Functions often come defined as quotients, so. Let's just write that word down quotients so functions come defined. This quotients by, which we mean we have one function cause X, let's say divided by another function, cause X divided by X squared. What we do is we identify that as one function you divided by another function V. This then gives us yet another result. Another formula that we need to be able to remember. This one goes VU by TX. Minus you DV by DX all over V squared. Now it looks very complicated formula, but it's not really you just have to remember the minus side and I must say the way that I always remember it is if anything is going to go wrong with anything, it's going to be what's in the denominator. So when we do the derivative. We're going to have to have a minus sign. Let's have a look how this formula is going to work with this particular example. So let's have a look at this example. Y equals cause X over X squared, and we've identified this as being you over VU divided by V. So you is cause X. And the is X squared. We can write down their derivatives. Do you buy DX is minus sign X and DV by DX is 2 X? Quote the formula. DY by the X is. VU by DX minus UDVX all over the squared. Again, we're quoting the formula every time, because that way we get to remember it. We get to know it. Equals and now we can plug in the various bits that we've got. So V will be X squared. Times by DU by DX. So that's times by minus sign X. Minus because of the minus that there is in the formula and then we want you which is convex. Times by and we want DV by DX, which is 2 X. And then all over. The squared, and in this case V is X squared, so that's X squared all squared. Now again, this doesn't look very nice. It needs tidying up. We need to gather things together, so if I turn over the page, write this expression again at the top of the page. Writing that down again DYX is equal 2. X squared times minus sign X minus cause X. Times 2X all over X squared squared. OK, we need to simplify this look again for the common factor, and there's an X there in the X. Squared is a minus sign there a minus sign there and an X there. So from each term we can take out the minus sign and the X and on top that will leave. As with X Sign X. Plus most be a plus now because we've taken the minus sign out plus and here we've got 2. Kohl's X left. All over and now X squared all squared is X to the power 4. Having done that, we can see that there's now a factor of X common to both the top, the numerator and to the bottom the denominator. So we can divide the top and the bottom by X in order to simplify it, so the minus sign stays minus X. Sign X +2 cause X. All over X cubed and we can leave it like that. Simplified in that way. And that's useful, because now if we wanted to, we could go on and put it equal to 0 and we could sort out Maxima and minima and all that kind of thing. So it's always helpful to try and rearrange these expressions, particularly to get the top in a simplified form. Notice though, that we didn't cancel any of these axes in here. That part of the sine X. That part of the variables. You can't just go canceling them out. You can only cancel those out, which are common factors. Let's take a second example. This time. Let's take it one that's just got polynomial functions of accent, so we've got X squared +6 all over 2X. Minus 7, just polynomials now causes no signs etc, so this is a U over VA quotient again. Let's line this one up. You equals X squared, and so do you find the X will be 2X. The is 2X minus Seven, and so DV by DX is just two. Quote the formula Y equals V. You buy TX. Minus UDVX All over the squared. Now we quoted the formula. We now in a position to be able to substitute in the various pieces that we need so. Why by the X? Is equal 2. Now this is VDU by DX so that's 2X minus 7. Times by du by DX, which is 2 X. Minus. U which was X squared plus six times divided by DX, which was just two and this is all over the square so it's all over 2X minus 7 squared. Now again we need to think about this one. We need to simplify it. We need to get together the various terms and if we look, there's a common factor of two there and there so we can take that two out as a common factor and put it at the front. So we have two. Then when we multiply out with X times by two X, that gives us two X squared. X times by 7 gives us minus Seven X. Then we have minus this, so it's minus X squared minus six. Close the bracket. All over 2X minus Seven or square. Keep the two outside and let's simplify the terms inside. X squared Minus Seven X minus 6. All over 2X minus Seven or squared and that's now informed. We need to go on and do something else with it we can do. 3rd example that I'd like to do with you is one where we're going to use this result in order to help us establish something new. Now we're going to use this result to help us prove another result. So let's begin with Y equals 10 X. It's a standard function, so we want to be able to differentiate it in a standard way. We want to result. We can use and just keep on using it. So we've got to begin with the definition of Tan X Tan X is defined as being sign X over cause X, and of course that's now a quotient, isn't it? That's now you over V, because we've been. Able to identify the you over V. Then we can have U equals sign X and so do you buy the X will be cause X. We've got the equals cause X and so DV by the X will be minus. Sign X. Lots of causes and signs about, so we need to be very, very careful when we do the substitution. Close quote the formula DY by the X is VU by DX minus UDVX all over V squared. And we're going to make this substitution, so let's just work our way through that. The why by DX. Will be. Now it's VDU by the X so V was cause X. You was sign X, so its derivative is caused X. Minus from the formula. You divvy by DX. Now you was sign X. And DV by the X will V was cause exo DV by the X is minus sign X. Oh, over. The squared and V was cause X, so that's all over Cos squared X. We now need to simplify the top so we have cause X times by cause X, so that's cost squared X. We have a minus and minus sign, so that's going to give us a plus and we've sign X times by cynex, so we've signed squared X. All over cause squared X. Equals. Now this is a standard result, well known result cost squared plus sign squared is always equal to 1 cost squared X plus sign squared. X is one, so that's one over cause squared X and of course we have another way of writing one over cost squared. One over kozaks we usually write as being sack X, so one over cost squared X. We would write as SEK squared X. And so that's how we differentiate tab. And now we've got a standard result that the derivative of tangent is sex squared X. We can simply quote that and use it anytime that we want to. We take one more example of using this in the same sort of way. Let's take the function Y equals second X. Now we know the definition of Psychics. It's one over cause X. One of the ways of doing this now is to realize that this is a quotient. It's AU over V. Having identified those, we can say you equals 1, and so do you buy. The X will be equal to. Now one is just a constant, so remember a constant is about rate of derivative is about rate of change. So if we differentiate something which is constant rate of change must be 0. The is cause X and so DV by the X will be minus sign X. And again, our formula is DY by X is equal to. The DU by The X. Minus UDV by the X all over V squared. So we're going to make the substitution now. This is going to change things slightly if do you buy the Axis zero when we start multiplying by zero sum of things may happen so. DY by DX is VDU by DX now remember V was cause X times do you buy DX that was zero because you was one. Minus U, that's one. Times by DV by DX now remember V was cause X and so its derivative is minus sign X and then all over V squared, which is cost squared X. So what we've got cause X times by zero is zero. Anything times by zero is 0 minus. Minus gives us a plus, and so we've got sine X over cause squared X. Looks looks like it might be something else, and remember that we've just seen that tan is sign over cars, so I can write this as one over cause X times sign X over cause X here I've got one over cause is sex X. Times sign over cause which is 10 X so I end up with the result that the derivative of sex is sex tinix. So. Anytime we want to use the derivative of sex, we can do so. All we do is we just write it straight down sex tanks and that's it. We don't have to work it all out again. And that's the end of Quotients.