59.000,9:59:59.000
111[br]00:05:59,270 --> 00:06:02,380[br]ဖယ္ျပီးသားျဖစ္သြားမွာပါ. equation ရဲ႕ ၂ဖက္စလုုံးကိုု

9:59:59.000,9:59:59.000
112[br]00:06:02,380 --> 00:06:04,400[br]6 ေပါင္းရေအာင္

9:59:59.000,9:59:59.000
113[br]00:06:04,400 --> 00:06:06,010[br]ဘယ္ဘက္အျခမ္းမွာ y တစ္ခုုထဲက်န္ၿပီး

9:59:59.000,9:59:59.000
114[br]00:06:06,010 --> 00:06:08,090[br]ဒီေကာင္ေတြကေတာ့ ေၾကသြားမွာပါ

9:59:59.000,9:59:59.000
115[br]00:06:08,090 --> 00:06:12,830[br]အခုုဆိုု y= -2/3x

9:59:59.000,9:59:59.000
116[br]00:06:12,830 --> 00:06:15,810[br]-2 အေပါင္း 6 က +4 ရပါတယ္

9:59:59.000,9:59:59.000
117[br]00:06:15,810 --> 00:06:19,890[br]ဒါကကြ်န္ေတာ္တိုု႔ရဲ႕ slope intercept form ပါ

9:59:59.000,9:59:59.000
118[br]00:06:19,890 --> 00:06:22,590[br]mx အေပါင္း b, ဒါက ကြ်န္ေတာ္တိုု႔ y ျဖတ္မွတ္ပါ။

9:59:59.000,9:59:59.000
119[br]00:06:22,590 --> 00:06:24,480[br]အခုု ကြ်န္ေတာ္တိုု႔ standard form

9:59:59.000,9:59:59.000
120[br]00:06:24,480 --> 00:06:25,730[br]ရွာဖိုု႔ပဲက်န္ပါေတာ့တယ္

9:59:59.000,9:59:59.000
121[br]00:06:25,730 --> 00:06:30,440[br].

9:59:59.000,9:59:59.000
122[br]00:06:30,440 --> 00:06:32,840[br]ဒီတစ္ခါလည္း ရွိၿပီးသား equationကိုု ေျပာင္းလုုိက္ရံုုပါပဲ

9:59:59.000,9:59:59.000
123[br]00:06:32,840 --> 00:06:34,500[br]x ေရာ y ေရာ equation ရဲ႕

9:59:59.000,9:59:59.000
124[br]00:06:34,500 --> 00:06:36,130[br]ဘယ္ဘက္အျခမ္းကိုု ေျပာင္းေပးရမွာပါ

9:59:59.000,9:59:59.000
125[br]00:06:36,130 --> 00:06:40,140[br]ဒါဆိုု equation ရဲ႕ ၂ဖက္စလံုုးကိုု 2/3 နဲ႔ေပါင္းၾကရေအာင္

9:59:59.000,9:59:59.000
126[br]00:06:40,140 --> 00:06:42,140[br]ကြ်န္ေတာ္ ဒီက စပါမယ္

9:59:59.000,9:59:59.000
127[br]00:06:42,140 --> 00:06:45,950[br]ကြ်န္ေတာ္တိုု႔မွာ y = -2/3x +4 ရွိပါတယ္

9:59:59.000,9:59:59.000
128[br]00:06:45,950 --> 00:06:47,540[br]ဒါက slope intercept form ပါ

9:59:59.000,9:59:59.000
129[br]00:06:47,540 --> 00:06:53,790[br]2/3x ကိုု equation ရဲ႕ ၂ဖက္စလုုံးကိုု

9:59:59.000,9:59:59.000
130[br]00:06:53,790 --> 00:06:55,040[br]ေပါင္းၾကရေအာင္

9:59:59.000,9:59:59.000
131[br]00:06:55,040 --> 00:06:57,650[br].

9:59:59.000,9:59:59.000
132[br]00:06:57,650 --> 00:07:00,060[br]ကြ်န္ေတာ္ဒီလိုုလုုပ္တာဟာ equation ရဲ႕

9:59:59.000,9:59:59.000
133[br]00:07:00,060 --> 00:07:02,350[br]ညာဖက္မွာ ဒီ -2/3x ကိုု မရွိေအာင္လိုု႔ပါ

9:59:59.000,9:59:59.000
134[br]00:07:02,350 --> 00:07:05,010[br]equation ရဲ႕ ဘယ္ဖက္အၿခမ္းက

9:59:59.000,9:59:59.000
135[br]00:07:05,010 --> 00:07:07,730

9:59:59.000,9:59:59.000
136[br]00:07:07,730 --> 00:07:09,890[br]အခုုဘာၿဖစ္သြားျပီလဲ?

9:59:59.000,9:59:59.000
137[br]00:07:09,890 --> 00:07:16,390[br]2/3x အေပါင္း y, ဒါက ကြ်န္ေတာ့္ equation ရဲ႕

9:59:59.000,9:59:59.000
138[br]00:07:16,390 --> 00:07:20,220[br]ဘယ္ဖက္အျခမ္းပါ။ ဒီေကာင္ေတြက ေၾကသြားတယ္ဆိုုေတာ့

9:59:59.000,9:59:59.000
139[br]00:07:20,220 --> 00:07:22,650[br]4 ရပါတယ္

9:59:59.000,9:59:59.000
140[br]00:07:22,650 --> 00:07:25,580[br]ဒါဆိုု ဒီ standard form ကိုုရပါၿပီ

9:59:59.000,9:59:59.000
141[br]00:07:25,580 --> 00:07:26,790[br].

9:59:59.000,9:59:59.000
142[br]00:07:26,790 --> 00:07:30,030[br]အပိုုင္းကိန္းေဖ်ာက္ခ်င္တယ္ဆိုုရင္ေတာ့

9:59:59.000,9:59:59.000
143[br]00:07:30,030 --> 00:07:32,340[br]၂ဖက္စလုုံးကိုု 3 နဲ႔ေျမွာက္လိုု႔ရပါတယ္[br][br]144[br]00:07:32,340 --> 00:07:33,860[br].[br][br]145[br]00:07:33,860 --> 00:07:36,400[br]အဲ့လိုုလုုပ္ရင္ ဘာရမလဲ?

9:59:59.000,9:59:59.000
146[br]00:07:36,400 --> 00:07:40,220[br]2/3xကိုု 3နဲ႔ေျမွာက္ရင္ 2xရပါတယ္

9:59:59.000,9:59:59.000
147[br]00:07:40,220 --> 00:07:43,440[br]yကိုု 3နဲ႔ေျမွာက္ရင္ 3y ရပါတယ္

9:59:59.000,9:59:59.000
148[br]00:07:43,440 --> 00:07:45,700[br]4 အေျမွာက္ 3 က 12

9:59:59.000,9:59:59.000
149[br]00:07:45,700 --> 00:07:47,620[br]equation ၂ခုုကတူတူပါပဲ။ ၂ဖက္စလုုံးကိုု 3နဲ႔ေျမွာက္လိုုက္တာပါပဲ

9:59:59.000,9:59:59.000
150[br]00:07:47,620 --> 00:07:48,760[br][br]151[br]00:07:48,760 --> 00:07:50,190[br]ဘယ္ဖက္အျခမ္းကိုုေျမွာက္ရင္ ညာဖက္ကိုုလည္းေျမွာက္ရမယ္

9:59:59.000,9:59:59.000
152[br]00:07:50,190 --> 00:07:52,680[br].[br][br]153[br]00:07:52,680 --> 00:07:56,160[br]ဒါဆိုု standard form ရပါၿပီ