1 00:00:00,000 --> 00:00:00,550 2 00:00:00,550 --> 00:00:03,240 I think it's pretty common knowledge how to find the area 3 00:00:03,240 --> 00:00:06,030 of the triangle if we know the length of its base 4 00:00:06,030 --> 00:00:07,250 and its height. 5 00:00:07,250 --> 00:00:10,540 So, for example, if that's my triangle, and this length right 6 00:00:10,540 --> 00:00:14,910 here-- this base-- is of length b and the height right here is 7 00:00:14,910 --> 00:00:19,080 of length h, it's pretty common knowledge that the area of this 8 00:00:19,080 --> 00:00:23,170 triangle is going to be equal to 1/2 times the base 9 00:00:23,170 --> 00:00:24,440 times the height. 10 00:00:24,440 --> 00:00:30,240 So, for example, if the base was equal to 5 and the height 11 00:00:30,240 --> 00:00:37,180 was equal to 6, then our area would be 1/2 times 5 times 6, 12 00:00:37,180 --> 00:00:41,770 which is 1/2 times 30-- which is equal to 15. 13 00:00:41,770 --> 00:00:45,120 Now what is less well-known is how to figure out the area of a 14 00:00:45,120 --> 00:00:48,250 triangle when you're only given the sides of the triangle. 15 00:00:48,250 --> 00:00:49,740 When you aren't given the height. 16 00:00:49,740 --> 00:00:53,470 So, for example, how do you figure out a triangle 17 00:00:53,470 --> 00:00:55,570 where I just give you the lengths of the sides. 18 00:00:55,570 --> 00:01:00,530 Let's say that's side a, side b, and side c. a, b, and c are 19 00:01:00,530 --> 00:01:01,640 the lengths of these sides. 20 00:01:01,640 --> 00:01:03,360 How do you figure that out? 21 00:01:03,360 --> 00:01:05,270 And to do that we're going to apply something 22 00:01:05,270 --> 00:01:06,430 called Heron's Formula. 23 00:01:06,430 --> 00:01:12,210 24 00:01:12,210 --> 00:01:13,790 And I'm not going to prove it in this video. 25 00:01:13,790 --> 00:01:15,200 I'm going to prove it in a future video. 26 00:01:15,200 --> 00:01:17,400 And really to prove it you already probably have 27 00:01:17,400 --> 00:01:18,720 the tools necessary. 28 00:01:18,720 --> 00:01:20,480 It's really just the Pythagorean theorem and 29 00:01:20,480 --> 00:01:22,220 a lot of hairy algebra. 30 00:01:22,220 --> 00:01:24,230 But I'm just going to show you the formula now and how to 31 00:01:24,230 --> 00:01:26,760 apply it, and then you'll hopefully appreciate that it's 32 00:01:26,760 --> 00:01:28,590 pretty simple and pretty easy to remember. 33 00:01:28,590 --> 00:01:31,660 And it can be a nice trick to impress people with. 34 00:01:31,660 --> 00:01:36,320 So Heron's Formula says first figure out this third variable 35 00:01:36,320 --> 00:01:38,640 S, which is essentially the perimeter of this 36 00:01:38,640 --> 00:01:40,660 triangle divided by 2. 37 00:01:40,660 --> 00:01:45,810 a plus b plus c, divided by 2. 38 00:01:45,810 --> 00:01:49,480 Then once you figure out S, the area of your triangle-- of this 39 00:01:49,480 --> 00:01:55,840 triangle right there-- is going to be equal to the square root 40 00:01:55,840 --> 00:01:59,710 of S-- this variable S right here that you just calculated-- 41 00:01:59,710 --> 00:02:10,540 times S minus a, times S minus b, times S minus c. 42 00:02:10,540 --> 00:02:12,480 That's Heron's Formula right there. 43 00:02:12,480 --> 00:02:13,830 This combination. 44 00:02:13,830 --> 00:02:16,130 Let me square it off for you. 45 00:02:16,130 --> 00:02:18,700 So that right there is Heron's Formula. 46 00:02:18,700 --> 00:02:21,610 And if that looks a little bit daunting-- it is a little bit 47 00:02:21,610 --> 00:02:24,290 more daunting, clearly, than just 1/2 times base 48 00:02:24,290 --> 00:02:25,290 times height. 49 00:02:25,290 --> 00:02:28,040 Let's do it with an actual example or two, and actually 50 00:02:28,040 --> 00:02:31,350 see this is actually not so bad. 51 00:02:31,350 --> 00:02:33,320 So let's say I have a triangle. 52 00:02:33,320 --> 00:02:35,300 I'll leave the formula up there. 53 00:02:35,300 --> 00:02:37,460 So let's say I have a triangle that has sides 54 00:02:37,460 --> 00:02:44,920 of length 9, 11, and 16. 55 00:02:44,920 --> 00:02:47,040 So let's apply Heron's Formula. 56 00:02:47,040 --> 00:02:51,190 S in this situation is going to be the perimeter divided by 2. 57 00:02:51,190 --> 00:02:56,630 So 9 plus 11 plus 16, divided by 2. 58 00:02:56,630 --> 00:03:00,430 Which is equal to 9 plus 11-- is 20-- plus 16 is 59 00:03:00,430 --> 00:03:04,660 36, divided by 2 is 18. 60 00:03:04,660 --> 00:03:09,430 And then the area by Heron's Formula is going to be equal to 61 00:03:09,430 --> 00:03:19,380 the square root of S-- 18-- times S minus a-- S minus 9. 62 00:03:19,380 --> 00:03:27,790 18 minus 9, times 18 minus 11, times 18 minus 16. 63 00:03:27,790 --> 00:03:31,490 64 00:03:31,490 --> 00:03:38,200 And then this is equal to the square root of 18 65 00:03:38,200 --> 00:03:44,730 times 9 times 7 times 2. 66 00:03:44,730 --> 00:03:47,340 Which is equal to-- let's see, 2 times 18 is 36. 67 00:03:47,340 --> 00:03:48,900 So I'll just rearrange it a bit. 68 00:03:48,900 --> 00:03:56,700 This is equal to the square root of 36 times 9 times 7, 69 00:03:56,700 --> 00:04:05,540 which is equal to the square root of 36 times the square 70 00:04:05,540 --> 00:04:09,330 root of 9 times the square root of 7. 71 00:04:09,330 --> 00:04:14,130 The square root of 36 is just 6. 72 00:04:14,130 --> 00:04:16,040 This is just 3. 73 00:04:16,040 --> 00:04:17,750 And we don't deal with the negative square roots, 74 00:04:17,750 --> 00:04:19,920 because you can't have negative side lengths. 75 00:04:19,920 --> 00:04:23,460 And so this is going to be equal to 18 times 76 00:04:23,460 --> 00:04:26,120 the square root of 7. 77 00:04:26,120 --> 00:04:28,060 So just like that, you saw it, it only took a couple of 78 00:04:28,060 --> 00:04:30,760 minutes to apply Heron's Formula, or even less than 79 00:04:30,760 --> 00:04:33,420 that, to figure out that the area of this triangle 80 00:04:33,420 --> 00:04:38,710 right here is equal to 18 square root of seven. 81 00:04:38,710 --> 00:04:42,040 Anyway, hopefully you found that pretty neat. 82 00:04:42,040 --> 00:04:42,331